Chapter 13: Problem 58
Replacement of aluminum ions in kaolinite with magnesium ions yields a compound with the formula \(\mathrm{Mg}_{3} \mathrm{Si}_{2} \mathrm{O}_{5}(\mathrm{OH})_{4}\). Assign an oxidation state to each element in this compound.
Short Answer
Expert verified
The correct oxidation states are \(\mathrm{Mg^{+2}_{3}}\), \(\mathrm{Si^{+4}_{2}}\), \(\mathrm{O^{-2}_{5}}\), and \(\mathrm{H^{+1}_{4}}\).
Step by step solution
01
Understand the Components of the Compound
Begin by identifying each element present in the compound \(\mathrm{Mg}_{3} \mathrm{Si}_{2} \mathrm{O}_{5}(\mathrm{OH})_{4}\). There are magnesium (Mg), silicon (Si), oxygen (O), and hydrogen (H) as part of the hydroxide (OH) groups.
02
Apply the Rules for Assigning Oxidation States
Recall the general rules for assigning oxidation states: uncombined elements have an oxidation state of zero; for a neutral molecule, the sum of the oxidation states is zero; oxygen typically has an oxidation state of -2, except in peroxides; hydrogen has an oxidation state of +1 when bonded to nonmetals. Silicon will often have an oxidation state of +4.
03
Assign Oxidation States to Hydrogen and Oxygen
Assign an oxidation state of +1 to hydrogen and -2 to each oxygen in the \(\mathrm{O}_{5}\) and in the hydroxide groups (\mathrm{OH}) since these are not peroxides.
04
Calculate the Oxidation State of Silicon
Since silicon typically has an oxidation state of +4, and there are two silicon atoms, the total contribution to the oxidation state from silicon is \(2 \times +4 = +8\).
05
Calculate the Oxidation State of Magnesium
With the oxidation states of the other elements known, the oxidation state of magnesium can be deduced by balancing the overall charge of the compound. Knowing that the compound is neutral, the oxidation states of all elements should sum up to zero.
06
Determine the Oxidation States Balance
The oxidation states of Si and O from \(\mathrm{O}_{5}\) along with O and H from \(\mathrm{OH})_{4}\) are already assigned; calculate the remaining charge that must be balanced by magnesium. There are nine oxygen atoms in total: five from \(\mathrm{O}_{5}\) and four from \(\mathrm{OH})_{4}\), resulting in \(9 \times -2 = -18\). There are four hydrogen atoms with an oxidation state of +1 each, resulting in \(4 \times +1 = +4\). The total charge from Si is +8. The sum is \(+8-18+4=-6\).
07
Assign Oxidation State to Magnesium
Three magnesium atoms must balance the remaining -6 charge, so each magnesium atom has an oxidation state of \(\frac{-6}{3} = -2\), which is not possible for magnesium. There is a mistake in the calculations since magnesium is a group 2 metal and it should have a +2 oxidation state. We should recalculate taking into account the correct oxidation state for Mg.
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Oxidation State Rules
Understanding oxidation states is crucial when it comes to analyzing chemical reactions, especially those involving electron transfer. Oxidation states, often referred to as oxidation numbers, are a bookkeeping method used in chemistry to keep track of the transfer of electrons in a compound or reaction.
Oxidation state rules provide a systematic way to assign a value to each atom in a chemical formula. Here are some fundamental concepts to remember:
Oxidation state rules provide a systematic way to assign a value to each atom in a chemical formula. Here are some fundamental concepts to remember:
- The oxidation state of any pure element is zero.
- For a molecule or compound, the sum of oxidation states is equal to its overall charge.
- Oxygen usually has an oxidation state of -2 except in peroxides or when bonded to fluorine.
- Hydrogen typically has an oxidation state of +1 when bonded with nonmetals, and -1 when bonded with metals.
- Alkali metals (group 1) have an oxidation state of +1, and alkaline earth metals (group 2) have an oxidation state of +2.
- Fluorine always has an oxidation state of -1 in its compounds.
Redox Chemistry
Redox chemistry pertains to the study of oxidation-reduction reactions where the transfer of electrons occurs between two species. It's a fundamental aspect of chemical reactions and encompasses a wide array of processes, including combustion, corrosion, photosynthesis, respiration, and even the functioning of batteries.
In a redox reaction, one species will lose electrons and become oxidized, while another will gain electrons and become reduced. This electron shift is reflected in the change in oxidation states of the atoms involved. An increase in oxidation state signifies oxidation, whereas a decrease indicates reduction. Key principles to remember are:
In a redox reaction, one species will lose electrons and become oxidized, while another will gain electrons and become reduced. This electron shift is reflected in the change in oxidation states of the atoms involved. An increase in oxidation state signifies oxidation, whereas a decrease indicates reduction. Key principles to remember are:
- Oxidation involves a loss of electrons (increase in oxidation state).
- Reduction involves a gain of electrons (decrease in oxidation state).
- The substance that gets reduced is called the oxidizing agent because it causes the other substance to be oxidized.
- Conversely, the substance that gets oxidized is called the reducing agent because it causes the other substance to be reduced.
Chemical Formula Analysis
Chemical formula analysis involves breaking down a compound's chemical formula to understand the composition and the proportion of each element within it. This analysis is key when determining the oxidation states of different atoms in a formula as well as when balancing chemical equations.
For example, in the compound \(\mathrm{Mg}_{3} \mathrm{Si}_{2} \mathrm{O}_{5}(\mathrm{OH})_{4}\), we can see that there are three magnesium (Mg) atoms, two silicon (Si) atoms, nine oxygen (O) atoms (five in the \(\mathrm{O}_{5}\) and four in the \(\mathrm{OH}\) groups), and four hydrogen (H) atoms. Knowing the typical oxidation states for these elements helps us to calculate the compound's overall charge.
After assigning the standard oxidation states (\(\mathrm{O} = -2\), \(\mathrm{H} = +1\), \(\mathrm{Si} = +4\)), we can determine that magnesium should also have a common oxidation state, which in its case is \(+2\), being an alkaline earth metal. By correctly applying the oxidation state rules to our compound, we find that the overall charge is indeed balanced, corroborating that our chemical formula analysis is correct.
For example, in the compound \(\mathrm{Mg}_{3} \mathrm{Si}_{2} \mathrm{O}_{5}(\mathrm{OH})_{4}\), we can see that there are three magnesium (Mg) atoms, two silicon (Si) atoms, nine oxygen (O) atoms (five in the \(\mathrm{O}_{5}\) and four in the \(\mathrm{OH}\) groups), and four hydrogen (H) atoms. Knowing the typical oxidation states for these elements helps us to calculate the compound's overall charge.
After assigning the standard oxidation states (\(\mathrm{O} = -2\), \(\mathrm{H} = +1\), \(\mathrm{Si} = +4\)), we can determine that magnesium should also have a common oxidation state, which in its case is \(+2\), being an alkaline earth metal. By correctly applying the oxidation state rules to our compound, we find that the overall charge is indeed balanced, corroborating that our chemical formula analysis is correct.