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Which of the following will have the lowest total vapor pressure at \(25^{\circ} \mathrm{C} ?\) a. pure water (vapor pressure \(=23.8\) torr at \(25^{\circ} \mathrm{C}\) ) b. a solution of glucose in water with \(\chi_{\mathrm{C}_{\mathrm{s}} \mathrm{H}_{\mathrm{l} 2} \mathrm{O}_{\mathrm{s}}}=0.01\) c. a solution of sodium chloride in water with \(\chi_{\mathrm{NaCl}}=0.01\) d. a solution of methanol in water with \(\chi_{\mathrm{CH_{3}}, \mathrm{OH}}=0.2\) (Consider the vapor pressure of both methanol \([143\) torr at \(\left.25^{\circ} \mathrm{C}\right]\) and water.

Short Answer

Expert verified
The lowest total vapor pressure at \(25^{\circ} \mathrm{C}\) is for solutions b and c (solution of glucose in water with \(\chi_{C_{6}H_{12}O_{6}} = 0.01\) and solution of sodium chloride in water with \(\chi_{NaCl} = 0.01\)), with a vapor pressure of 23.562 torr.

Step by step solution

01

Expression for Raoult's Law

To calculate the vapor pressure of a solution, we use Raoult's Law: \(P_{solution} = P_{solvent} * \chi_{solvent}\), where \(P_{solution}\) is the vapor pressure of the solution, \(P_{solvent}\) is the vapor pressure of the pure solvent, and \(\chi_{solvent}\) is the mole fraction of the solvent in the solution.
02

Calculate the mole fraction of solvent for each solution

We are given the mole fractions for the solutes in each solution. To find the mole fraction of the solvent, we can subtract the mole fraction of the solute from 1: a. \(\chi_{water} = 1\) b. \(\chi_{water} = 1 - \chi_{C_{6}H_{12}O_{6}} = 1 - 0.01 = 0.99\) c. \(\chi_{water} = 1 - \chi_{NaCl} = 1 - 0.01 = 0.99\) d. \(\chi_{water} = 1 - \chi_{CH_{3}OH} = 1 - 0.2 = 0.8\)
03

Calculate the vapor pressure for each solution using Raoult's Law

Now we can plug our mole fractions and vapor pressures into Raoult's Law to find the vapor pressure of each solution: a. \(P_{water} = 23.8 * 1 = 23.8\) torr b. \(P_{glucose} = 23.8 * 0.99 = 23.562\) torr c. \(P_{NaCl} = 23.8 * 0.99 = 23.562\) torr d. For the methanol solution, we need to consider both the vapor pressures of methanol and water. We apply Raoult's Law separately for each component and then add the results: \(P_{CH_{3}OH} = 143 * 0.2 = 28.6\) torr and \(P_{water} = 23.8 * 0.8 = 19.04\) torr. So, \(P_{methanol} = P_{CH_{3}OH} + P_{water} = 28.6 + 19.04 = 47.64\) torr.
04

Compare the vapor pressures and determine the lowest

Comparing the vapor pressures, we observe that the glucose solution (b) and the sodium chloride solution (c) have the lowest vapor pressures at 23.562 torr. Hence, the solutions b and c (solution of glucose in water with \(\chi_{C_{6}H_{12}O_{6}} = 0.01\) and solution of sodium chloride in water with \(\chi_{NaCl} = 0.01\)) have the lowest total vapor pressure.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Vapor Pressure
Vapor pressure is a critical concept in chemistry, especially when studying the behavior of liquids and solutions. In simple terms, it's the pressure exerted by a vapor in equilibrium with its liquid phase at a given temperature. The higher the vapor pressure of a liquid, the more volatile it is, meaning it will evaporate or boil more easily.

At a constant temperature, pure liquids have a specific vapor pressure; however, when a solute is dissolved into a liquid to form a solution, the vapor pressure changes. This change is predicted by Raoult's Law, which states that the vapor pressure of a solvent above a solution is directly proportional to its mole fraction in the solution. Applying Raoult's Law helps in understanding how solutes can lower the vapor pressure of a solvent through the phenomenon called vapor pressure lowering, a type of colligative property.
Mole Fraction
Mole fraction is a way of expressing the concentration of a component in a mixture or solution. It's defined as the ratio of the number of moles of a particular component to the total number of moles of all components in the mixture.

