Chapter 15: Problem 20
What is a catalyst? How does a catalyst increase the rate of a chemical reaction?
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Chapter 15: Problem 20
What is a catalyst? How does a catalyst increase the rate of a chemical reaction?
These are the key concepts you need to understand to accurately answer the question.
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Get started for freeThe evaporation of a 120 -nm film of \(n\) -pentane from a single crystal of aluminum oxide is zero order with a rate constant of \(1.92 \times 10^{13} \mathrm{molecules} / \mathrm{cm}^{2} \cdot \mathrm{s}\) at \(120 \mathrm{~K}\) a. If the initial surface coverage is \(8.9 \times 10^{16}\) molecules \(/ \mathrm{cm}^{2}\), how long will it take for one-half of the film to evaporate? b. What fraction of the film is left after 10 s? Assume the same initial coverage as in part a.
Consider the data showing the initial rate of a reaction (A \(\longrightarrow\) products) at several different concentrations of A. What is the order of the reaction? Write a rate law for the reaction, includ- ing the value of the rate constant, \(k\). $$ \begin{array}{cc} {[\mathrm{A}](\mathrm{M})} & \text { Initial Rate }(\mathrm{M} / \mathrm{s}) \\\ 0.15 & 0.008 \\ \hline 0.30 & 0.016 \\ \hline 0.60 & 0.032 \\ \hline \end{array} $$
What are the four basic steps involved in heterogeneous catalysis?
Explain the difference between the rate law for a reaction and the integrated rate law for a reaction. What relationship does each kind of rate law express?
Iodine atoms combine to form \(\mathrm{I}_{2}\) in liquid hexane solvent with a rate constant of \(1.5 \times 10^{10} \mathrm{~L} / \mathrm{mol} \cdot \mathrm{s}\). The reaction is second order in I. since the reaction occurs so quickly, the only way to study the reaction is to create iodine atoms almost instanta- neously, usually by photochemical decomposition of \(\mathrm{I}_{2} .\) Suppose a flash of light creates an initial [I] concentration of \(0.0100 \mathrm{M} .\) How long will it take for \(95 \%\) of the newly created iodine atoms to recombine to form \(\mathrm{I}_{2} ?\)
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