Warning: foreach() argument must be of type array|object, bool given in /var/www/html/web/app/themes/studypress-core-theme/template-parts/header/mobile-offcanvas.php on line 20

Why must chemical equations be balanced?

Short Answer

Expert verified
Chemical equations must be balanced to adhere to the Law of Conservation of Mass, ensuring that the amount of each atom is the same on both reactant and product sides of the equation.

Step by step solution

01

Understand the Law of Conservation of Mass

Recognize that the Law of Conservation of Mass states that mass can neither be created nor destroyed in a chemical reaction. Therefore, the mass of the reactants must equal the mass of the products.
02

Identify what a Chemical Equation Represents

Understand that a chemical equation represents a chemical reaction where reactants are transformed into products. The reactants are the substances that start the reaction, and the products are the new substances formed.
03

Determine the Role of Balancing in Chemical Equations

Realize that a balanced chemical equation ensures that the number of atoms of each element is the same on both sides of the equation, following the Law of Conservation of Mass. This demonstrates that atoms are simply rearranged in a chemical reaction, not created or destroyed.
04

Recognize the Practicality of Balanced Equations

Acknowledge that balanced chemical equations are essential for calculating how much reactant is required or how much product is formed in a reaction, vital for scientific experiments and industrial processes.

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with Vaia!

Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Law of Conservation of Mass
Imagine that you have a sealed bag of candies; no matter how much you shake it, the amount of candies doesn't change. This is essentially what the Law of Conservation of Mass is about. In the context of a chemical reaction, this law asserts that you must end up with the same mass of materials that you started with, because mass is neither created nor destroyed. Let's break this down: during a reaction, atoms are not lost; they are simply rearranged to form new substances. When you balance a chemical equation, you are ensuring that the mass of the reactants, or the substances you start with, is equal to the mass of the products, the new substances formed. This fundamental principle is the bedrock of chemistry and is crucial when predicting the outcomes of reactions.
Chemical Reaction
A chemical reaction is like a dance where atoms in substances (we'll call them reactants) partner up with different atoms to form new substances (the products). During this process, bonds between atoms in the reactants are broken, and new bonds are formed to create the products. This magical transformation is represented by a chemical equation, which uses chemical symbols to show what's happening. A perfectly choreographed dance requires each dancer to have a partner, and similarly, a balanced chemical equation ensures each atom from the reactants has a place in the products, respecting the Law of Conservation of Mass. By understanding chemical reactions, you're peeking into the universe's rule book for how matter behaves.
Stoichiometry
Let's turn up the complexity a notch and dive into stoichiometry. Think of it as the recipe for a chemical reaction that tells you the exact amounts of ingredients (reactants) you need to make the desired amount of the finished dish (products). It's a section of chemistry that deals with the quantities of materials consumed and produced in reactions. By balancing a chemical equation, you obtain the correct stoichiometric coefficients, which are the numbers in front of the chemical formulas that indicate the proportion of molecules needed for the reaction to proceed. Getting stoichiometry right is paramount in science because it ensures that reactions are predictable and controllable, making your experiment's results reproducible and scalable, whether you're working in a lab or an industrial plant.
Reactants and Products
Finally, let's get acquainted with the main characters of a chemical equation: reactants and products. The reactants are the substances you start with, like flour, sugar, and eggs for a cake. During the chemical reaction, these reactants are transformed into products, which are the end result of the reaction, like a freshly baked cake in our analogy. Balancing chemical equations is like making sure you have the right amount of each ingredient for your cake, so you don't end up with too much flour or too few eggs. By balancing, you verify that the number of atoms for each element is the same in the reactants and the products, making it clear how much of each substance will interact and what will be produced when the reaction comes to completion.

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

For the reaction shown, calculate the theoretical yield of product (in grams) for each initial amount of reactants. $$ 2 \mathrm{Al}(s)+3 \mathrm{Cl}_{2}(g) \longrightarrow 2 \mathrm{AlCl}_{3}(s) $$ a. \(2.0 \mathrm{~g} \mathrm{Al}, 2.0 \mathrm{~g} \mathrm{Cl}_{2}\) b. \(7.5 \mathrm{~g} \mathrm{Al}, 24.8 \mathrm{~g} \mathrm{Cl}_{2}\) c. \(0.235 \mathrm{~g} \mathrm{Al}, 1.15 \mathrm{~g} \mathrm{Cl}_{2}\)

Calculate the theoretical yield of product (in moles) for each initial amount of reactants. $$ 3 \mathrm{Mn}(s)+2 \mathrm{O}_{2}(g) \longrightarrow \mathrm{Mn}_{3} \mathrm{O}_{4}(s) $$ a. \(3 \mathrm{~mol} \mathrm{Mn}, 3 \mathrm{~mol} \mathrm{O}_{2}\) b. \(4 \mathrm{~mol} \mathrm{Mn}, 7 \mathrm{~mol} \mathrm{O}_{2}\) c. \(27.5 \mathrm{~mol} \mathrm{Mn}, 43.8 \mathrm{~mol} \mathrm{O}_{2}\)

Write a general equation for the reaction of an alkali metal with: a. a halogen b. water

What is reaction stoichiometry? What is the significance of the coefficients in a balanced chemical equation?

Consider the balanced equation: $$ \mathrm{SiO}_{2}(s)+3 \mathrm{C}(s) \longrightarrow \mathrm{SiC}(s)+2 \mathrm{CO}(g) $$ Complete the table showing the appropriate number of moles of reactants and products. If the number of moles of a reactant is provided, fill in the required amount of the other reactant, as well as the moles of each product that forms. If the number of moles of a product is provided, fill in the required amount of each reactant to make that amount of product, as well as the amount of the other product that forms.

See all solutions

Recommended explanations on Chemistry Textbooks

View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.

Sign-up for free