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Enzymes are kinetically important for many of the complex reactions necessary for plant and animal life to exist. However, only a tiny amount of any particular enzyme is required for these complex reactions to occur. Explain.

Short Answer

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In conclusion, enzymes function as biological catalysts that enable complex chemical reactions in living organisms. They work in small quantities because of their high efficiency and turnover rates, as well as their precisely regulated mechanisms. Enzymes can process a vast number of substrate molecules per second and are thoroughly controlled within cells, ensuring that reactions progress effectively and cellular balance is maintained. These properties make enzymes crucial to the complex reactions necessary for plant and animal life to exist.

Step by step solution

01

Introduction to Enzymes

Enzymes are biological catalysts that speed up chemical reactions in living organisms. They are proteins with highly specific structures, which allow them to bind to particular molecules called substrates. When a substrate binds to an enzyme, the enzyme's structure is altered slightly, causing the substrate to be broken down or combined with other molecules at a much faster rate than would be possible without the enzyme present.
02

Function of Enzymes

Enzymes lower the activation energy required for a chemical reaction to occur. As a result, they dramatically increase the rate at which their substrates are processed and the overall reaction proceeds. Due to their highly specific structures, enzymes only catalyze specific reactions, ensuring that complex processes in cells can be tightly regulated and controlled.
03

Mechanism of Enzyme Action

Enzymes work through a process called the lock-and-key model. The enzyme has a unique three-dimensional structure, termed the active site, that accurately fits the specific structure of its substrate, much like a key fitting into a lock. Once the substrate binds to the enzyme's active site, the enzyme undergoes a conformational change, facilitating the reaction and ultimately generating the product needed. The enzyme then returns to its original shape, detaching from the products, and is ready to undergo another reaction cycle with a new substrate molecule.
04

High Efficiency and Turnover Rates

Enzymes are incredibly efficient catalysts. They can typically process hundreds to thousands of substrate molecules per second. This high turnover rate means that a relatively small concentration of enzymes is sufficient to drive complex chemical reactions in living organisms. In many cases, thousands of substrate molecules can be converted to products by a single enzyme molecule in a very short period. This high turnover rate allows biological systems to function effectively with only tiny amounts of enzyme molecules.
05

Enzyme Regulation

The activities of enzymes are precisely regulated in cells, ensuring that they are present and active only when their specific functions are needed. The function of enzymes can be controlled through factors such as their synthesis and degradation, localization within the cell, and regulation by small molecules or other proteins. These regulatory processes ensure that enzymes can perform their roles in reactions efficiently, while also maintaining cellular balance and preventing undesired reactions from taking place. In conclusion, enzymes are powerful catalysts that work in small concentrations due to their high efficiency, turnover rates, and precise regulatory mechanisms. These characteristics make enzymes essential for the complex chemical reactions necessary for plant and animal life to exist.

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Most popular questions from this chapter

Consider a reaction of the type aA products, in which the rate law is found to be rate =k[A]3 (termolecular reactions are improbable but possible). If the first half-life of the reaction is found to be 40. s, what is the time for the second half-life? Hint: Using your calculus knowledge, derive the integrated rate law from the differential rate law for a termolecular reaction:  Rate =d[A]dt=k[A]3

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