Warning: foreach() argument must be of type array|object, bool given in /var/www/html/web/app/themes/studypress-core-theme/template-parts/header/mobile-offcanvas.php on line 20

Define what is meant by unimolecular and bimolecular steps. Why are termolecular steps infrequently seen in chemical reactions?

Short Answer

Expert verified
Unimolecular steps involve a single molecule undergoing a change or reaction and follow first-order kinetics, with a general form of \(A \rightarrow P\). Bimolecular steps involve two molecules interacting or colliding to form a product or undergo a change and follow second-order kinetics, with a general form of \(A + B \rightarrow P\). Termolecular steps, which involve the simultaneous collision of three molecules, are infrequently seen in chemical reactions due to the low probability of simultaneous collisions, high activation energies, and the formation of complex and unstable intermediates.

Step by step solution

01

Definition of Unimolecular Steps

Unimolecular steps involve a single molecule undergoing a change or a reaction. These steps can be described by first-order kinetics, as the rate of the reaction depends on the concentration of the single reacting molecule. The general form of a unimolecular step is \(A \rightarrow P\), where A represents the initial molecule and P represents the product(s).
02

Definition of Bimolecular Steps

Bimolecular steps involve two molecules interacting or colliding with each other to form a product or undergo a change. These steps can be described by second-order kinetics, as the rate of the reaction depends on the concentration of both reacting molecules. The general form of a bimolecular step is \(A + B \rightarrow P\), where A and B are the initial molecules and P represents the product(s).
03

Infrequent Observation of Termolecular Steps

Termolecular steps involve the simultaneous collision of three molecules to form a product or undergo a change. These steps are infrequently seen in chemical reactions for several reasons. First, the probability of three molecules colliding at the same time and the proper orientation is very low. Second, termolecular steps usually have very high activation energies, making these reactions difficult to achieve under normal conditions. Finally, termolecular steps often involve complex and unstable intermediates, which may break down or react in alternate pathways before forming the desired product. Due to these factors, termolecular steps are less common compared to unimolecular and bimolecular steps in chemical reactions.

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with Vaia!

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

Draw a rough sketch of the energy profile for each of the following cases: a. \(\Delta E=+10 \mathrm{kJ} / \mathrm{mol}, E_{\mathrm{a}}=25 \mathrm{kJ} / \mathrm{mol}\) b. \(\Delta E=-10 \mathrm{kJ} / \mathrm{mol}, E_{\mathrm{a}}=50 \mathrm{kJ} / \mathrm{mol}\) c. \(\Delta E=-50 \mathrm{kJ} / \mathrm{mol}, E_{\mathrm{a}}=50 \mathrm{kJ} / \mathrm{mol}\)

A certain reaction has the following general form: $$\mathrm{aA} \longrightarrow \mathrm{bB}$$ At a particular temperature and \([\mathrm{A}]_{0}=2.80 \times 10^{-3} \mathrm{M},\)concentration versus time data were collected for this reaction, and a plot of \(1 /[\mathrm{A}]\) versus time resulted in a straight line with a slope value of \(+3.60 \times 10^{-2} \mathrm{L} / \mathrm{mol} \cdot \mathrm{s}\) a. Determine the rate law, the integrated rate law, and the value of the rate constant for this reaction. b. Calculate the half-life for this reaction. c. How much time is required for the concentration of A to decrease to \(7.00 \times 10^{-4} \mathrm{M} ?\)

A reaction of the form $$aA \longrightarrow Products$$gives a plot of \(\ln [\mathrm{A}]\) versus time (in seconds), which is a straight line with a slope of \(-7.35 \times 10^{-3} .\) Assuming \([\mathrm{A}]_{0}=\) \(0.0100 M,\) calculate the time (in seconds) required for the reaction to reach \(22.9 \%\) completion.

Enzymes are kinetically important for many of the complex reactions necessary for plant and animal life to exist. However, only a tiny amount of any particular enzyme is required for these complex reactions to occur. Explain.

In the Haber process for the production of ammonia, $$\mathrm{N}_{2}(g)+3 \mathrm{H}_{2}(g) \longrightarrow 2 \mathrm{NH}_{3}(g)$$ what is the relationship between the rate of production of ammonia and the rate of consumption of hydrogen?

See all solutions

Recommended explanations on Chemistry Textbooks

View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.

Sign-up for free