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Consider the tabulated data showing the initial rate of a reaction (A \(\longrightarrow\) products) at several different concentrations of A. What is the order of the reaction? Write a rate law for the reac- tion, including the value of the rate constant, \(k\). $$ \begin{array}{cc} {[\mathrm{A}](\mathrm{M})} & \text { Initial Rate }(\mathrm{M} / \mathrm{s}) \\\ 0.12 & 0.0078 \\ \hline 0.16 & 0.0104 \\ \hline 0.20 & 0.0130 \\ \hline \end{array} $$

Short Answer

Expert verified
The reaction is first-order with respect to [A], with a rate law of Rate = k[A] where k is approximately 0.065 M^-1s^-1.

Step by step solution

01

Analyze the Relationship Between Concentration and Initial Rate

Examine the given data to determine how the initial rate changes with the concentration of reactant A. Note that when the concentration increases, the initial rate also increases. To find the order of the reaction with respect to A, one can look for a pattern in the way the rate changes as the concentration changes.
02

Calculate the Rate Constant for Each Pair of Data

Use the rate equation, Rate = k[A]^n, where n is the order of the reaction. Assume n is 1 for a first-order reaction and solve for k in each case to see if it remains constant. k = Rate/[A]. Calculate the values of k for at least two different concentrations to compare.
03

Determine the Order of the Reaction

Compare the calculated rate constants. If they are consistent across different concentrations, the assumed order is likely correct. If the calculated values of k vary significantly, try a different reaction order and repeat step 2.
04

Calculate the Ratio of Rate Changes and Concentration Changes

For a reaction where the order is n, the rate changes by a factor of (concentration change)^n. Calculate the ratios of rate changes to the corresponding concentration changes. The ratio should be constant if the correct order is assumed.
05

Write the Rate Law Including the Value of k

Once the reaction order and the value of k are confirmed to be constant for different data points, write the rate law as Rate = k[A]^n, including the calculated value of k.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Chemical Kinetics
Chemical kinetics is the study of the rates at which chemical reactions proceed and the factors that affect these rates. It's crucial in understanding how reactions happen and how to control them, whether you're developing a new pharmaceutical or running a biochemical assay.

The rate of a reaction is often expressed as the change in concentration of a reactant or product per unit time. For example, if a reaction has a high rate, it means that the substances involved are being consumed or produced quickly. Factors that can influence reaction rates include reactant concentrations, temperature, the presence of a catalyst, and the physical state of the reactants. By examining how these factors affect reaction rates, chemists can deduce the mechanism of the reaction—how reactants transform into products at the molecular level.
Rate Law
A rate law is an equation that links the rate of a chemical reaction to the concentration of its reactants. It usually takes the form of \( \text{Rate} = k[\text{Reactant}]^n \), where \( k \) is the rate constant, \( [\text{Reactant}] \) is the concentration of the reactant, and \( n \) is the reaction order. The reaction order is an exponent that provides insight into the relationship between reactant concentration and reaction rate.

Determining the rate law involves identifying the reaction order and the value of \( k \) through experiments. The process typically involves measuring the initial rates of a reaction at various reactant concentrations. Through analysis, scientists can then deduce the mathematical relationship between concentration and reaction rate.
Rate Constant
The rate constant, represented by the symbol \( k \) in the rate law equation, is a proportionality constant that links the rate of the reaction to the concentrations of reactants raised to their respective powers in the rate law equation. The value of \( k \) is specific to a particular reaction at a given temperature and does not change with the concentrations of the reactants.

The units of \( k \) depend on the overall reaction order. For a first-order reaction, \( k \) has units of \( s^{-1} \); for a second-order reaction, the units are \( M^{-1}s^{-1} \), and so on. Knowing the rate constant helps chemists predict how fast a reaction will proceed under different conditions.
Initial Rate Method
The initial rate method is a practical approach to determining the reaction order by measuring the initial rate of reaction—the rate immediately after the reaction starts, before the concentrations of reactants have changed significantly. This method is useful because it eliminates the complications that arise from changes in concentrations over time.

To use this method, a series of experiments are conducted in which the concentration of one reactant is varied while holding the others constant. The initial rates of the reaction are measured for these various concentrations. By comparing how the initial rates change with the change in reactant concentrations, the reaction order with respect to each reactant can be deduced. After finding the reaction order, the rate constant \( k \) can also be calculated.

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Most popular questions from this chapter

This reaction is first order in \(\mathrm{N}_{2} \mathrm{O}_{5}\) $$ \mathrm{N}_{2} \mathrm{O}_{5}(g) \longrightarrow \mathrm{NO}_{3}(g)+\mathrm{NO}_{2}(g) $$ The rate constant for the reaction at a certain temperature is \(0.053 / \mathrm{s}\) a. Calculate the rate of the reaction when \(\left[\mathrm{N}_{2} \mathrm{O}_{5}\right]=0.055 \mathrm{M}\). b. What would the rate of the reaction be at the concentration indicated in part a if the reaction were second order? Zero order? (Assume the same numerical value for the rate con- stant with the appropriate units.)

For the reaction \(2 \mathrm{~A}(g)+\mathrm{B}(g) \longrightarrow 3 \mathrm{C}(g),\) a. determine the expression for the rate of the reaction in terms of the change in concentration of each of the reactants and products. b. when \(A\) is decreasing at a rate of \(0.100 \mathrm{M} / \mathrm{s},\) how fast is \(\mathrm{B}\) decreasing? How fast is C increasing?

The evaporation of a 120 -nm film of \(n\) -pentane from a single crystal of aluminum oxide is zero order with a rate constant of \(1.92 \times 10^{13} \mathrm{molecules} / \mathrm{cm}^{2} \cdot \mathrm{s}\) at \(120 \mathrm{~K}\) a. If the initial surface coverage is \(8.9 \times 10^{16}\) molecules \(/ \mathrm{cm}^{2}\), how long will it take for one-half of the film to evaporate? b. What fraction of the film is left after 10 s? Assume the same initial coverage as in part a.

Consider the reaction: $$ \mathrm{NO}_{2}(g) \longrightarrow \mathrm{NO}(g)+\frac{1}{2} \mathrm{O}_{2}(g) $$ The tabulated data were collected for the concentration of \(\mathrm{NO}_{2}\) as a function of time: $$ \begin{array}{cc} \text { Time (s) } & {\left[\mathrm{NO}_{2}\right] \text { (M) }} \\ \hline 0 & 1.000 \\ \hline 10 & 0.951 \\ \hline 20 & 0.904 \\ \hline 30 & 0.860 \\ \hline 40 & 0.818 \\ \hline 50 & 0.778 \\ \hline 60 & 0.740 \\ \hline 70 & 0.704 \\ \hline 80 & 0.670 \\ \hline 90 & 0.637 \\ \hline 100 & 0.606 \\ \hline \end{array} $$ a. What is the average rate of the reaction between 10 and 20 s? Between 50 and 60 s? b. What is the rate of formation of \(\mathrm{O}_{2}\) between 50 and \(60 \mathrm{~s}\) ?

Explain the difference between a normal chemical equation for a chemical reaction and the mechanism of that reaction.

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