For a solution with a solute A and solvent B, the mole fraction of A, denoted as \(\chi_A\), is calculated using the formula \(\chi_A = \frac{n_A}{n_A + n_B}\), where \(n_A\) and \(n_B\) represent the number of moles of the solute and solvent, respectively. The mole fraction is dimensionless and always less than or equal to one. It's particularly useful in Raoult's Law because it reflects the ratio of solvent to solution, thus determining the change in vapor pressure upon the addition of a solute.
Solutions Chemistry
Solutions chemistry revolves around the study of homogeneous mixtures composed of two or more substances. In a solution, the substance present in the largest amount is called the solvent, while the other substances are solutes. When solutes dissolve in a solvent, they can alter the physical properties of the solvent, such as vapor pressure, boiling point, and freezing point.

Solutions can be solid, liquid, or gas, but in the context of Raoult's Law, we're typically referring to liquid solutions. Understanding the quantitative aspects of solutions, including how solutes affect vapor pressure and mole fractions, enables chemists and students to predict how different compositions will behave under various conditions.
Colligative Properties
Colligative properties are characteristics of solutions that depend only on the ratio of the number of solute particles to the number of solvent molecules in a solution, not on the nature of the chemical species present. These properties include vapor pressure lowering, boiling point elevation, freezing point depression, and osmotic pressure.

To delve deeper into one of these properties: vapor pressure lowering is illustrated by Raoult's Law, which shows that the vapor pressure of a solvent will decrease when a non-volatile solute is added. This decrease is directly proportional to the mole fraction of the solvent in the solution. These concepts are pivotal for many practical applications, including the formulation of antifreeze solutions, the manufacturing of pharmaceuticals, and the design of chemical separation processes.

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Most popular questions from this chapter

Explain the following on the basis of the behavior of atoms and/or ions. a. Cooking with water is faster in a pressure cooker than in an open pan. b. Salt is used on icy roads. c. Melted sea ice from the Arctic Ocean produces fresh water. d. \(\mathrm{CO}_{2}(s)\) (dry ice) does not have a normal boiling point under normal atmospheric conditions, even though \(\mathrm{CO}_{2}\) is a liquid in fire extinguishers. e. Adding a solute to a solvent extends the liquid phase over a larger temperature range.

The vapor pressures of several solutions of water-propanol \(\left(\mathrm{CH}_{3} \mathrm{CH}_{2} \mathrm{CH}_{2} \mathrm{OH}\right)\) were determined at various compositions, with the following data collected at \(45^{\circ} \mathrm{C}:\) $$\begin{array}{|lc|} \hline & \text { Vapor Pressure } \\ \chi_{\mathrm{H}_{2} \mathrm{O}} & \text { (torr) } \\ 0 & 74.0 \\ 0.15 & 77.3 \\ 0.37 & 80.2 \\ 0.54 & 81.6 \\ 0.69 & 80.6 \\ 0.83 & 78.2 \\ 1.00 & 71.9 \\ \hline \end{array}$$a. Are solutions of water and propanol ideal? Explain. b. Predict the sign of \(\Delta H_{\text {soln }}\) for water-propanol solutions. c. Are the interactive forces between propanol and water molecules weaker than, stronger than, or equal to the interactive forces between the pure substances? Explain. d. Which of the solutions in the data would have the lowest normal boiling point?

A water desalination plant is set up near a salt marsh containing water that is 0.10 \(M\) NaCl. Calculate the minimum pressure that must be applied at \(20 .^{\circ} \mathrm{C}\) to purify the water by reverse osmosis. Assume \(\mathrm{NaCl}\) is completely dissociated.

A 0.500 -g sample of a compound is dissolved in enough water to form \(100.0 \mathrm{mL}\) of solution. This solution has an osmotic pressure of 2.50 atm at \(25^{\circ} \mathrm{C}\). If each molecule of the solute dissociates into two particles (in this solvent), what is the molar mass of this solute?

Which solvent, water or hexane \(\left(\mathrm{C}_{6} \mathrm{H}_{14}\right),\) would you choose to dissolve each of the following? a. \(\mathrm{Cu}\left(\mathrm{NO}_{3}\right)_{2}\) b. \(\mathrm{CS}_{2}\) c. \(\mathrm{CH}_{3} \mathrm{OH}\) d. \(\mathrm{CH}_{3}\left(\mathrm{CH}_{2}\right)_{16} \mathrm{CH}_{2} \mathrm{OH}\) e.\(\mathrm HCl\) {f .} \( \mathrm{C}_{6} \mathrm{H}_{6}\)

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