Warning: foreach() argument must be of type array|object, bool given in /var/www/html/web/app/themes/studypress-core-theme/template-parts/header/mobile-offcanvas.php on line 20

In the molecular orbital model, compare and contrast \(\sigma\) bonds with \(\pi\) bonds. What orbitals form the \(\sigma\) bonds and what orbit- als form the \(\pi\) bonds? Assume the \(z\) -axis is the internuclear axis.

Short Answer

Expert verified
In the molecular orbital model, σ bonds are formed by the head-to-head overlap of atomic orbitals (such as s orbitals and the z-component of p orbitals e.g. 1s-1s or 2pz-2pz). They are stronger and more stable due to the direct orbital overlap along the internuclear axis (z-axis). In contrast, π bonds are formed by the side-to-side overlap of atomic orbitals (x and y components of p orbitals e.g. 2px-2px or 2py-2py) and have electron distribution above and below the internuclear axis (z-axis), making them weaker and less stable due to less effective orbital overlap.

Step by step solution

01

Understand Sigma (σ) and Pi (π) Bonds

The molecular orbital model explains the formation of chemical bonds through the merging of atomic orbitals. There are two types of bonds in this model: the sigma (σ) bond and the pi (π) bond. Both of these bonds are formed by the overlapping of atomic orbitals, but the way they form and their characteristics are different.
02

Define and Describe Sigma (σ) Bonds

Sigma (σ) bonds are formed by the head-to-head overlapping of atomic orbitals. They are cylindrical in shape, symmetric along the internuclear axis (z-axis in this case), and have an electron probability distribution concentrated on the internuclear axis. The electron cloud in a σ bond directly overlaps between the two bonded atoms. Due to this direct overlapping, σ bonds are generally stronger, resulting in greater stability and more significant bond energy.
03

Identify Orbitals That Form Sigma (σ) Bonds

The overlapping of s orbitals (1s, 2s, 3s, etc.) and the z-axis component of p orbitals (pz) form σ bonds. For example, when two hydrogen atoms bond through their 1s orbitals, a σ bond is formed. 1s-1s, 2s-2s, 1s-2s, and 2pz-2pz overlapping combinations can produce σ bonds.
04

Define and Describe Pi (π) Bonds

Pi (π) bonds are formed by the side-to-side overlapping of atomic orbitals. Unlike σ bonds, π bonds are not cylindrical nor symmetric along the internuclear axis. Instead, the electron probability distribution in π bonds is found above and below the internuclear axis. As a result, π bonds are generally weaker than σ bonds due to less effective orbital overlap and larger electron cloud separation from the internuclear axis.
05

Identify Orbitals That Form Pi (π) Bonds

The x-axis (px) and y-axis (py) components of p orbitals form π bonds. Since these components are perpendicular to the internuclear axis (z-axis), the resulting bond structure will have electron distribution above and below the z-axis. 2px-2px and 2py-2py overlapping combinations can produce π bonds. To summarize, σ bonds are formed by the head-to-head overlap of atomic orbitals (s orbitals and the z-component of p orbitals), while π bonds are formed by the side-to-side overlap of atomic orbitals (x and y components of p orbitals). Sigma bonds are stronger and more stable due to more effective orbital overlap, while pi bonds are weaker due to less effective orbital overlap and larger electron cloud separation from the internuclear axis.

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with Vaia!

Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Sigma Bonds
A sigma (\(\sigma\)) bond is a type of chemical bond formed through the head-to-head overlapping of atomic orbitals. This head-on overlap results in a cylindrical shape that is symmetric along the internuclear axis, which is often defined as the z-axis.

One key feature of \(\sigma\) bonds is that the electron cloud is concentrated directly between the two nuclei, leading to a strong bond due to effective overlapping. The strength and stability of a \(\sigma\) bond make it the primary bond in molecules.
  • The direct overlap provides greater bond energy.
  • They hold the highest electron probability directly on the internuclear axis.
The formation involves overlapping s orbitals like 1s-1s, as well as other configurations like 2s-2s, 1s-2s, and particularly 2\(p_z\)-2\(p_z\) from p orbitals.

Overall, \(\sigma\) bonds are the backbone of molecular structures in chemistry, providing significant structural integrity due to their strong interaction.
Pi Bonds
Pi (\(\pi\)) bonds are distinctly different from \(\sigma\) bonds. They occur through the side-to-side overlap of atomic orbitals and are characterized by an electron probability distribution that is not along the internuclear axis but is above and below it.

