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Almost all metals in nature are found as ionic compounds in ores instead of being in the pure state. Why? What must be done to a sample of ore to obtain a metal substance that has desirable properties?

Short Answer

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Metals in nature are found as ionic compounds in ores because they tend to lose electrons and form positively charged ions, combining with non-metals which gain electrons to create negatively charged ions. The formation of these ionic compounds makes ores valuable for metal extraction. To obtain a metal with desirable properties from an ore, a process called metallurgy is performed, involving concentration of the ore, reduction of the metal from its compound state, and refining to remove impurities. The specific methods used depend on the type of metal, its reactivity, and the ore itself.

Step by step solution

01

Understanding Ionic Compounds and Ores

Metals are found as ionic compounds in ores because they have a strong tendency to lose electrons and form positively charged ions (cations). Non-metal elements, on the other hand, have a strong tendency to gain electrons and form negatively charged ions (anions). When metals and non-metals combine, they form ionic compounds due to the transfer of electrons from metals to non-metals. An ore is a naturally occurring solid material from which a metal or valuable mineral can be extracted profitably. Ores contain minerals, which are composed of ionic compounds.
02

Extracting Metals from Ores

To obtain a metal substance with desirable properties from an ore, a process called metallurgy is performed. Metallurgy involves multiple steps, such as: 1. Concentration of the ore: This process aims to remove impurities and gangue (unwanted minerals) from the ore. Methods such as hydraulic washing, froth flotation, and magnetic separation can be used to concentrate the ore. 2. Reduction of the metal: After the concentration, the metal must be reduced from its compound state (like an oxide) to its elemental state. The reduction process can be achieved through chemical reactions or electrolysis. For example, in the case of iron, its oxide is reduced using carbon as a reducing agent. 3. Refining of the metal: After reduction, the metal might still contain some impurities. To obtain a pure sample of metal, the impurities must be removed. Refining methods include liquation, distillation, electrolytic refining, and zone refining. The specific methods used in the extraction process depend on the type of metal, its reactivity, and the type of ore. By undergoing this process, a metal can be extracted from its ore, and its desirable properties can be obtained.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Understanding Ionic Compounds in Ores
Metals are often found in nature as ionic compounds within ores. This occurs because metals tend to lose electrons and form positive ions, while non-metals tend to gain electrons and form negative ions. When these oppositely charged ions attract each other, they form ionic bonds, resulting in ionic compounds. Metals are rarely found in their pure state due to their high reactivity, which leads them to naturally bond with non-metals. Ores are the naturally occurring rocks that contain these metal compounds, often as minerals.

These compounds usually require further processing to isolate the metal component. Since metals form durable ionic bonds in these compounds, it's essential to understand that the extraction process involves breaking these strong bonds to retrieve pure metal. By understanding the interaction of metals and non-metals and their tendency to form ionic compounds, we gain insight into the necessity of processing ores to acquire usable metal forms.
Ore Concentration Techniques
The first step in extracting metals from ores is the concentration process. This step is vital because ores contain various impurities and unwanted minerals, known as gangue, along with the desired metal-containing minerals. Ore concentration techniques help to increase the percentage of the desired metal component within the ore.

Common methods include:
  • Hydraulic Washing: This method uses water to wash away lighter gangue particles, leaving behind heavier metal particles.
  • Froth Flotation: In this technique, ores are mixed with water and frothing agents. When air is bubbled through the mixture, metal particles attach to bubbles and rise to the surface, separating from impurities.
  • Magnetic Separation: Used when either the ore or the impurities have magnetic properties. A magnet is used to attract magnetic particles, leaving non-magnetic gangue behind.
These methods set the stage for the reduction of metals in subsequent steps by enhancing the concentration of the metallic component within the ore.
Methods of Metal Extraction
The extraction of metals involves reducing them from their compound state in ores to their elemental, or pure, state. This is often referred to as the reduction process, a critical part of metallurgy.

Various methods are used to achieve metal reduction depending on the type of ore and metal:
  • Chemical Reduction: This involves using a reducing agent, like carbon, to remove oxygen from metal oxides. For instance, iron ores are typically reduced using carbon in blast furnaces.
  • Electrolysis: For more reactive metals, such as aluminum, electrical energy is used to break down the ionic compounds. The metal ions are reduced to pure metal at the cathode.
Choosing the correct method for extraction is crucial since it affects the efficiency and cost-effectiveness of the process. Each metal and its ore demand a tailored approach considering their chemical and physical properties.
Exploring the Reduction Process
Reduction in metallurgy refers to the process of converting metal ions into a pure metal form through the removal of oxygen or other components. The reduction process often follows ore concentration and sets the stage for further refining if necessary.

During reduction, the ore is often in a compound state, such as oxide or sulphide, and must be transformed into the metal. The right reduction method is selected based on the metal's reactivity and economic considerations.
  • In chemical reduction, reducing agents like carbon can react with metal oxides to produce the metal and release by-products like carbon dioxide.
  • In electrolysis, metals are separated in an electrolytic cell, where electric current causes reduction.
This process is essential to obtain metal in a form that can later be refined for industrial or commercial use, ensuring the metal achieves desired purity and properties.

