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What mass of sodium oxalate (Na2C2O4) is needed to prepare 0.250L of a 0.100M solution?

Short Answer

Expert verified
To find the mass of sodium oxalate needed, first calculate the moles of solute: Moles of solute = 0.100M×0.250L = 0.025mol.

Step by step solution

01

Find the number of moles required

Use the formula for molarity: Moles of solute = Molarity × Volume of solution Here, the molarity of the solution is 0.100 M and the volume of the solution is 0.250 L. Calculate the moles of sodium oxalate: Moles of solute = 0.100M×0.250L

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Sodium Oxalate
Sodium Oxalate, represented chemically as Na2C2O4, is a salt consisting of sodium ions and oxalate ions. It is commonly used in the laboratory for various applications such as standardizing potassium permanganate solutions.
Sodium oxalate is characterized by its white color and crystalline appearance. It is slightly soluble in water, which allows it to dissolve and form a solution when mixed with water. This property makes it suitable for preparing standard solutions in titrations and other chemical processes.
Understanding the chemical formula is crucial because it provides insight into the composition and molar mass, which are essential components in solution preparation. This knowledge helps in calculating the amount needed to achieve desired molarity in a given volume.
Solution Preparation
Solution preparation is a fundamental technique in chemistry that involves dissolving a given quantity of a solute in a solvent to form a homogeneous mixture. The goal is to achieve a specific concentration, measured as molarity, which is a crucial parameter for solution use in experiments.
When preparing a solution, it's important to follow these steps:
  • Determine the desired molarity and volume of the solution you need.
  • Calculate the number of moles of solute required using the formula: Moles of solute=Molarity×Volume (L)
  • Convert the moles of solute to grams using the molar mass of the solute, which is obtained from the chemical formula.
  • Weigh the calculated mass of the solute and dissolve it in the solvent, typically water, to reach the desired volume.
These steps ensure accurate preparation of solutions that are critical for laboratory experiments and research.
Moles of Solute
The concept of moles of solute is an essential part of understanding solution chemistry. Moles provide a bridge between the microscopic world of atoms and the macroscopic world that we encounter daily. One mole contains Avogadro's number of entities, typically atoms or molecules, making it a standard measurement unit in chemistry.
To calculate the moles of solute in a solution, use the relationship between molarity (M) and volume (V) with the formula:
  • Moles of solute=M×V
Where M is the molarity, and V is the volume in liters. This formula is crucial because it allows for the accurate preparation and scaling of chemical reactions.
Knowing how to manipulate the equation is key for tasks like diluting solutions or determining how much solute is needed to reach a specific concentration, as in the original exercise.

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Most popular questions from this chapter

The vapor pressures of several solutions of water-propanol (CH3CH2CH2OH) were determined at various compositions, with the following data collected at 45C:  Vapor Pressure χH2O (torr) 074.00.1577.30.3780.20.5481.60.6980.60.8378.21.0071.9a. Are solutions of water and propanol ideal? Explain. b. Predict the sign of ΔHsoln  for water-propanol solutions. c. Are the interactive forces between propanol and water molecules weaker than, stronger than, or equal to the interactive forces between the pure substances? Explain. d. Which of the solutions in the data would have the lowest normal boiling point?

A 2.00g sample of a large biomolecule was dissolved in 15.0 g carbon tetrachloride. The boiling point of this solution was determined to be 77.85C. Calculate the molar mass of the biomolecule. For carbon tetrachloride, the boiling-point constant is 5.03Ckg/mol, and the boiling point of pure carbon tetrachloride is 76.50C

Is molality or molarity dependent on temperature? Explain your answer. Why is molality, and not molarity, used in the equations describing freezing-point depression and boiling point elevation?

Which of the following will have the lowest total vapor pressure at 25C? a. pure water (vapor pressure =23.8 torr at 25C ) b. a solution of glucose in water with χCsHl2Os=0.01 c. a solution of sodium chloride in water with χNaCl=0.01 d. a solution of methanol in water with χCH3,OH=0.2 (Consider the vapor pressure of both methanol [143 torr at 25C] and water.

How would you prepare 1.0 L of an aqueous solution of sodium chloride having an osmotic pressure of 15 atm at 22C? Assume sodium chloride exists as Na+ and Cl ions in solution.

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