Warning: foreach() argument must be of type array|object, bool given in /var/www/html/web/app/themes/studypress-core-theme/template-parts/header/mobile-offcanvas.php on line 20

Calculate the percent composition by mass of the following compounds that are important starting materials for synthetic polymers: a. \(\mathrm{C}_{3} \mathrm{H}_{4} \mathrm{O}_{2}\) (acrylic acid, from which acrylic plastics are made) b. \(\mathrm{C}_{4} \mathrm{H}_{6} \mathrm{O}_{2}\) (methyl acrylate, from which Plexiglas is made) c. \(\mathrm{C}_{3} \mathrm{H}_{3} \mathrm{~N}\) (acrylonitrile, from which Orlon is made)

Short Answer

Expert verified
The percent compositions by mass for the compounds are: a. Acrylic Acid: \(50.00\% \ \mathrm{C}, 5.58\% \ \mathrm{H}, 44.42\% \ \mathrm{O}\) b. Methyl Acrylate: \(55.82\% \ \mathrm{C}, 7.03\% \ \mathrm{H}, 37.15\% \ \mathrm{O}\) c. Acrylonitrile: \(67.76\% \ \mathrm{C}, 5.70\% \ \mathrm{H}, 26.54\% \ \mathrm{N}\)

Step by step solution

01

Find the molar mass of \(\mathrm{C}_{3} \mathrm{H}_{4} \mathrm{O}_{2}\)

From the periodic table, the atomic masses of Carbon, Hydrogen, and Oxygen are \(12.01\,\text{g/mol}\), \(1.01\,\text{g/mol}\), and \(16.00\,\text{g/mol}\), respectively. The molar mass of \(\mathrm{C}_{3} \mathrm{H}_{4} \mathrm{O}_{2}\) is: \[3(12.01)+4(1.01)+2(16.00)=72.06\,\text{g/mol}\]
02

Find the percent composition by mass of each element

To find the percent composition by mass of each element, divide the mass contribution of each element by the total molar mass and multiply by 100. Carbon: \(\frac{3(12.01)}{72.06} \times 100 = 50.00\%\) Hydrogen: \(\frac{4(1.01)}{72.06} \times 100 = 5.58\%\) Oxygen: \(\frac{2(16.00)}{72.06} \times 100 = 44.42\%\) Acrylic Acid Percent Composition: \(50.00\% \ \mathrm{C}, 5.58\% \ \mathrm{H}, 44.42\% \ \mathrm{O}\) b. Methyl Acrylate:
03

Find the molar mass of \(\mathrm{C}_{4} \mathrm{H}_{6} \mathrm{O}_{2}\)

The molar mass of \(\mathrm{C}_{4} \mathrm{H}_{6} \mathrm{O}_{2}\) is: \[4(12.01)+6(1.01)+2(16.00)=86.08\,\text{g/mol}\]
04

Find the percent composition by mass of each element

To find the percent composition by mass of each element, divide the mass contribution of each element by the total molar mass and multiply by 100. Carbon: \(\frac{4(12.01)}{86.08} \times 100 = 55.82\%\) Hydrogen: \(\frac{6(1.01)}{86.08} \times 100 = 7.03\%\) Oxygen: \(\frac{2(16.00)}{86.08} \times 100 = 37.15\%\) Methyl Acrylate Percent Composition: \(55.82\% \ \mathrm{C}, 7.03\% \ \mathrm{H}, 37.15\% \ \mathrm{O}\) c. Acrylonitrile:
05

Find the molar mass of \(\mathrm{C}_{3} \mathrm{H}_{3} \mathrm{N}\)

From the periodic table, the atomic mass of Nitrogen is \(14.01\,\text{g/mol}\). The molar mass of \(\mathrm{C}_{3} \mathrm{H}_{3} \mathrm{N}\) is: \[3(12.01)+3(1.01)+1(14.01)=53.08\,\text{g/mol}\]
06

Find the percent composition by mass of each element

To find the percent composition by mass of each element, divide the mass contribution of each element by the total molar mass and multiply by 100. Carbon: \(\frac{3(12.01)}{53.08} \times 100 = 67.76\%\) Hydrogen: \(\frac{3(1.01)}{53.08} \times 100 = 5.70\%\) Nitrogen: \(\frac{1(14.01)}{53.08} \times 100 = 26.54\%\) Acrylonitrile Percent Composition: \(67.76\% \ \mathrm{C}, 5.70\% \ \mathrm{H}, 26.54\% \ \mathrm{N}\)

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with Vaia!

Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Molar Mass Calculation
Understanding molar mass is essential in chemistry as it helps in determining the mass of individual elements in a compound. The molar mass of a compound is the sum of the atomic masses of all the atoms in its chemical formula. To calculate it, you'll need the atomic masses of the elements, which can be found on the periodic table.
For example, in acrylic acid with the formula \(\mathrm{C}_3\mathrm{H}_4\mathrm{O}_2\), the molar mass is calculated by:
  • Multiplying the atomic mass of carbon (12.01 g/mol) by the number of carbon atoms (3)
  • Adding the result to the total mass of hydrogen atoms: 4 x 1.01 g/mol
  • Finally, adding the total mass of oxygen atoms: 2 x 16.00 g/mol
This results in a total molar mass of \(72.06\,\text{g/mol}\). Molar mass is an integral part of finding the percent composition, which tells us how much of each element is in a compound.
Synthetic Polymers
Synthetic polymers are large, complex molecules created from simpler units known as monomers. These materials are crucial in manufacturing a wide range of products, from plastics to fibers, because they can be customized for different properties.
Examples include acrylic acid, methyl acrylate, and acrylonitrile. Acrylic acid is used to make acrylic plastics, which are known for their transparency and resistance to breaking. Methyl acrylate serves as a building block for Plexiglas, a material widely used for making windows and lenses. Acrylonitrile is a key component in Orlon, a lightweight, strong fiber used for textiles.
  • Acrylic plastics: durable and resistant
  • Plexiglas: clear and shatter-resistant
  • Orlon: strong and flexible fiber
These polymers have a profound impact on our daily lives and advancements in technology, enhancing both utilities and aesthetics of countless products.
Elemental Analysis
Elemental analysis involves determining the percentage of each element in a compound. It is an essential analytical chemistry method used in both quality control and research.
Here, percent composition refers to the mass percentage each element contributes to the total mass of the compound. The formula for finding percent composition by mass is:
  • Compute the mass contribution of each element: # of atoms \(\times\) atomic mass
  • Divide the result by the compound's total molar mass
  • Multiply by 100 to convert it to a percentage
For instance, in acrylic acid, carbon has a percent composition of 50.00%. This process highlights which elements predominate in a compound, which is critical in determining its properties. By understanding these ratios, chemists can infer how a compound will behave in reactions or in product formulations.

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

Consider the following unbalanced reaction: $$ \mathrm{P}_{4}(s)+\mathrm{F}_{2}(g) \longrightarrow \mathrm{PF}_{3}(g) $$ What mass of \(\mathrm{F}_{2}\) is needed to produce \(120 . \mathrm{g}\) of \(\mathrm{PF}_{3}\) if the reaction has a \(78.1 \%\) yield?

Consider the following balanced chemical equation: A 1 5B h 3C 1 4D a. Equal masses of A and B are reacted. Complete each of the following with either “A is the limiting reactant because ________”; “B is the limiting reactant because ________”; or “we cannot determine the limiting reactant because ________.” i. If the molar mass of A is greater than the molar mass of B, then ii. If the molar mass of B is greater than the molar mass of A, then b. The products of the reaction are carbon dioxide (C) and water (D). Compound A has a similar molar mass to carbon dioxide. Compound B is a diatomic molecule. Identify compound B, and support your answer. c. Compound A is a hydrocarbon that is 81.71% carbon by mass. Determine its empirical and molecular formulas

Gallium arsenide, GaAs, has gained widespread use in semiconductor devices that convert light and electrical signals in fiber-optic communications systems. Gallium consists of \(60 . \%^{69} \mathrm{Ga}\) and \(40 . \%^{71} \mathrm{Ga}\). Arsenic has only one naturally occurring isotope, \({ }^{75}\) As. Gallium arsenide is a polymeric material, but its mass spectrum shows fragments with the formulas GaAs and \(\mathrm{Ga}_{2} \mathrm{As}_{2}\). What would the distribution of peaks look like for these two fragments?

Give the balanced equation for each of the following chemical reactions: a. Glucose \(\left(\mathrm{C}_{6} \mathrm{H}_{12} \mathrm{O}_{6}\right)\) reacts with oxygen gas to produce gaseous carbon dioxide and water vapor. b. Solid iron(III) sulfide reacts with gaseous hydrogen chloride to form solid iron(III) chloride and hydrogen sulfide gas. c. Carbon disulfide liquid reacts with ammonia gas to produce hydrogen sulfide gas and solid ammonium thiocyanate \(\left(\mathrm{NH}_{4} \mathrm{SCN}\right)\).

A potential fuel for rockets is a combination of \(\mathrm{B}_{4} \mathrm{H}_{9}\) and \(\mathrm{O}_{2}\) The two react according to the following balanced equation: $$ 2 \mathrm{~B}_{4} \mathrm{H}_{9}(l)+12 \mathrm{O}_{2}(g) \longrightarrow 5 \mathrm{~B}_{2} \mathrm{O}_{3}(s)+9 \mathrm{H}_{2} \mathrm{O}(g) $$ If one tank in a rocket holds \(126 \mathrm{~g} \mathrm{~B}_{4} \mathrm{H}_{9}\) and another tank holds \(192 \mathrm{~g} \mathrm{O}_{2}\), what mass of water can be produced when the entire contents of each tank react together?

See all solutions

Recommended explanations on Chemistry Textbooks

View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.

Sign-up for free