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How is the solubility of an ionic compound with a basic anion affected by \(\mathrm{pH}\) ? Explain.

Short Answer

Expert verified
The solubility of an ionic compound with a basic anion increases in an acidic solution due to the reaction between the anion and hydronium ions, which keeps the anion dissolved in solution.

Step by step solution

01

Understand the concept of solubility

Solubility is the ability of a substance (solute) to dissolve in a solvent to form a homogeneous mixture called a solution. Ionic compounds dissolve in water by dissociating into their constituent ions.
02

Recognize the relationship between solubility and pH

The pH of the solution can affect the solubility of ionic compounds, especially those with basic anions. Basic anions can react with the hydronium (H3O+) ions present in acidic solutions, reducing the concentration of anions available to form precipitates, and thus increasing the solubility of the compound.
03

Describe the effect of varying pH on solubility

At higher pH (basic conditions), there are fewer hydronium ions available to react with the basic anions, which means the anions are more likely to form the solid compound and precipitate out of solution, decreasing solubility. At lower pH (acidic conditions), the increased hydronium ions react with the basic anions, effectively keeping them in solution by forming water and other neutral molecules, increasing the solubility of the ionic compound.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Ionic Compounds
Ionic compounds are substances composed of positive and negative ions that are held together by strong electrostatic forces known as ionic bonds. In an ionic compound, cations (positively charged ions) and anions (negatively charged ions) are present in ratios that balance the overall charge of the compound. When ionic compounds dissolve in water, they disassociate into these ions, which then interact with the water molecules.

For instance, table salt ((NaCl)) dissolves in water by separating into Na+ (sodium ions) and Cl- (chloride ions). The ease with which these compounds dissolve in water varies greatly and is influenced by different factors, including temperature and the presence of other substances in the solution, like varying pH levels, which we will explore further in subsequent sections.
Solubility Chemistry
Solubility chemistry is the study of how substances dissolve to form solutions and the conditions that affect this process. The solubility of a substance is frequently expressed as the maximum amount that can dissolve in a specific volume of solvent at a given temperature. Factors affecting solubility include the nature of the solute and solvent, temperature, pressure, and in many cases, pH.

To quantify solubility, scientists use the solubility product constant (Ksp), particularly for sparingly soluble salts. It's a unique value for a given substance under stable conditions that helps to predict whether a precipitate will form when two ionic solutions are mixed. Understanding the quantitative aspects of solubility provides vital insights into various applications, from pharmaceuticals to industrial processes.
pH Effects on Solubility
The pH of a solution can significantly alter the solubility of ionic compounds, particularly those containing basic anions or acidic cations. The pH scale is a measure of the acidity or basicity of an aqueous solution. Acidic solutions have pH values less than 7, while basic solutions have pH values greater than 7.

When ionic compounds containing basic anions such as carbonate (CO32-) or phosphate (PO43-) are dissolved in water, the pH becomes a key factor. At higher pH levels, these basic anions are less likely to react with hydronium ions (H3O+), and the solubility of such compounds may decrease as the anions start to precipitate. Conversely, at lower pH levels, these anions react with the hydronium ions in the water, forming neutral or less charged species, which then remain in solution, thus increasing the solubility of the compound.
Acid-Base Reactions
Acid-base reactions are a subset of chemical reactions that involve the transfer of protons (H+) between a pair of substances. In the context of solubility, when a basic ionic compound is placed in an acidic solution, it can undergo an acid-base reaction. The basic anion acts as a proton acceptor and reacts with the available hydronium ions (H3O+) in the solution.

The reaction between hydronium ions and basic anions can lead to the formation of water and an acid, neutralizing the basic anion and preventing it from forming a precipitate. This kind of interaction exemplifies the dynamic relationship between solubility and pH where the protonation state of the solute plays a pivotal role in determining whether a substance will dissolve or form a precipitate in a particular environment.

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Most popular questions from this chapter

Name a compound that you could add to a solution of each of the compounds to make a buffer. Explain your reasoning in complete sentences. a. acetic acid b. sodium nitrite c. ammonia d. potassium formate e. \(\mathrm{Na}_{2} \mathrm{HPO}_{4}\) (two possible answers)

Calculate the molar solubility of \(\mathrm{MX}\left(K_{\mathrm{sp}}=1.27 \times 10^{-36}\right) \mathrm{in}\) each liquid or solution. a. pure water b. \(0.25 \mathrm{M} \mathrm{MCl}_{2}\) c. \(0.20 \mathrm{M} \mathrm{Na}_{2} \mathrm{X}\)

Calculate the \(p H\) of the solution that results from each mixture. a. \(50.0 \mathrm{~mL}\) of \(0.15 \mathrm{M} \mathrm{HCHO}_{2}\) with \(75.0 \mathrm{~mL}\) of \(0.13 \mathrm{M} \mathrm{NaCHO}_{2}\) b. \(125.0 \mathrm{~mL}\) of \(0.10 \mathrm{M} \mathrm{NH}_{3}\) with \(250.0 \mathrm{~mL}\) of \(0.10 \mathrm{M} \mathrm{NH}_{4} \mathrm{Cl}\)

The \(\mathrm{pH}\) at the equivalence point of the titration of a strong acid with a strong base is 7.0. However, the \(\mathrm{pH}\) at the equivalence point of the titration of a weak acid with a strong base is above \(7.0 .\) Explain.

Without doing any calculations, determine if \(\mathrm{pH}=\mathrm{p} K_{\mathrm{a}}\) \(\mathrm{pH}>\mathrm{p} K_{\mathrm{a}},\) or \(\mathrm{pH}<\mathrm{p} K_{\mathrm{a}}\). Assume that \(\mathrm{HA}\) is a weak monoprotic acid. a. \(0.10 \mathrm{~mol}\) HA and \(0.050 \mathrm{~mol}\) of \(\mathrm{A}^{-}\) in \(1.0 \mathrm{~L}\) of solution b. \(0.10 \mathrm{~mol}\) HA and \(0.150 \mathrm{~mol}\) of \(\mathrm{A}^{-}\) in \(1.0 \mathrm{~L}\) of solution c. \(0.10 \mathrm{~mol}\) HA and \(0.050 \mathrm{~mol}\) of \(\mathrm{OH}^{-}\) in \(1.0 \mathrm{~L}\) of solution d. \(0.10 \mathrm{~mol}\) HA and \(0.075 \mathrm{~mol}\) of \(\mathrm{OH}^{-}\) in \(1.0 \mathrm{~L}\) of solution

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