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Carbon tetrachloride (CCl\(_4\)) and benzene (C \(_{6} \mathrm{H}_{6}\) ) form ideal solutions. Consider an equimolar solution of \(\mathrm{CCl}_{4}\) and \(\mathrm{C}_{6} \mathrm{H}_{6}\) at \(25^{\circ} \mathrm{C} .\) The vapor above the solution is collected and condensed. Using the following data, determine the composition in mole fraction of the condensed vapor.

Short Answer

Expert verified
The composition of the condensed vapor is: - Mole fraction of Benzene: \(y_{C_{6}H_{6}} = 0.4536\) - Mole fraction of Carbon Tetrachloride: \(y_{CCl_{4}} = 0.5464\)

Step by step solution

01

Write down the given information and variables

Temperature: \(25^{\circ} C\) Benzene: \(C_{6}H_{6}\) Carbon Tetrachloride: \(CCl_{4}\) \[x_{C_{6}H_{6}} = x_{CCl_4} = 0.5\] Vapor Pressures: - Pure Benzene: \(P_{C_{6}H_{6}}^{sat}= 12.7\ kPa\) - Pure Carbon Tetrachloride: \(P_{CCl_{4}}^{sat}= 15.3\ kPa\)
02

Apply Raoult's Law to both components

We'll use Raoult's Law for each component to find the partial pressures. Raoult's Law for Benzene: \(P_{C_{6}H_{6}} = x_{C_{6}H_{6}}P_{C_{6}H_{6}}^{sat}\) Raoult's Law for Carbon Tetrachloride: \(P_{CCl_{4}} = x_{CCl_4}P_{CCl_{4}}^{sat}\)
03

Calculate partial pressures for both components

For Benzene: \(P_{C_{6}H_{6}} = 0.5 \times 12.7\ kPa = 6.35\ kPa\) For Carbon Tetrachloride: \(P_{CCl_{4}} = 0.5 \times 15.3\ kPa = 7.65\ kPa\)
04

Calculate total pressure of the mixture

The total pressure of the mixture can be calculated by adding the partial pressures. \(P_{total} = P_{C_{6}H_{6}} + P_{CCl_{4}}\) \(P_{total} = 6.35\ kPa + 7.65\ kPa = 14\ kPa\)
05

Calculate the mole fractions of Benzene and Carbon Tetrachloride in the vapor

Mole fraction of Benzene in the vapor: \(y_{C_{6}H_{6}} = \frac{P_{C_{6}H_{6}}}{P_{total}} = \frac{6.35\ kPa}{14\ kPa} = 0.4536\) Mole fraction of Carbon Tetrachloride in the vapor: \(y_{CCl_{4}} = \frac{P_{CCl_{4}}}{P_{total}} = \frac{7.65\ kPa}{14\ kPa} = 0.5464\)
06

Express the results

The composition of the condensed vapor: - Mole fraction of Benzene: \(y_{C_{6}H_{6}} = 0.4536\) - Mole fraction of Carbon Tetrachloride: \(y_{CCl_{4}} = 0.5464\)

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Raoult's Law
This law plays a crucial role in understanding how mixtures behave. Developed by Francois-Marie Raoult, it states that the partial vapor pressure of each component in an ideal solution is equal to the vapor pressure of the pure component multiplied by its mole fraction in the solution.

This means that for a component A in a solution, its partial pressure (\(P_A\)) is given by \(P_A = x_A P_A^{\text{sat}}\), where \(x_A\) is the mole fraction of A and \(P_A^{\text{sat}}\) is its vapor pressure when pure. Raoult's Law assumes ideal behavior, where interactions between molecules are similar whether they’re in a solution or in pure form.
  • Useful for dilute solutions
  • Helps in predicting how solvent and solute interact
  • Key for determining phase equilibrium in mixtures
Vapor Pressure
Vapor pressure is the pressure exerted by a vapor in equilibrium with its liquid or solid form in a closed system. Each pure substance has a specific vapor pressure at any given temperature. For example, benzene and carbon tetrachloride have different vapor pressures at 25°C, reflecting their volatility differences.

