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The type of rate law for a reaction, either the differential rate law or the integrated rate law, is usually determined by which data is easiest to collect. Explain.

Short Answer

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The choice between using a differential rate law or an integrated rate law for a reaction depends on the available data or which data is easiest to collect. Differential rate laws relate the reaction rate to the instantaneous concentrations of reactants, and are appropriate when such data is available. Integrated rate laws describe how reactant concentrations change over time and should be used when data on concentration changes over time is more readily accessible. Choose the appropriate rate law based on your data, and then apply it to analyze the reaction rates and better understand the reaction mechanism.

Step by step solution

01

Understand the difference between differential and integrated rate laws

Differential rate laws express the reaction rate as a function of the instantaneous concentrations of reactants. This means that they describe how fast the reaction is happening at a particular moment in time. In contrast, integrated rate laws relate the reaction rate to how the concentrations of reactants change over time. Instead of providing a snapshot of the reaction rate at a specific time, they describe how the reaction progresses overall.
02

Consider the data available

The choice between using a differential rate law or an integrated rate law depends on what kind of data is available or easiest to collect. If you have data on the instantaneous concentrations of reactants at different points in time, it is more appropriate to use a differential rate law to analyze the reaction. If, on the other hand, you have data on how the concentrations of reactants change over time, an integrated rate law would be most suitable.
03

Choose the appropriate rate law

Once you have evaluated the available data, you can choose the appropriate rate law based on your findings. For example, if you find that it is easiest to collect data on the instantaneous concentrations of reactants, you should choose to use a differential rate law for the reaction. Conversely, if the data on how the concentrations of reactants change over time is more readily available or easier to collect, you should choose to use an integrated rate law.
04

Analyze the reaction using the chosen rate law

After selecting the appropriate rate law, you can then apply it to analyze the reaction rates and determine how different factors, such as the concentrations of reactants, affect the reaction. This will allow you to better understand the reaction mechanism and make predictions about the behavior of the reaction under various conditions.

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Most popular questions from this chapter

The reaction $$\left(\mathrm{CH}_{3}\right)_{3} \mathrm{CBr}+\mathrm{OH}^{-} \longrightarrow\left(\mathrm{CH}_{3}\right)_{3} \mathrm{COH}+\mathrm{Br}^{-}$$ in a certain solvent is first order with respect to \(\left(\mathrm{CH}_{3}\right)_{3} \mathrm{CBr}\) and zero order with respect to OH \(^{-} .\) In several experiments, the rate constant \(k\) was determined at different temperatures. A plot of \(\ln (k)\) versus \(1 / T\) was constructed resulting in a straight line with a slope value of \(-1.10 \times 10^{4} \mathrm{K}\) and \(y\) -intercept of 33.5. Assume \(k\) has units of \(\mathrm{s}^{-1}\).a. Determine the activation energy for this reaction. b. Determine the value of the frequency factor \(A\) c. Calculate the value of \(k\) at \(25^{\circ} \mathrm{C}\)

A proposed mechanism for a reaction is $$\mathrm{C}_{4} \mathrm{H}_{9} \mathrm{Br} \longrightarrow \mathrm{C}_{4} \mathrm{H}_{9}^{+}+\mathrm{Br}^{-} \quad \text { Slow }$$ $$\mathrm{C}_{4} \mathrm{H}_{9}^{+}+\mathrm{H}_{2} \mathrm{O} \longrightarrow \mathrm{C}_{4} \mathrm{H}_{9} \mathrm{OH}_{2}^{+} \quad \text { Fast }$$ $$\mathrm{C}_{4} \mathrm{H}_{9} \mathrm{OH}_{2}^{+}+\mathrm{H}_{2} \mathrm{O} \longrightarrow \mathrm{C}_{4} \mathrm{H}_{9} \mathrm{OH}+\mathrm{H}_{3} \mathrm{O}^{+}\quad \text { Fast }$$ Write the rate law expected for this mechanism. What is the overall balanced equation for the reaction? What are the intermediates in the proposed mechanism?

Consider two reaction vessels, one containing A and the other containing \(\mathrm{B},\) with equal concentrations at \(t=0 .\) If both substances decompose by first-order kinetics, where $$\begin{aligned} &k_{A}=4.50 \times 10^{-4} \mathrm{s}^{-1}\\\ &k_{\mathrm{B}}=3.70 \times 10^{-3} \mathrm{s}^{-1} \end{aligned}$$how much time must pass to reach a condition such that \([\mathrm{A}]=\) \(4.00[\mathrm{B}] ?\)

The activation energy for some reaction $$\mathrm{X}_{2}(g)+\mathrm{Y}_{2}(g) \longrightarrow 2 \mathrm{XY}(g)$$ is \(167 \mathrm{kJ} / \mathrm{mol},\) and \(\Delta E\) for the reaction is \(+28 \mathrm{kJ} / \mathrm{mol} .\) What is the activation energy for the decomposition of XY?

Draw a rough sketch of the energy profile for each of the following cases: a. \(\Delta E=+10 \mathrm{kJ} / \mathrm{mol}, E_{\mathrm{a}}=25 \mathrm{kJ} / \mathrm{mol}\) b. \(\Delta E=-10 \mathrm{kJ} / \mathrm{mol}, E_{\mathrm{a}}=50 \mathrm{kJ} / \mathrm{mol}\) c. \(\Delta E=-50 \mathrm{kJ} / \mathrm{mol}, E_{\mathrm{a}}=50 \mathrm{kJ} / \mathrm{mol}\)

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