Warning: foreach() argument must be of type array|object, bool given in /var/www/html/web/app/themes/studypress-core-theme/template-parts/header/mobile-offcanvas.php on line 20

For the reaction A+BC, explain at least two ways in which the rate law could be zero order in chemical A.

Short Answer

Expert verified
The reaction $A+B \rightarrow C$ can be zero order in chemical A through two approaches: 1. In the presence of a catalyst or an enzyme which saturates with chemical A, the rate of reaction becomes independent of the concentration of A making the reaction zero order with respect to A. 2. If the rate-determining step (slowest step in the reaction mechanism) does not involve chemical A, the rate of the reaction will be independent of the concentration of A, resulting in a zero-order reaction with respect to A.

Step by step solution

01

Approach 1: Presence of a catalyst or enzyme which saturates with chemical A

One possible way to make the reaction zero order in chemical A is in the presence of a catalyst or an enzyme which can saturate with A. When the concentration of A increases, the catalyst or enzyme-related reaction site becomes saturated with A, so increasing the concentration of A does not affect the rate of the reaction anymore. The rate of reaction becomes independent of the concentration of A and hence the reaction becomes zero order with respect to chemical A.
02

Approach 2: The rate-determining step does not involve chemical A

Another way to make the reaction zero order in chemical A is if the rate-determining step, which is the slowest step in the reaction mechanism, does not involve chemical A. In a reaction mechanism that has multiple elementary steps, the overall rate law depends on the rate-determining step. If the slowest step in the mechanism does not involve chemical A, the rate of the reaction will be independent of the concentration of chemical A. In this scenario, the reaction order will be zero with respect to chemical A. These are two possible ways for the reaction between A and B to be zero order in chemical A. It is important to remember that the reaction order is determined by the reaction mechanism and cannot be predicted solely based on the balanced chemical equation.

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with Vaia!

Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Reaction Mechanism
In chemistry, the reaction mechanism is a step-by-step sequence of elementary reactions by which a chemical change occurs. Understanding the mechanism helps to identify how different reaction components interact and transform.
A chemical reaction isn't always a one-step process but can involve multiple stages, moving from reactants to products.
This sequence of steps is termed the mechanism of the reaction.
  • Each elementary step is a smaller reaction that includes just a few molecules.
  • Steps can vary in how quickly they occur; some are fast while others are slow.
  • The slowest step plays a crucial role in defining the rate of the entire reaction.

The entire sequence is necessary to fully understand how a given reaction occurs and to derive the reaction's overall rate law.
Catalyst
A catalyst is a substance that speeds up a chemical reaction without being consumed in the process. Catalysts function by lowering the activation energy of a reaction, which allows the reaction to proceed more quickly.
In some cases, a catalyst may become saturated with one of the reactants, affecting the rate order of a reaction.
  • They provide an alternative pathway with a lower activation energy.
  • They increase the reaction rate but do not alter the position of equilibrium.
  • They are specific to certain reactions, meaning a catalyst used for one may not work for another.

In zero order kinetics, the presence of a catalyst can mean that even when the concentration of one reactant increases, it does not affect the reaction rate if the catalyst is already saturated.
Rate-Determining Step
The rate-determining step is the slowest step in a reaction mechanism and it effectively sets the pace of the entire reaction. It's the bottleneck of the process, providing a cap on how fast the overall reaction can proceed.
  • If a particular step in a reaction is much slower relative to others, it will determine the reaction's rate.
  • The reaction order is significantly impacted by the rate-determining step.
  • In some reactions, none of the reactants might directly participate in this slow step.

Due to its slow nature, only components involved in this step influence the reaction’s rate law, making it crucial in determining the reaction's kinetics.
Enzyme Saturation
Enzymes are biological catalysts that significantly increase reaction rates. Enzyme saturation occurs when all enzyme molecules are occupied with substrate molecules, and adding more substrate won't further increase the rate of reaction.
  • At low substrate concentrations, increases in concentration lead to proportional increases in reaction rate.
  • Once saturation is reached, the enzymes can't work any faster, regardless of the substrate availability.
  • This is akin to a busy highway where adding more cars doesn't improve traffic flow once capacity is reached.

In terms of reaction kinetics, enzyme saturation often results in the reaction proceeding at a constant rate, typical of zero order reactions.

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

The decomposition of hydrogen iodide on finely divided gold at 150C is zero order with respect to HI. The rate defined below is constant at 1.20×104mol/Ls 2HI(g)AuH2(g)+I2(g) Rate =Δ[HI]Δt=k=1.20×104mol/Ls a. If the initial HI concentration was 0.250 mol/L, calculate the concentration of HI at 25 minutes after the start of the reaction. b. How long will it take for all of the 0.250M HI to decompose?

Table 112 illustrates how the average rate of a reaction decreases with time. Why does the average rate decrease with time? How does the instantaneous rate of a reaction depend on time? Why are initial rates used by convention?

The activation energy of a certain uncatalyzed biochemical reaction is 50.0 kJ/mol. In the presence of a catalyst at 37C the rate constant for the reaction increases by a factor of 2.50×103 as compared with the uncatalyzed reaction. Assuming the frequency factor A is the same for both the catalyzed and uncatalyzed reactions, calculate the activation energy for the catalyzed reaction.

Which of the following reactions would you expect to proceed at a faster rate at room temperature? Why? (Hint: Think about which reaction would have the lower activation energy.) 2Ce4+(aq)+Hg22+(aq)2Ce3+(aq)+2Hg2+(aq) H3O+(aq)+OH(aq)2H2O(l)

Consider the general reaction aA+bBcC and the following average rate data over some time period Δt: ΔAΔt=0.0080mol/Ls ΔBΔt=0.0120mol/Ls ΔCΔt=0.0160mol/Ls Determine a set of possible coefficients to balance this general reaction.

See all solutions

Recommended explanations on Chemistry Textbooks

View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.

Sign-up for free