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The complex ion \(\mathrm{NiCl}_{4}^{2-}\) has two unpaired electrons, whereas \(\mathrm{Ni}(\mathrm{CN})_{4}{ }^{2-}\) is diamagnetic. Propose structures for these two complex ions.

Short Answer

Expert verified
The proposed structures for the two complex ions are: 1. \(NiCl_{4}^{2-}\): Tetrahedral structure with two unpaired electrons due to weak field ligands (chloride ions). 2. \(Ni(CN)_{4}^{2-}\): Square planar structure with no unpaired electrons due to strong field ligands (cyanide ions).

Step by step solution

01

Determine the oxidation state

First, we need to determine the oxidation state of the nickel (Ni) in both complex ions. For \(NiCl_{4}^{2-}\): 4 chloride ions, each with a -1 charge, results in a total charge of -4. So the nickel must have an oxidation state of +2 to compensate and give an overall charge of -2 for the ion. For \(Ni(CN)_{4}^{2-}\): 4 cyanide ions, each with a -1 charge, also results in a total charge of -4. In this case, the nickel must also have an oxidation state of +2 to compensate and give an overall charge of -2 for the ion. In both complex ions, the nickel ion has an oxidation state of +2.
02

Determine the electron configuration

Next, we need to find out the electron configuration of the nickel ion in the +2 oxidation state. The atom Ni has an atomic number of 28, which means it has 28 electrons in its ground state. The electron configuration for the ground state Ni is [Ar]3d^8 4s^2, where [Ar] represents the electron configuration of the argon atom (1s^2 2s^2 2p^6 3s^2 3p^6). When we remove 2 electrons from Ni to obtain the Ni^2+ ion, we get the following electron configuration: \[Ni^{2+}: [Ar]3d^8\]
03

Apply Crystal Field Theory

Now we will apply Crystal Field Theory (CFT) to each complex ion. CFT is used to describe the interaction between the central metal ion and the ligands in a complex ion. In the case of \(NiCl_{4}^{2-}\), the chlorine ligands are considered weak field ligands. This means that they will not cause a significant splitting of the 3d orbital energy levels. Thus, Ni^2+ with the electron configuration [Ar]3d^8 will have the electrons distributed as such: two sets of paired electrons and two unpaired electrons, satisfying the given condition that \(NiCl_{4}^{2-}\) has two unpaired electrons. The structure proposed for \(NiCl_{4}^{2-}\) is a tetrahedral one (4 ligands). In the case of \(Ni(CN)_{4}^{2-}\), the cyanide ligands are considered strong field ligands. This means that they will cause a significant splitting of the 3d orbital energy levels. The electron configuration of Ni^2+ in a strong field will cause the electrons to pair up in the lower energy d orbitals, resulting in a diamagnetic complex as mentioned in the problem statement. The structure proposed for \(Ni(CN)_{4}^{2-}\) is a square planar one (4 ligands).
04

Conclusion

The proposed structures for the two complex ions are: 1. \(NiCl_{4}^{2-}\): Tetrahedral structure with two unpaired electrons due to weak field ligands (chloride ions). 2. \(Ni(CN)_{4}^{2-}\): Square planar structure with no unpaired electrons due to strong field ligands (cyanide ions).

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Crystal Field Theory
Crystal Field Theory (CFT) is a model that describes the breaking up of degenerate (same energy) d-orbitals in transition metal ions when they form coordination compounds. When ligands approach the central metal ion, the spatial distribution of the ligands around the central ion affects the energy levels of the d-orbitals. Depending on the geometry of the complex, certain orbitals will experience more repulsion and have higher energy than others.

This change in energy levels leads to what we call 'crystal field splitting'. Strong field ligands, like cyanide (CN), cause a significant separation in the d-orbitals' energy, leading to a low-spin configuration where electrons are more likely to pair up in the lower energy orbitals. Weak field ligands, like chloride (Cl), result in a smaller splitting and typically cause a high-spin configuration where electrons will occupy higher energy orbitals to minimize electron pairing.
Electron Configuration
Electron configuration describes the arrangement of electrons around an atomic nucleus according to specific rules. For transition metals, the electron configuration significantly influences their chemistry, including the formation of complex ions. When transition metals like nickel (Ni) form ions, they generally lose their outer s-orbital electrons first before losing d-orbital electrons.

The electron configuration of a free Ni atom is [Ar]3d84s2, but once it loses two electrons to become Ni2+, the configuration is [Ar]3d8. Understanding this is key to predicting magnetic properties and the geometry of the transition metal complexes.
Ligands
Ligands are ions or molecules that bind to a central metal atom to form a coordination complex. They can have different effects on the metal ion's d-orbitals depending on their field strength. Ligands like water, ammonia, and chloride are typical examples of weak field ligands, and they tend to produce high-spin complexes. Conversely, ligands such as cyanide, carbon monoxide, and phosphines are strong field ligands, often creating low-spin complexes.

