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How is the mumber of hybrid orbitals related to the number of standard atomic orbitals that are hybridized?

Short Answer

Expert verified
The number of hybrid orbitals formed is equal to the number of atomic orbitals that are hybridized.

Step by step solution

01

Understanding Hybrid Orbitals

Hybridization is the concept of mixing atomic orbitals into new hybrid orbitals, suitable for the pairing of electrons to form chemical bonds in molecular orbitals. The number of hybrid orbitals created is equal to the number of atomic orbitals that are mixed together.
02

Identify Number of Atomic Orbitals Involved in Hybridization

To determine the number of hybrid orbitals, identify which and how many atomic orbitals are involved in the hybridization process. This could be s, p, d or f orbitals.
03

Relating Hybrid Orbitals to Atomic Orbitals

The key relationship is that the number of hybrid orbitals formed is always equal to the number of atomic orbitals that were mixed. For example, sp3 hybridization involves the mixing of one s orbital and three p orbitals, resulting in four sp3 hybrid orbitals.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Hybridization in Chemistry
Understanding hybridization in chemistry is crucial for grasping how atoms combine to form molecules with specific shapes and properties. At its core, hybridization is a theoretical model that explains the formation of equivalent orbitals capable of making bonds with other atoms. When atomic orbitals mix, they create new orbitals called hybrid orbitals, which are identical in energy.

For example, in a carbon atom, the 2s and three 2p orbitals mix to form four equivalent sp3 hybrid orbitals. This process allows carbon to form four covalent bonds with other atoms, resulting in a tetrahedral geometry, as seen in methane (CH4). The concept of hybridization helps explain molecule geometry, which cannot be understood solely by looking at unhybridized atomic orbitals.

Exercise Insight

In addressing the exercise, it's helpful to visualize the atomic orbitals as puzzle pieces that come together to create a new picture, the hybrid orbitals. When students grasp that these puzzle pieces (atomic orbitals) interact in a one-to-one fashion to create a new set (hybrid orbitals), the concept becomes clearer.
Molecular Orbitals
Molecular orbitals are resultant from the combination of atomic orbitals when two atoms approach each other closely in a bond formation process. These orbitals can be either bonding or antibonding. Bonding orbitals are lower in energy, promoting stability and electron sharing between atoms, while antibonding orbitals are higher in energy and can lead to the repulsion of electrons.

The concept of molecular orbitals extends upon basic atomic orbital theory by showing how electrons are delocalized over an entire molecule, rather than being confined to a single atom. This delocalization of electrons is what gives rise to many of the physical and chemical properties of molecules.

Exercise Improvement Advice

For a more profound understanding, students should practice sketching molecular orbital diagrams for simple molecules, considering both the atomic orbitals of the constituent atoms and the resulting molecular orbitals. This visualization helps in comprehending that the number of orbitals is conserved during the mixing process - the number of molecular orbitals equals the number of atomic orbitals combined.
Atomic Orbitals Mixing
Atomic orbitals mixing is a key aspect of quantum chemistry where individual atomic orbitals (AOs) combine to form new molecular orbitals (MOs). The mixing of orbitals takes into account their shape, energy, and phase, leading to constructive or destructive interference patterns based on the wave nature of electrons.

This interaction can result in different types of molecular orbitals, with 'bonding' molecular orbitals being the most energetically favorable for electron pairing and bond formation. The types of atomic orbitals that can mix include the s, p, d, and f orbitals, with 's' orbitals being spherical, 'p' orbitals having a dumbbell shape, and 'd' and 'f' orbitals having more complex geometries.

Connecting Concepts

To tie this concept back to the exercise, it is important to highlight that the type and number of atomic orbitals that mix dictate the shape and number of resulting hybrid orbitals. Emphasizing examples such as the formation of sp, sp2, or sp3 hybrid orbitals depending on the number and types of atomic orbitals involved will enhance students' comprehension of how atomic orbitals determine the geometry and bonding properties of molecules.

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Most popular questions from this chapter

Which statement best captures the fundamental idea behind VSEPR theory? Explain what is wrong with each of the other statements. a. The angle between two or more bonds is determined primarily by the repulsions between the electrons within those bonds and other (lone pair) electrons on the central atom of a molecule. Each of these electron groups (bonding electrons or lone pair electrons) will lower its potential energy by maximizing its separation from other electron groups, thus determining the geometry of the molecule. b. The angle between two or more bonds is determined primarily by the repulsions between the electrons within those bonds. Each of these bonding electrons will lower its potential energy by maximizing its separation from other electron groups, thus determining the geometry of the molecule. c. The geometry of a molecule is determined by the shapes of the overlapping orbitals that form the chemical bonds. Therefore, to determine the geometry of a molecule, you must determine the shapes of the orbitals involved in bonding.

Draw the structures of two compounds that have the composition \(\mathrm{CH}_{3} \mathrm{NO}_{2}\) and have all three \(\mathrm{H}\) atoms bonded to the \(\mathrm{C}\). Predict which compound has the larger ONO bond angle.

Use VSEPR theory to predict the geometry (including bond angles) about each interior atom of methyl azide \(\left(\mathrm{CH}_{3} \mathrm{~N}_{3}\right),\) and make a sketch of the molecule. Would you expect the bond angle between the two interior nitrogen atoms to be the same or different? Would you expect the two nitrogen-nitrogen bond lengths to be the same or different?

Sketch the antibonding molecular orbital that results from the linear combination of two 1 s orbitals. Indicate the region where interference occurs and state the kind of interference (constructive or destructive).

Which hybridization scheme allows the formation of at least one \(\pi\) bond? $$ s p^{3}, s p^{2}, s p^{3} d^{2} $$

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