In a mixture, the total vapor pressure comprises the sum of the partial pressures of the components in the vapor phase. This total pressure is crucial for understanding boiling points and the behavior of solvents. More volatile substances have higher vapor pressures, tending to evaporate more readily.
  • Dependent on temperature
  • Important in distillation processes
  • Varies between substances
Mole Fraction
Mole fraction is a way of expressing the concentration of a component in a mixture. It is calculated by dividing the number of moles of a substance by the total number of moles in the solution. Unlike other concentration measures like molarity, mole fraction is dimensionless and always adds up to 1 for all components in a solution.

In the context of Raoult's Law, the mole fraction of a component directly influences its vapor pressure contribution in a mixture. Mole fraction provides a simple way to express quantitative relationships between different substances in a chemical equilibrium.
  • Dimensionless measure of concentration
  • Used in determining vapor pressures and other colligative properties
  • Sum of all mole fractions in a solution is always 1
Ideal Solutions
An ideal solution is one where the enthalpy of mixing is zero, implying that intermolecular forces between different components are equal to those within the same component. Under these conditions, solutions often obey Raoult's Law very accurately.

Ideal behavior is a simpler model of real-world interactions and provides a baseline for understanding deviations. In these solutions, we assume no volume change upon mixing and similar molecular interactions across components. Ideal solutions serve as the conceptual groundwork for understanding how real mixtures may deviate under similar conditions.
  • Follows Raoult's Law perfectly
  • No energy change upon mixing
  • Useful as a model for more complex systems

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Most popular questions from this chapter

Consider the reaction $$\mathrm{Fe}_{2} \mathrm{O}_{3}(s)+3 \mathrm{H}_{2}(g) \longrightarrow 2 \mathrm{Fe}(s)+3 \mathrm{H}_{2} \mathrm{O}(g)$$ a. Use \(\Delta G_{\mathrm{f}}^{\circ}\) values in Appendix 4 to calculate \(\Delta G^{\circ}\) for this reaction. b. Is this reaction spontaneous under standard conditions at \(298 \mathrm{K} ?\) c. The value of \(\Delta H^{\circ}\) for this reaction is \(100 .\) kJ. At what temperatures is this reaction spontaneous at standard conditions? Assume that \(\Delta H^{\circ}\) and \(\Delta S^{\circ}\) do not depend on temperature.

Calculate \(\Delta S_{\text {sur }}\) for the following reactions at \(25^{\circ} \mathrm{C}\) and 1 atm. $$\text { a. } \mathrm{C}_{3} \mathrm{H}_{8}(g)+5 \mathrm{O}_{2}(g) \longrightarrow 3 \mathrm{CO}_{2}(g)+4 \mathrm{H}_{2} \mathrm{O}(l)$$$$\begin{aligned} &\Delta H^{\circ}=-2221 \mathrm{kJ}\\\ &\text { b. } 2 \mathrm{NO}_{2}(g) \longrightarrow 2 \mathrm{NO}(g)+\mathrm{O}_{2}(g) \quad \Delta H^{\circ}=112 \mathrm{kJ} \end{aligned}$$

Sodium chloride is added to water (at \(25^{\circ} \mathrm{C}\) ) until it is saturated. Calculate the \(\mathrm{Cl}^{-}\) concentration in such a solution.

Some nonelectrolyte solute (molar mass \(=142 \mathrm{g} / \mathrm{mol}\) ) was dissolved in \(150 . \mathrm{mL}\) of a solvent (density \(=0.879 \mathrm{g} / \mathrm{cm}^{3}\) ). The elevated boiling point of the solution was \(355.4 \mathrm{K} .\) What mass of solute was dissolved in the solvent? For the solvent, the enthalpy of vaporization is \(33.90 \mathrm{kJ} / \mathrm{mol},\) the entropy of vaporization is \(95.95 \mathrm{J} / \mathrm{K} \cdot \mathrm{mol},\) and the boiling-point elevation constant is \(2.5 \mathrm{K} \cdot \mathrm{kg} / \mathrm{mol}.\)

It is quite common for a solid to change from one structure to another at a temperature below its melting point. For example, sulfur undergoes a phase change from the rhombic crystal structure to the monoclinic crystal form at temperatures above \(95^{\circ} \mathrm{C}.\) a. Predict the signs of \(\Delta H\) and \(\Delta S\) for the process \(S_{\text {rhombic }}(s) \longrightarrow S_{\text {monoclinic }}(s).\) b. Which form of sulfur has the more ordered crystalline structure (has the smaller positional probability)?

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