Chapter 15: Problem 107
The proposed mechanism for the formation of hydrogen bromide can be written in a simplified form as: \(\begin{array}{ll}\operatorname{Br}_{2}(g) \stackrel{k_{1}}{k_{1}} 2 \operatorname{Br}(g) & \text { Fast } \\\ \operatorname{Br}(g)+\mathrm{H}_{2}(g) \stackrel{k_{2}}{\longrightarrow} \operatorname{HBr}(g)+\mathrm{H}(g) & \text { Slow } \\\ \mathrm{H}(g)+\mathrm{Br}_{2}(g) \stackrel{k_{3}}{\longrightarrow} \mathrm{HBr}(g)+\operatorname{Br}(g) & \text { Fast }\end{array}\)
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