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Explain the difference between macrostates (external arrangements of particles) and microstates (internal arrangements of particles).

Short Answer

Expert verified
Macrostates characterize the observable overall properties of a system, such as temperature or pressure, while microstates represent the detailed arrangements of particles that result in those observable macrostate properties.

Step by step solution

01

Understanding Macrostates

A macrostate is defined by macroscopic properties that characterize the thermodynamic system, such as temperature, pressure, volume, and amount of substance. These properties are the external conditions of a system that we can directly measure or observe.
02

Understanding Microstates

A microstate refers to a specific detailed microscopic configuration of a system, defining the positions and momenta of all the particles. Each macrostate of a system can be realized by many different microstates, representing the internal arrangements of particles that give rise to the observed macroscopic conditions.
03

Macrostates vs. Microstates

The key difference lies in the level of detail: macrostates describe the system as a whole and are directly measurable, while microstates account for the numerous ways in which the internal components (particles) of the system can be arranged, consistent with the given macrostate.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Thermodynamics
Thermodynamics is a branch of physics that deals with heat, work, and temperature, and their relation to energy, radiation, and physical properties of matter. The behavior of these quantities is governed by the four laws of thermodynamics which dictate how energy is transferred within and between systems, and thus are fundamental to understanding physical processes.

At the heart of thermodynamic study is the concept of a 'thermodynamic system', a carefully defined macroscopic sample of matter. The state of this system is described through observable (macroscopic) properties such as temperature, pressure, and volume. Thermodynamics allows us to predict how these properties change in response to various processes, using ideas from statistics that relate to the microscopic configurations of the system's particles.
Macroscopic Properties
Macroscopic properties are the large-scale features of a system that can be measured without observing individual particles. These include temperature, which measures the average kinetic energy of particles; pressure, which is the force exerted by particles upon the walls of their container; and volume, the space that the system occupies. Macroscopic properties allow us to describe the system's macrostate: the general, observable state of the system that is independent of the specific microscopic details of particle arrangements.

Understanding and calculating changes in these properties is crucial for many engineering applications, from fostering efficient power generation in heat engines to designing refrigeration systems.
Microscopic Configurations
While macroscopic properties describe the system in a broad sense, microscopic configurations are concerned with the positions and velocities of each individual particle within the system. These configurations represent microstates, which are numerous and typically unobservable due to their atomic or molecular scale detail.

Microstates are critical to the field of statistical mechanics, which connects the microscopic behavior of particles with the macroscopic properties observed in thermodynamics. The probability of a system being in a particular microstate is influenced by factors like energy distribution and temperature, which are reflected in macroscopic behavior through the laws of thermodynamics.
Thermodynamic Systems
A thermodynamic system is any collection of matter within a defined boundary that can exchange energy and/or matter with its surroundings. These systems are usually classified according to the types of exchanges they permit: an isolated system does not exchange energy or matter, a closed system exchanges only energy, and an open system exchanges both energy and matter.

An understanding of the different types of thermodynamic systems is vital when applying the laws of thermodynamics to real-world scenarios or during the study of various engineering and scientific problems. Each type of system, from a steam engine to the Earth's atmosphere, can be studied using thermodynamic principles to understand how energy transformations underlie the system's behavior.

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Most popular questions from this chapter

Calculate the free energy change for this reaction at \(25^{\circ} \mathrm{C}\). Is the reaction spontaneous? (Assume that all reactants and products are in their standard states.) $$ \begin{array}{c} 2 \mathrm{Ca}(s)+\mathrm{O}_{2}(g) \longrightarrow 2 \mathrm{CaO}(s) \\ \Delta H_{\mathrm{rxn}}^{\circ}=-1269.8 \mathrm{~kJ} ; \Delta S_{\mathrm{rxn}}^{\circ}=-364.6 \mathrm{~J} / \mathrm{K} \end{array} $$

Consider the reaction: $$\begin{array}{r} \mathrm{I}_{2}(g)+\mathrm{Cl}_{2}(g) \rightleftharpoons 2 \mathrm{ICl}(g) \\ K_{\mathrm{p}}=81.9 \text { at } 25{ }^{\circ} \mathrm{C} \end{array}$$ Calculate \(\Delta G_{\mathrm{rxn}}\) for the reaction at \(25^{\circ} \mathrm{C}\) under each of the following conditions: a. standard conditions b. at equilibrium c. \(P_{\mathrm{ICl}}=2.55 \mathrm{~atm} ; P_{\mathrm{I}_{2}}=0.325 \mathrm{~atm} ; P_{\mathrm{Cl}_{2}}=0.221 \mathrm{~atm}\)

Calculate the free energy change for this reaction at \(25^{\circ} \mathrm{C}\). Is the reaction spontaneous? (Assume that all reactants and products are in their standard states.) $$\begin{array}{c}\mathrm{C}_{3} \mathrm{H}_{8}(g)+5 \mathrm{O}_{2}(g) \longrightarrow 3 \mathrm{CO}_{2}(g)+4 \mathrm{H}_{2} \mathrm{O}(g) \\\\\Delta H_{\mathrm{rxn}}^{\circ}=-2217 \mathrm{~kJ} ; \Delta S_{\mathrm{rxn}}^{\circ}=101.1 \mathrm{~J} / \mathrm{K}\end{array}$$

For each pair of substances, choose the one that you expect to have the higher standard molar entropy \(\left(S^{\circ}\right)\) at \(25^{\circ} \mathrm{C} .\) Explain your choices. a. \(\mathrm{CO}(g) ; \mathrm{CO}_{2}(g)\) b. \(\mathrm{CH}_{3} \mathrm{OH}(l) ; \mathrm{CH}_{3} \mathrm{OH}(g)\) c. \(\operatorname{Ar}(g) ; \mathrm{CO}_{2}(g)\) d. \(\mathrm{CH}_{4}(g) ; \mathrm{SiH}_{4}(g)\) e. \(\mathrm{NO}_{2}(g) ; \mathrm{CH}_{3} \mathrm{CH}_{2} \mathrm{CH}_{3}(g)\) f. \(\operatorname{NaBr}(s) ; \operatorname{NaBr}(a q)\)

Nomex, a condensation copolymer used by firefighters because of its flame- resistant properties, forms from isophthalic acid and \(m\) -aminoaniline. Draw the structure of the dimer. (Hint: Water is eliminated when the bond between the monomers forms.)

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