To ensure that the chemical equation accurately reflects the conservation of mass and charge,
balancing half-reactions is a critical step in the process of electrolysis. In the context of our exercise, the half-reactions represent the transformations of potassium ions and bromide ions separately. The balancing process ensures that the number of electrons lost in oxidation equals the number of electrons gained in reduction.
In our particular example, the half-reactions are:
- Reduction at cathode: \( K^+ + e^- \rightarrow K(s) \)
- Oxidation at anode: \(2Br^- \rightarrow Br_2(g) + 2e^- \)
These reactions are already balanced in terms of atoms and charge. For every two bromide ions that lose a total of two electrons, there are two potassium ions each gaining one electron. Instruction in balancing equations is fundamental for students because it lays the groundwork for understanding complex redox reactions and stoichiometry in chemistry.