The number and spatial arrangement of ligands around the metal ion, known as the coordination number and geometry, respectively, determine the shape and properties of the complex. The nature of ligands and their arrangement are crucial in applications such as catalysis, material science, and medicine.
Oxidation State
The oxidation state, also known as the oxidation number, is a concept that allows chemists to keep track of electron transfer in chemical reactions, especially redox reactions. It is essentially a bookkeeping tool that assigns a hypothetical charge to atoms in a molecule or ion if the electrons were assigned to the more electronegative atom. In coordination chemistry, the oxidation state of the metal center is paramount in determining the overall properties of the complex ion.

The oxidation state helps predict how many electrons are in the d-orbitals of the metal, which influences the magnetism and geometry of the complex. For instance, a nickel ion (Ni) in a +2 oxidation state, as in the complex ions NiCl42− and Ni(CN)42−, will have different physical and chemical properties based on the ligands attached and their respective field strengths.

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Most popular questions from this chapter

One of the classic methods for the determination of the manganese content in steel involves converting all the manganese to the deeply colored permanganate ion and then measuring the absorption of light. The steel is first dissolved in nitric acid, producing the manganese(II) ion and nitrogen dioxide gas. This solution is then reacted with an acidic solution containing periodate ion; the products are the permanganate and iodate ions. Write balanced chemical equations for both of these steps.

Acetylacetone (see Exercise 43, part a), abbreviated acacH, is a bidentate ligand. It loses a proton and coordinates as acac-, as shown below: Acetylacetone reacts with an ethanol solution containing a salt of europium to give a compound that is \(40.1 \% \mathrm{C}\) and \(4.71 \% \mathrm{H}\) by mass. Combustion of \(0.286 \mathrm{~g}\) of the compound gives \(0.112\) \(\mathrm{g} \mathrm{Eu}_{2} \mathrm{O}_{3}\). Assuming the compound contains only \(\mathrm{C}, \mathrm{H}, \mathrm{O}\), and Eu, determine the formula of the compound formed from the reaction of acetylacetone and the europium salt. (Assume that the compound contains one europium ion.)

Henry Taube, 1983 Nobel Prize winner in chemistry, has studied the mechanisms of the oxidation-reduction reactions of transition metal complexes. In one experiment he and his students studied the following reaction: \(\begin{aligned} \mathrm{Cr}\left(\mathrm{H}_{2} \mathrm{O}\right)_{6}^{2+}(a q) &+\mathrm{Co}\left(\mathrm{NH}_{3}\right)_{5} \mathrm{Cl}^{2+}(a q) \\ & \longrightarrow \mathrm{Cr}(\mathrm{III}) \text { complexes }+\mathrm{Co}(\mathrm{II}) \text { complexes } \end{aligned}\) Chromium(III) and cobalt(III) complexes are substitutionally inert (no exchange of ligands) under conditions of the experiment. Chromium(II) and cobalt(II) complexes can exchange ligands very rapidly. One of the products of the reaction is \(\mathrm{Cr}\left(\mathrm{H}_{2} \mathrm{O}\right)_{5} \mathrm{Cl}^{2+} .\) Is this consistent with the reaction proceeding through formation of \(\left(\mathrm{H}_{2} \mathrm{O}\right)_{5} \mathrm{Cr}-\mathrm{Cl}-\mathrm{Co}\left(\mathrm{NH}_{3}\right)_{5}\) as an intermediate? Explain.

When concentrated hydrochloric acid is added to a red solution containing the \(\mathrm{Co}\left(\mathrm{H}_{2} \mathrm{O}\right)_{6}^{2+}\) complex ion, the solution turns blue as the tetrahedral \(\mathrm{CoCl}_{4}{ }^{2-}\) complex ion forms. Explain this color change.

There are three salts that contain complex ions of chromium and have the molecular formula \(\mathrm{CrCl}_{3} \cdot 6 \mathrm{H}_{2} \mathrm{O}\). Treating \(0.27 \mathrm{~g}\) of the first salt with a strong dehydrating agent resulted in a mass loss of \(0.036 \mathrm{~g}\). Treating \(270 \mathrm{mg}\) of the second salt with the same dehydrating agent resulted in a mass loss of \(18 \mathrm{mg}\). The third salt did not lose any mass when treated with the same dehydrating agent. Addition of excess aqueous silver nitrate to \(100.0\) -mL portions of \(0.100 M\) solutions of each salt resulted in the formation of different masses of silver chloride; one solution yielded \(1430 \mathrm{mg} \mathrm{AgCl}\); another, \(2870 \mathrm{mg} \mathrm{AgCl}\); the third, \(4300 \mathrm{mg} \mathrm{AgCl}\). Two of the salts are green and one is violet. Suggest probable structural formulas for these salts, defending your answer on the basis of the preceding observations. State which salt is most likely to be violet. Would a study of the magnetic properties of the salts be helpful in determining the structural formulas? Explain.

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