Chapter 7: Problem 82
Give the maximum number of electrons in an atom that can have these quantum numbers: a. \(n=0, \ell=0, m_{\ell}=0\) b. \(n=2, \ell=1, m_{\ell}=-1, m_{s}=-\frac{1}{2}\) c. \(n=3, m_{s}=+\frac{1}{2}\) d. \(n=2, \ell=2\) e. \(n=1, \ell=0, m_{\ell}=0\)
Short Answer
Expert verified
(a) 0 electrons
(b) 1 electron
(c) 9 electrons
(d) 0 electrons
(e) 2 electrons
Step by step solution
01
(a) n=0, l=0, ml=0
Quantum numbers have specific roles and ranges. The principal quantum number n starts from the positive integers (1, 2, 3, ...). Since n=0 is not a valid principal quantum number, there can be no electrons with this configuration.
02
(b) n=2, l=1, ml=-1, ms=-1/2
The allowed values of l range from 0 to n-1. In this case, l=1 is allowed for n=2. The ml values range from -l to +l, so ml=-1 is allowed for l=1. ms takes values of ±1/2, so ms=-1/2 is allowed as well. This configuration is valid, and since the electron has a defined spin, there can be only one electron with this configuration.
03
(c) n=3, ms=+1/2
When n=3, the allowed l values are 0, 1, and 2. For each l, the allowed ml values are:
- l=0: ml=0
- l=1: ml=-1, 0, +1
- l=2: ml=-2, -1, 0, +1, +2
Considering the ms value of +1/2, we have two possible electrons for each ml value (except for the one with ms=-1/2). Thus, there can be a maximum of 9 electrons with these quantum numbers.
04
(d) n=2, l=2
The allowed values of l range from 0 to n-1. For n=2, l values can be 0 or 1 only. Since l=2 is not a valid value for n=2, there can be no electrons with this configuration.
05
(e) n=1, l=0, ml=0
The allowed values for l range from 0 to n-1. In this case, l=0 is allowed for n=1. For l=0, the only allowed ml value is 0. There can be two electrons for this valid quantum number configuration based on the possible ms values of ±1/2.
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Electron Configuration
Electron configuration describes the distribution of electrons in an atom’s orbitals. Understanding this helps figure out how electrons are arranged in different shells and subshells, defined by four types of quantum numbers.
- The principal quantum number \( n \) determines the shell.
- The azimuthal quantum number \( \ell \), sometimes called the angular momentum quantum number, defines the subshell shape.
- The magnetic quantum number \( m_\ell \) decides the orientation of an electron's orbital within a subshell.
- The spin quantum number \( m_s \) explains the electron's spin direction.
Principal Quantum Number
The principal quantum number, \( n \), is essential in describing an electron's position in an atom. It tells us the main energy level or shell occupied by an electron.
- \( n \) can take positive integer values such as 1, 2, 3, and so forth.
- This number signifies the size of the electron orbitals: the larger the \( n \), the bigger the orbital and the higher the energy level.
Electron Spin
Electron spin is a fundamental property akin to the electron’s own angular momentum. The spin quantum number, \( m_s \), explains how an electron can behave like a tiny magnet.
- \( m_s \) can either be \(+\frac{1}{2}\) or \(-\frac{1}{2}\).
- This indicates the two possible spin states: up (+1/2) or down (-1/2).
Magnetic Quantum Number
The magnetic quantum number, \( m_\ell \), identifies the orientation of an orbital within its subshell. This quantum number provides further definition after the azimuthal quantum number \( \ell \).
- \( m_\ell \) ranges from \(-\ell\) to \(+\ell\).
- For a given \( \ell \), this creates \(2\ell + 1\) possible orientations of the orbital.