This configuration arises primarily from the overlapping of the \(p_x\) and \(p_y\) orbitals. Given their perpendicular orientation to the internuclear z-axis, \(\pi\) bonds have an inherently weaker overlap when compared to \(\sigma\) bonds.
  • These bonds are not cylindrical, hence not symmetric around the z-axis.
  • The electron cloud creates two lobes on opposite sides of the bond axis.
Pi bonds are usually formed in conjunction with a \(\sigma\) bond in multiple bonds like double or triple bonds, enhancing molecular configuration.

While weaker than \(\sigma\) bonds, \(\pi\) bonds add complexity and versatility to molecular structures by accommodating delocalization of electrons, such as in cases of resonance.
Atomic Orbitals
Atomic orbitals are the regions around an atom's nucleus where the probability of finding electrons is highest. These orbitals come in different shapes and sizes, which significantly influence how they overlap to form bonds.

In the formation of molecular orbitals, atomic orbitals merge in specific ways:
  • s orbitals are spherical and overlap directly to form \(\sigma\) bonds.
  • p orbitals come in three orientations: \(p_x\), \(p_y\), and \(p_z\), each with a distinct axis of overlap potential.
The \(p_z\) orbitals, aligned with the internuclear axis, engage in head-on overlap better suited for \(\sigma\) bond formation.

Conversely, \(p_x\) and \(p_y\), being sideways in nature, participate in creating \(\pi\) bonds. This variety in orientation grants flexibility in the bonding process, allowing for the complex molecular geometries observed in nature.

Understanding atomic orbitals and their arrangements is crucial to anticipating how molecules interact, bond, and achieve stability through electron sharing.

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

Use the localized electron model to describe the bonding in \(\mathrm{H}_{2} \mathrm{CO}\) (carbon is the central atom).

For each of the following molecules, write the Lewis structure(s), predict the molecular structure (including bond angles), give the expected hybrid orbitals on the central atom, and predict the overall polarity. a. \(\mathrm{CF}_{4}\) e. \(\mathrm{BeH}_{2}\) i. \(\mathrm{KrF}_{4}\) b. \(\mathrm{NF}_{3}\) f. \(\mathrm{TeF}_{4}\) j. \(\mathrm{SeF}_{6}\) c. \(\mathrm{OF}_{2}\) g. AsF \(_{5}\) k. IFs d. \(\mathrm{BF}_{3}\) h. \(\mathrm{KrF}_{2}\) L. \(\mathrm{IF}_{3}\)

Arrange the following from lowest to highest ionization energy: \(\mathrm{O}, \mathrm{O}_{2}, \mathrm{O}_{2}^{-}, \mathrm{O}_{2}^{+} .\) Explain your answer.

Cyanamide \(\left(\mathrm{H}_{2} \mathrm{NCN}\right)\), an important industrial chemical, is produced by the following steps: $$ \begin{aligned} \mathrm{CaC}_{2}+\mathrm{N}_{2} & \longrightarrow \mathrm{CaNCN}+\mathrm{C} \\\ \mathrm{CaNCN} & \stackrel{\text { Acid }}{\longrightarrow} \mathrm{H}_{2} \mathrm{NCN} \\ \text { Cyanamide } \end{aligned} $$ Calcium cyanamide (CaNCN) is used as a direct-application fertilizer, weed killer, and cotton defoliant. It is also used to make cyanamide, dicyandiamide, and melamine plastics: Dicyandiamide not shown) a. Write Lewis structures for \(\mathrm{NCN}^{2-}, \mathrm{H}_{2} \mathrm{NCN}\), dicyandiamide, and melamine, including resonance structures where appropriate. b. Give the hybridization of the \(\mathrm{C}\) and \(\mathrm{N}\) atoms in each species. c. How many \(\sigma\) bonds and how many \(\pi\) bonds are in each species? d. Is the ring in melamine planar? e. There are three different \(\mathrm{C}-\mathrm{N}\) bond distances in dicyandiamide, \(\mathrm{NCNC}\left(\mathrm{NH}_{2}\right)_{2}\), and the molecule is nonlinear. Of all the resonance structures you drew for this molecule, predict which should be the most important.

The \(\mathrm{N}_{2} \mathrm{O}\) molecule is linear and polar. a. On the basis of this experimental evidence, which arrangement, NNO or NON, is correct? Explain your answer. b. On the basis of your answer to part a, write the Lewis structure of \(\mathrm{N}_{2} \mathrm{O}\) (including resonance forms). Give the formal charge on each atom and the hybridization of the central atom. c. How would the multiple bonding in \(\mathrm{N} \equiv \mathrm{N}-\ddot{\mathrm{O}}\) : be described in terms of orbitals?

See all solutions

Recommended explanations on Chemistry Textbooks

View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.

Sign-up for free