Chapter 14: Problem 99
A sample of a certain monoprotic weak acid was dissolved in water and titrated with 0.125 \(M\) NaOH, requiring \(16.00 \mathrm{mL}\) to reach the equivalence point. During the titration, the pH after adding \(2.00 \mathrm{mL}\) NaOH was \(6.912 .\) Calculate \(K_{\mathrm{a}}\) for the weak acid.
Short Answer
Expert verified
The Ka value for the weak acid is approximately \(1.74 \times 10^{-9}\).
Step by step solution
01
Determine the moles of OH- in the added NaOH
To calculate the moles of OH- in the added NaOH, we can use the given concentration and volume:
Moles of OH- = \(concentration \times volume\)
Moles of OH- = \(0.125 \frac{mol}{L} \times 0.002 L\)
Moles of OH- = \(0.00025 mol\)
02
Calculate the moles of the weak acid present in the sample
Since we know that it required 16.00 mL of 0.125 M NaOH to reach the equivalence point, we can determine the moles of the weak acid in the sample:
Moles of weak acid = moles of OH- (at equivalence point)
Moles of weak acid = \(0.125 \frac{mol}{L} \times 0.016 L\)
Moles of weak acid = \(0.002 mol\)
03
Calculate the initial concentrations of the weak acid and its conjugate base
After adding 2.00 mL of 0.125 M NaOH, the moles of the weak acid and its conjugate base will be:
Moles of weak acid remaining = \(0.002 mol - 0.00025 mol = 0.00175 mol\)
Moles of conjugate base formed = \(0.00025 mol\)
Now, we can calculate the concentrations of the weak acid and its conjugate base:
Initial concentration of the weak acid = \(\frac{0.00175 mol}{0.018 L} = 0.09722\frac{mol}{L}\)
Initial concentration of the conjugate base = \(\frac{0.00025 mol}{0.018 L} = 0.01389\frac{mol}{L}\)
04
Use the provided pH and an equilibrium expression to determine the Ka value
From the given pH, we can determine the hydrogen ion concentration:
pH = 6.912
\[H^+ = 10^{-pH} = 10^{-6.912} = 1.209 \times 10^{-7}\]
Now, we can use the Ka expression to calculate Ka value:
For a weak acid, HA, and its conjugate base, A-, the Ka expression is:
\[K_a = \frac{[H^+][A^-]}{[HA]}\]
Here, H+ is the hydrogen ion concentration, A- is the conjugate base concentration, and HA is the weak acid concentration. We can plug in the values:
\[K_a = \frac{(1.209 \times 10^{-7})(0.01389)}{0.09722}\]
\[K_a = 1.74 \times 10^{-9}\]
So, the Ka value for the weak acid is approximately \(1.74 \times 10^{-9}\).
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Weak Acid
A weak acid is an acid that only partially ionizes in water. This means it does not completely dissociate into its ions when dissolved. For example, if you dissolve 100 molecules of a weak acid in water, only a few of them will break apart and release hydrogen ions.
This is different from a strong acid that dissociates completely. Weak acids are essential in chemistry as they offer a buffer action and resist changes in pH. Typical weak acids include acetic acid, found in vinegar, and citric acid, present in citrus fruits.
This is different from a strong acid that dissociates completely. Weak acids are essential in chemistry as they offer a buffer action and resist changes in pH. Typical weak acids include acetic acid, found in vinegar, and citric acid, present in citrus fruits.
- Ionizes partially in solution
- Selectively forms two types of ions
- Has a measurable equilibrium with its ions
Equivalence Point
The equivalence point in a titration is a key concept. It is the point at which the amount of titrant added is just enough to completely neutralize the analyte solution.
In the case of an acid-base titration involving a weak acid and a strong base, the equivalence point marks the point when all the weak acid has reacted with the base to form water and a conjugate base.
For the given example, the equivalence point is reached with 16.00 mL of NaOH. At equivalence, the solution may not have a neutral pH due to the presence of the conjugate base in case of a weak acid:
In the case of an acid-base titration involving a weak acid and a strong base, the equivalence point marks the point when all the weak acid has reacted with the base to form water and a conjugate base.
For the given example, the equivalence point is reached with 16.00 mL of NaOH. At equivalence, the solution may not have a neutral pH due to the presence of the conjugate base in case of a weak acid:
- Complete reaction between acid and base
- Only product ions present
- Important for calculating unknown concentrations
pH Calculation
Calculating the pH of a solution is a fundamental part of acid-base chemistry. pH is a measure of the hydrogen ion concentration in a solution.
The scale generally ranges from 0 to 14, with lower numbers being more acidic and higher numbers more basic. To find the pH, you can use the formula: \[ pH = -\log[H^+] \]
In the given example, after adding 2.00 mL of NaOH, the pH was measured to be 6.912. From this pH value, we can determine the concentration of hydrogen ions \([H^+]\):
\[H^+ = 10^{-6.912} = 1.209 \times 10^{-7}\] Understanding pH calculations is important because it helps us monitor how acidity changes during reactions, particularly in titration experiments.
The scale generally ranges from 0 to 14, with lower numbers being more acidic and higher numbers more basic. To find the pH, you can use the formula: \[ pH = -\log[H^+] \]
In the given example, after adding 2.00 mL of NaOH, the pH was measured to be 6.912. From this pH value, we can determine the concentration of hydrogen ions \([H^+]\):
\[H^+ = 10^{-6.912} = 1.209 \times 10^{-7}\] Understanding pH calculations is important because it helps us monitor how acidity changes during reactions, particularly in titration experiments.
Acid Dissociation Constant (Ka)
The acid dissociation constant, represented as \(K_a\), is a crucial value in chemistry. It measures the strength of an acid in solution and describes its ability to donate protons.
This constant is specific for each acid and defined by the equilibrium concentrations of the reactants and products in the ionization of the acid.
For a weak acid \( HA \) that dissociates into \( H^+ \) and \( A^- \), the expression is:\[K_a = \frac{[H^+][A^-]}{[HA]} \]In the given example, the \(K_a\) value was calculated using the concentrations at the specific titration point:\[K_a = \frac{(1.209 \times 10^{-7})(0.01389)}{0.09722}\]This gives a \(K_a\) of approximately \(1.74 \times 10^{-9}\).
This constant is specific for each acid and defined by the equilibrium concentrations of the reactants and products in the ionization of the acid.
For a weak acid \( HA \) that dissociates into \( H^+ \) and \( A^- \), the expression is:\[K_a = \frac{[H^+][A^-]}{[HA]} \]In the given example, the \(K_a\) value was calculated using the concentrations at the specific titration point:\[K_a = \frac{(1.209 \times 10^{-7})(0.01389)}{0.09722}\]This gives a \(K_a\) of approximately \(1.74 \times 10^{-9}\).
- Indicates how strongly an acid conducts electricity in a solution
- Determines the degree of ionization for different acids
- Helps predict the direction of the equilibrium reaction