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Mixing together solutions of acetic acid and sodium hydroxide can make a buffered solution. Explain. How does the amount of each solution added change the effectiveness of the buffer?

Short Answer

Expert verified
Mixing acetic acid (a weak acid) and sodium hydroxide (a strong base) forms a buffered solution containing both the weak acid and its conjugate base, sodium acetate. Buffer effectiveness is determined by the Henderson-Hasselbalch equation: \( pH = pK_a + \log \frac{[A^-]}{[HA]} \), comparing the concentrations of these two components. The buffer's capacity to resist pH changes is higher when the base/acid concentrations ratio is close to 1 and when the overall concentrations are high. Changing the amounts of acetic acid and sodium hydroxide added to the solution will affect this ratio and, consequently, the buffer's effectiveness.

Step by step solution

01

Introduction to pH and Buffer

A buffer solution is a mixture of a weak acid and its conjugate base, or a weak base and its conjugate acid. It helps to resist changes in pH when small amounts of an acid or a base are added. In our case, mixing acetic acid (a weak acid) and sodium hydroxide (a strong base) will yield a buffered solution.
02

Formation of the Buffer

The reaction between acetic acid (CH3COOH) and sodium hydroxide (NaOH) can be represented as follows: \( CH_3COOH + NaOH \rightarrow CH_3COONa + H_2O \) Sodium acetate (CH3COONa) is the salt formed, and it represents the conjugate base of acetic acid, while water is another product. In a buffered solution, both the weak acid (acetic acid in this case) and its conjugate base (sodium acetate) will be present in appreciable amounts.
03

Henderson-Hasselbalch Equation

The effectiveness of a buffer is determined by its ability to resist changes in pH. This can be explained using the Henderson-Hasselbalch equation: \( pH = pK_a + \log \frac{[A^-]}{[HA]} \) where pH is the solution's pH, pKa is the acid dissociation constant of the weak acid, [A-] is the concentration of the conjugate base (here, the acetate ion from sodium acetate), and [HA] is the concentration of the weak acid (acetic acid in this case).
04

Change in Buffer Effectiveness

The effectiveness of the buffer depends on the ratio of the concentrations of the conjugate base and the weak acid, \(\frac{[A^-]}{[HA]}\). As we add different amounts of acetic acid and sodium hydroxide solutions, the concentrations of the acetate ion and acetic acid in the solution will change. Consequently, the buffer capacity, which reflects the solution's ability to resist changes in pH, will also change. A buffer solution will be more effective when the ratio of base/acid concentrations is close to 1, and when the overall concentrations of both components are high. Adding more of one component without the other may cause a decrease in the buffer's ability to resist pH changes, as it disturbs the equilibrium.

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Most popular questions from this chapter

What concentration of \(\mathrm{NH}_{4} \mathrm{Cl}\) is necessary to buffer a \(0.52-M\) \(\mathrm{NH}_{3}\) solution at \(\mathrm{pH}=9.00 ?\left(K_{\mathrm{b}} \text { for } \mathrm{NH}_{3}=1.8 \times 10^{-5} .\right)\)

You have a solution of the weak acid HA and add some of the salt NaA to it. What are the major species in the solution? What do you need to know to calculate the \(\mathrm{pH}\) of the solution, and how would you use this information? How does the pH of the solution of just the HA compare with that of the final mixture? Explain.

Consider a buffer solution where [weak acid] \(>\) [conjugate base]. How is the pH of the solution related to the \(\mathrm{p} K_{\mathrm{a}}\) value of the weak acid? If [conjugate base] \(>\) [weak acid], how is pH related to \(\mathrm{p} K_{\mathrm{a}} ?\)

Consider the following acids and bases: Choose substances from the following list that would be the best choice to prepare a \(\mathrm{pH}=9.0\) buffer solution. a. \(\mathrm{HCO}_{2} \mathrm{H}\) b. HOBr c. \(\mathrm{KHCO}_{2}\) d. \(\mathrm{HONH}_{3} \mathrm{NO}_{3}\) \(\mathbf{e} .\left(\mathbf{C}_{2} \mathbf{H}_{5}\right)_{2} \mathrm{NH}\) f. \(\left(C_{2} H_{5}\right)_{2} N H_{2} C l\) g. \(\mathrm{HONH}_{2}\) h. NaOBr

A friend asks the following: "Consider a buffered solution made up of the weak acid HA and its salt NaA. If a strong base like NaOH is added, the HA reacts with the OH - to form A Thus the amount of acid (HA) is decreased, and the amount of base \(\left(\mathrm{A}^{-}\right)\) is increased. Analogously, adding HCl to the buffered solution forms more of the acid (HA) by reacting with the base \(\left(\mathrm{A}^{-}\right)\). Thus how can we claim that a buffered solution resists changes in the pH of the solution?" How would you explain buffering to this friend?

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