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What is ion pairing?

Short Answer

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Ion pairing is the process where oppositely charged ions in a solution associate with each other to form a neutral complex or "paired ion". There are two types of ion pairs: contact ion pairs (CIPs) and solvent-separated ion pairs (SSIPs). Factors affecting ion pairing include ion size and charge, solvent properties, concentration, and temperature. Ion pairing is essential for predicting ion behavior in chemical reactions, understanding ion transport in biological systems, estimating solubility, and explaining interactions in complex systems.

Step by step solution

01

Definition of Ion Pairing

Ion pairing is the process in which oppositely charged ions in a solution associate with each other to form a neutral complex or a "paired ion". This phenomenon occurs because the attractive electrostatic force between the cation and anion is strong enough to overcome the thermal motion and solvent separation.
02

Types of Ion Pairs

There are mainly two types of ion pairs: contact ion pairs (CIPs) and solvent-separated ion pairs (SSIPs). 1. Contact ion pairs (CIPs): These pairs involve the direct interaction between the cation and anion without any intervening solvent molecule. The ions are close together, typically within a distance of 2-3 angstroms. 2. Solvent-separated ion pairs (SSIPs): In these pairs, one or more solvent molecules are present between the cation and anion, effectively separating the ions. The ions are farther apart, generally in a distance range of 4-6 angstroms.
03

Factors Affecting Ion Pairing

Several factors can affect the formation and stability of ion pairs. Some of these factors include: 1. Ion size and charge: Larger ions or ions with higher charges are more likely to form ion pairs as they have a stronger electrostatic attraction and polarization effect. 2. Solvent properties: Polar solvents, such as water, can decrease the likelihood of ion pairing due to their ability to solvate and stabilize individual ions. The solvation shell of the ions needs to be disrupted in order for ion pairing to occur. 3. Concentration: Higher concentrations of ions in solution increase the likelihood of ion pairing because the probability of encounters between oppositely charged ions is higher. 4. Temperature: As temperature increases, the thermal motion of the ions also increases, reducing the stability of ion pairs.
04

Importance of Ion Pairing

Ion pairing is significant in various fields, such as chemistry, biology, and environmental sciences. Some examples of its importance include: 1. Predicting the behavior of ions in chemical reactions in various solvents. 2. Understanding the transport and bioavailability of ions in biological systems. 3. Estimating the solubility of salts in different solvents and environmental conditions. 4. Explaining the interactions between charged molecules in supramolecular chemistry and other complex systems.

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Most popular questions from this chapter

You have a solution of two volatile liquids, \(A\) and \(B\) (assume ideal behavior). Pure liquid A has a vapor pressure of 350.0 torr and pure liquid B has a vapor pressure of 100.0 torr at the temperature of the solution. The vapor at equilibrium above the solution has double the mole fraction of substance A that the solution does. What is the mole fraction of liquid A in the solution?

In a coffee-cup calorimeter, \(1.60 \mathrm{g} \mathrm{NH}_{4} \mathrm{NO}_{3}\) was mixed with \(75.0 \mathrm{g}\) water at an initial temperature \(25.00^{\circ} \mathrm{C}\). After dissolution of the salt, the final temperature of the calorimeter contents was \(23.34^{\circ} \mathrm{C}\) a. Assuming the solution has a heat capacity of \(4.18 \mathrm{J} / \mathrm{g} \cdot^{\circ} \mathrm{C}\) and assuming no heat loss to the calorimeter, calculate the enthalpy of solution \(\left(\Delta H_{\text {soln }}\right)\) for the dissolution of \(\mathrm{NH}_{4} \mathrm{NO}_{3}\) in units of kJ/mol. b. If the enthalpy of hydration for \(\mathrm{NH}_{4} \mathrm{NO}_{3}\) is \(-630 . \mathrm{kJ} / \mathrm{mol}\), calculate the lattice energy of \(\mathrm{NH}_{4} \mathrm{NO}_{3}\)

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How would you prepare 1.0 L of an aqueous solution of sodium chloride having an osmotic pressure of 15 atm at \(22^{\circ} \mathrm{C} ?\) Assume sodium chloride exists as \(\mathrm{Na}^{+}\) and \(\mathrm{Cl}^{-}\) ions in solution.

In lab you need to prepare at least \(100 \mathrm{mL}\) of each of the following solutions. Explain how you would proceed using the given information. a. \(2.0 \mathrm{m} \mathrm{KCl}\) in water (density of \(\mathrm{H}_{2} \mathrm{O}=1.00 \mathrm{g} / \mathrm{cm}^{3}\) ) b. \(15 \%\) NaOH by mass in water \(\left(d=1.00 \mathrm{g} / \mathrm{cm}^{3}\right)\) c. \(25 \%\) NaOH by mass in \(\mathrm{CH}_{3} \mathrm{OH}\left(d=0.79 \mathrm{g} / \mathrm{cm}^{3}\right)\) d. 0.10 mole fraction of \(\mathrm{C}_{6} \mathrm{H}_{12} \mathrm{O}_{6}\) in water \(\left(d=1.00 \mathrm{g} / \mathrm{cm}^{3}\right)\)

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