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Most popular questions from this chapter

Consider aqueous solutions of the following coordination compounds: \(\mathrm{Co}\left(\mathrm{NH}_{3}\right)_{6} \mathrm{I}_{3}, \mathrm{Pt}\left(\mathrm{NH}_{3}\right)_{4} \mathrm{I}_{4}, \mathrm{Na}_{2} \mathrm{Pt} \mathrm{I}_{6}\), and \(\mathrm{Cr}\left(\mathrm{NH}_{3}\right)_{4} \mathrm{I}_{3} .\) If aqueous \(\mathrm{AgNO}_{3}\) is added to separate beakers containing solutions of each coordination compound, how many moles of AgI will precipitate per mole of transition metal present? Assume that each transition metal ion forms an octahedral complex.

Draw all geometrical and linkage isomers of \(\mathrm{Co}\left(\mathrm{NH}_{3}\right)_{4}\left(\mathrm{NO}_{2}\right)_{2}\).

Henry Taube, 1983 Nobel Prize winner in chemistry, has studied the mechanisms of the oxidation-reduction reactions of transition metal complexes. In one experiment he and his students studied the following reaction: \(\begin{aligned} \mathrm{Cr}\left(\mathrm{H}_{2} \mathrm{O}\right)_{6}^{2+}(a q) &+\mathrm{Co}\left(\mathrm{NH}_{3}\right)_{5} \mathrm{Cl}^{2+}(a q) \\ & \longrightarrow \mathrm{Cr}(\mathrm{III}) \text { complexes }+\mathrm{Co}(\mathrm{II}) \text { complexes } \end{aligned}\) Chromium(III) and cobalt(III) complexes are substitutionally inert (no exchange of ligands) under conditions of the experiment. Chromium(II) and cobalt(II) complexes can exchange ligands very rapidly. One of the products of the reaction is \(\mathrm{Cr}\left(\mathrm{H}_{2} \mathrm{O}\right)_{5} \mathrm{Cl}^{2+} .\) Is this consistent with the reaction proceeding through formation of \(\left(\mathrm{H}_{2} \mathrm{O}\right)_{5} \mathrm{Cr}-\mathrm{Cl}-\mathrm{Co}\left(\mathrm{NH}_{3}\right)_{5}\) as an intermediate? Explain.

a. In the absorption spectrum of the complex ion \(\mathrm{Cr}(\mathrm{NCS})_{6}{ }^{3-}\), there is a band corresponding to the absorption of a photon of light with an energy of \(1.75 \times 10^{4} \mathrm{~cm}^{-1}\). Given \(1 \mathrm{~cm}^{-1}=\) \(1.986 \times 10^{-23} \mathrm{~J}\), what is the wavelength of this photon? b. The \(\mathrm{Cr}-\mathrm{N}-\mathrm{C}\) bond angle in \(\mathrm{Cr}(\mathrm{NCS})_{6}{ }^{3-}\) is predicted to be \(180^{\circ}\). What is the hybridization of the \(\mathrm{N}\) atom in the \(\mathrm{NCS}^{-}\) ligand when a Lewis acid-base reaction occurs between \(\mathrm{Cr}^{3+}\) and \(\mathrm{NCS}^{-}\) that would give a \(180^{\circ}\) \(\mathrm{Cr}-\mathrm{N}-\mathrm{C}\) bond angle? \(\mathrm{Cr}(\mathrm{NCS})_{6}{ }^{3-}\) undergoes sub- stitution by ethylenediamine (en) according to the equation $$ \mathrm{Cr}(\mathrm{NCS})_{6}^{3-}+2 \mathrm{en} \longrightarrow \mathrm{Cr}(\mathrm{NCS})_{2}(\mathrm{en})_{2}^{+}+4 \mathrm{NCS}^{-} $$ Does \(\mathrm{Cr}(\mathrm{NCS})_{2}(\mathrm{en})_{2}^{+}\) exhibit geometric isomerism? Does \(\mathrm{Cr}(\mathrm{NCS})_{2}(\mathrm{en})_{2}^{+}\) exhibit optical isomerism?

Carbon monoxide is toxic because it binds more strongly to iron in hemoglobin (Hb) than does \(\mathrm{O}_{2}\). Consider the following reactions and approximate standard free energy changes: $$ \begin{aligned} \mathrm{Hb}+\mathrm{O}_{2} & \longrightarrow \mathrm{HbO}_{2} & \Delta G^{\circ} &=-70 \mathrm{~kJ} \\ \mathrm{Hb}+\mathrm{CO} \longrightarrow \mathrm{HbCO} & \Delta G^{\circ} &=-80 \mathrm{~kJ} \end{aligned} $$ Using these data, estimate the equilibrium constant value at \(25^{\circ} \mathrm{C}\) for the following reaction: $$ \mathrm{HbO}_{2}+\mathrm{CO} \rightleftharpoons \mathrm{HbCO}+\mathrm{O}_{2} $$

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