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Determine the molecular geometry about each interior atom and sketch each molecule. a. \(\mathrm{C}_{2} \mathrm{H}_{2}\) (skeletal structure \(\mathrm{HCCH}\) ) b. \(\mathrm{C}_{2} \mathrm{H}_{4}\) (skeletal structure \(\mathrm{H}_{2} \mathrm{CCH}_{2}\) ) c. \(\mathrm{C}_{2} \mathrm{H}_{6}\) (skeletal structure \(\mathrm{H}_{3} \mathrm{CCH}_{3}\) )

Short Answer

Expert verified
a. C2H2 has a linear molecular geometry. b. C2H4 has a trigonal planar molecular geometry around each carbon. c. C2H6 has a tetrahedral molecular geometry around each carbon.

Step by step solution

01

Determining the Molecular Geometry for C2H2

Each carbon in ethyne (C2H2) forms a triple bond with the other carbon and a single bond with hydrogen. Thus, they have a linear geometry due to the sp hybridization with bond angles of approximately 180 degrees.
02

Sketching C2H2

The skeletal structure HC≡CH represents C2H2 as a straight line with two hydrogens bonded to the ends, signifying its linear molecular geometry.
03

Determining the Molecular Geometry for C2H4

Each carbon in ethene (C2H4) forms a double bond with the other carbon and single bonds with two hydrogens. The hybridization of the carbons is sp2, which results in a trigonal planar geometry around each carbon with bond angles of approximately 120 degrees.
04

Sketching C2H4

The skeletal structure H2C=CH2 represents C2H4 as two carbons connected by a double bond, each carbon also bonded to two hydrogens, arranged in a plane, reflecting its trigonal planar molecular geometry.
05

Determining the Molecular Geometry for C2H6

Each carbon in ethane (C2H6) forms a single bond with the other carbon and three single bonds with hydrogen. The central atoms are sp3 hybridized leading to a tetrahedral geometry with bond angles close to 109.5 degrees around each of the carbons.
06

Sketching C2H6

The skeletal structure H3C-CH3 represents C2H6 with two carbon atoms single-bonded to each other, each carbon also bonded to three hydrogen atoms evenly spaced, illustrating the tetrahedral molecular geometry.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

SP Hybridization
Understanding sp hybridization is essential to grasping the structure of certain organic molecules, such as ethyne (C2H2). In sp hybridization, an atom’s s-orbital mixes with one of its p-orbitals, creating two equivalent hybrid orbitals. This hybridization occurs in carbon atoms that are involved in a triple bond, typical for molecules like C2H2.

These two sp hybrid orbitals are arranged linearly, 180 degrees apart, which explains why such molecules have a linear geometry. When a carbon atom undergoes sp hybridization, like in ethyne, it can make very strong σ (sigma) bonds with other carbons or hydrogens, leaving two p-orbitals untouched. These unhybridized p-orbitals overlap side-to-side to form π (pi) bonds, which are essential for the triple bond's formation.
  • Each carbon in C2H2 forms a σ bond through sp hybrid orbitals.
  • The linear arrangement maximizes the distance between the bonded pairs, minimizing repulsion.
  • The molecule exhibits a straight-line geometry, with bond angles at about 180 degrees.
Visualizing this linear arrangement can greatly simplify the understanding of complex organic molecules and predict their reactions.
Trigonal Planar Geometry
When examining molecules such as ethene (C2H4), one comes across the term trigonal planar geometry. This geometric arrangement is associated with sp2 hybridization, where one s-orbital and two p-orbitals within an atom, such as carbon, hybridize to form three sp2 hybrid orbitals.

These three orbitals lie in a single plane, separated by approximately 120 degrees. In ethene, each carbon atom forms three sigma bonds, two with hydrogen atoms and one with the other carbon atom, leading to this planar arrangement. Simultaneously, the remaining p-orbital that is not involved in hybridization forms a pi bond with the other carbon atom.
  • The trigonal planar shape describes a flat, three-pointed shape where bond angles are about 120 degrees.
  • In C2H4, the double bond consists of one σ bond and one π bond, contributing to the planar geometry.
  • The molecule's geometry can affect properties like polarity and reactivity.
Recognizing trigonal planar molecules is crucial for predicting their chemical behavior and interactions in various organic reactions.
Tetrahedral Geometry
Tetrahedral geometry is a common geometry seen in organic chemistry, particularly in molecules like ethane (C2H6). This geometry arises from sp3 hybridization, where one s-orbital and three p-orbitals of a carbon atom mix to create four hybrid orbitals.

These orbitals are oriented in a way that they point to the corners of a tetrahedron, with bond angles close to 109.5 degrees. For ethane, each carbon atom forms four sigma bonds, one with the other carbon and three with hydrogen atoms, resulting in a three-dimensional tetrahedral shape.
  • Each carbon atom’s four sp3 hybrid orbitals form bonds pointing toward the vertices of a tetrahedron.
  • Bond angles are approximately 109.5 degrees, reducing electron pair repulsion.
  • The tetrahedral shape is integral to understanding the spatial arrangement of atoms in a molecule and their resultant properties.
The idea of tetrahedral molecular geometry is a key concept for envisioning the arrangement of atoms in many organic compounds, thus being a fundamental principle for students learning organic chemistry.

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Most popular questions from this chapter

Give the correct electron and molecular geometries that correspond to each set of electron groups around the central atom of a molecule. a. four electron groups overall; three bonding groups and one lone pair b. four electron groups overall; two bonding groups and two lone pairs c. five electron groups overall; four bonding groups and one lone pair d. five electron groups overall; three bonding groups and two lone pairs e. five electron groups overall; two bonding groups and three lone pairs f. six electron groups overall; five bonding groups and one lone pair g. six electron groups overall; four bonding groups and two lone pairs

In VSEPR theory, which uses the Lewis model to determine molecular geometry, the trend of decreasing bond angles in \(\mathrm{CH}_{4}, \mathrm{NH}_{3},\) and \(\mathrm{H}_{2} \mathrm{O}\) is accounted for by the greater repulsion of lone pair electrons compared to bonding pair electrons. How would this trend be accounted for in valence bond theory?

When applying MO theory to heteronuclear diatomic molecules, the atomic orbitals used may be of different energies. If two atomic orbitals of different energies make two molecular orbitals, how are the energies of the molecular orbitals related to the energies of the atomic orbitals? How is the shape of the resultant molecular orbitals related to the shape of the atomic orbitals?

Name the hybridization scheme that corresponds to each electron geometry. a. linear b. trigonal planar c. tetrahedral d. trigonal bipyramidal e. octahedral

Which species has the smaller bond angle, \(\mathrm{H}_{3} \mathrm{O}^{+}\) or \(\mathrm{H}_{2} \mathrm{O}\). Explain.

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