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When 1 mol of a fuel burns at constant pressure, it produces \(3452 \mathrm{~kJ}\) of heat and does \(11 \mathrm{~kJ}\) of work. What are \(\Delta E\) and \(\Delta H\) for the combustion of the fuel?

Short Answer

Expert verified
Delta E = 3452 kJ - 11 kJ = 3441 kJ, Delta H = 3452 kJ

Step by step solution

01

Calculate the Change in Internal Energy (Delta E)

According to the first law of thermodynamics, the change in internal energy (Delta E) of a system is equal to the heat (q) added to the system minus the work (w) done by the system on its surroundings. This can be written as: Delta E = q - w. Given that the heat produced is 3452 kJ and the work done is 11 kJ, we can substitute these values into the equation to get Delta E.
02

Calculate the Change in Enthalpy (Delta H)

At constant pressure, the change in enthalpy (Delta H) is equal to the heat (q_p) that is exchanged. Therefore, Delta H is equal to the heat produced during the combustion process, which is given as 3452 kJ.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Change in Internal Energy
In thermodynamics, the internal energy of a system is the total of all forms of energy present within it. It's an extensive property, meaning it depends on the amount of matter in the system. The change in internal energy, denoted as \(\text{\Delta} E\), encapsulates how the internal energy shifts due to interactions like heat transfer or work done by or on the system.

Consider our exercise where a fuel's combustion releases \(3452 \mathrm{~kJ}\) of heat and does \(11 \mathrm{~kJ}\) of work. To calculate the change in internal energy, we subtract the work done from the heat produced: \(\text{\Delta} E = q - w\). Thus, \(\text{\Delta} E = 3452 \mathrm{~kJ} - 11 \mathrm{~kJ} = 3441 \mathrm{~kJ}\). This indicates the net amount of energy that gets stored in the system after the combustion.
First Law of Thermodynamics
The first law of thermodynamics, also known as the law of energy conservation, establishes the principle that energy can neither be created nor destroyed, only transformed. It provides a relationship between the heat absorbed or released by a system and the work it performs on its surroundings, or that is done on it.

Following this principle, our exercise states that the fuel combustion at constant pressure results not just in the release of heat, but also in the system performing work. Intuitively, we can see the first law in action: the energy that was contained in the fuel's chemical bonds is converted into thermal energy, and some of it becomes mechanical energy that does work. Therefore, the change in internal energy \(\text{\Delta} E\) will equal the heat \(q\) minus the work \(w\): \(\text{\Delta} E = q - w\). This law underpins the calculations in our exercise and is fundamental to understanding energy flow in chemical processes.
Change in Enthalpy
Enthalpy, denoted as \(H\), is a thermodynamic quantity equivalent to the total heat content of a system. It is linked to the internal energy of the system but also takes into account the pressure and volume of the system. The term \(\text{\Delta} H\) represents the change in enthalpy during a process.

In reactions occurring at constant pressure, like our exercise's combustion process, the change in enthalpy \(\text{\Delta} H\) reflects the heat exchanged with the surroundings. Here, the heat produced is entirely attributed to the change in enthalpy since no volume change occurs when the pressure is held constant. Consequently, \(\text{\Delta} H\) in our scenario is directly equal to the heat produced, \(3452 \mathrm{~kJ}\). Understanding \(\text{\Delta} H\) is crucial for processes involving heat transfer under constant pressure conditions.
Combustion Process
The combustion process is a high-temperature exothermic reaction where a fuel reacts with an oxidant, typically oxygen, releasing energy in the form of heat and light. Commonly, combustion refers to the burning of a fuel like gas, wood, or oil.

In our exercise, the combustion of 1 mole of fuel at constant pressure indicates a controlled environment typically found in calorimetry studies. The substantial release of energy (heat) measured as \(3452 \mathrm{~kJ}\), is indicative of the energy available in the chemical bonds of the fuel. This energy release is used not only to increase the internal energy of the products but also to do work on the surroundings, as denoted by the \(11 \mathrm{~kJ}\) of work performed. The details of the combustion process allow for insights into the energy changes during the reaction and are fundamental in fields such as energy engineering, environmental science, and thermochemistry.

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Most popular questions from this chapter

Determine whether each process is exothermic or endothermic and indicate the sign of \(\Delta H\). a. natural gas burning on a stove b. isopropyl alcohol evaporating from skin c. water condensing from steam

Under certain nonstandard conditions, oxidation by \(\mathrm{O}_{2}(g)\) of \(1 \mathrm{~mol}\) of \(\mathrm{SO}_{2}(g)\) to \(\mathrm{SO}_{3}(g)\) absorbs \(89.5 \mathrm{~kJ}\). The enthalpy of formation of \(\mathrm{SO}_{3}(g)\) is -204.2 kJ under these conditions. Find the enthalpy of formation of \(\mathrm{SO}_{2}(g)\).

A system absorbs \(196 \mathrm{~kJ}\) of heat, and the surroundings do \(117 \mathrm{~kJ}\) of work on the system. What is the change in internal energy of the system?

Identify each energy exchange as primarily heat or work and determine whether the sign of \(\Delta E\) is positive or negative for the system. MISSED THIS? a. Sweat evaporates from skin, cooling the skin. (The evaporating sweat is the system.) b. A balloon expands against an external pressure. (The contents of the balloon is the system.) c. An aqueous chemical reaction mixture is warmed with an external flame. (The reaction mixture is the system.)

Determine the mass of \(\mathrm{CO}_{2}\) produced by burning enough of each fuel to produce \(1.00 \times 10^{2} \mathrm{~kJ}\) of heat. Which fuel contributes least to global warming per kJ of heat produced? MISSED THIS? Read Sections 7.4,\(7.6 ; \mathrm{KCV} 7.4,7.6, \mathrm{HE} 7.2,7.7\) a. \(\mathrm{CH}_{4}(g)+2 \mathrm{O}_{2}(g) \longrightarrow \mathrm{CO}_{2}(g)+2 \mathrm{H}_{2} \mathrm{O}(g)\) $$\Delta H_{\mathrm{rxn}}^{\circ}=-802.3 \mathrm{~kJ}$$ b. \(\mathrm{C}_{3} \mathrm{H}_{8}(g)+5 \mathrm{O}_{2}(g) \longrightarrow 3 \mathrm{CO}_{2}(g)+4 \mathrm{H}_{2}\mathrm{O}(g)\) $$\Delta H_{\mathrm{rxn}}^{\circ}=-2043 \mathrm{~kJ} $$c. \(\mathrm{C}_{8} \mathrm{H}_{18}(l)+{ }^{25} /{ }_{2} \mathrm{O}_{2}(g) \longrightarrow 8 \mathrm{CO}_{2}(g)+9 \mathrm{H}_{2} \mathrm{O}(g)\) $$\Delta H_{\mathrm{rnn}}^{\circ}=-5074.1 \mathrm{~kJ}$$

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