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How does the oxyacid strength of the halogens vary as the number of oxygens in the formula increases?

Short Answer

Expert verified
As the number of oxygen atoms in the oxyacid formula increases, the oxyacid strength also increases. This is due to the oxygen atoms pulling electron density away from the halogen atom, increasing the strength of the H-X bond and delocalizing the negative charge on the oxygen atoms. For example, with the halogen chlorine, the oxyacid strength increases as follows: HClO (weak), HClO2 (moderate), HClO3 (strong), and HClO4 (very strong).

Step by step solution

01

Define Oxyacid and Oxyacid Strength

An oxyacid is a compound made up of hydrogen, a halogen, and oxygen. It usually has the general formula HXOn, where X is a halogen and n is the number of oxygen atoms. Oxyacid strength refers to the acidity of the compound and its ability to donate a proton (H+). Acidity typically increases as the strength of the H-X bond decreases, allowing for easier dissociation of the H+ ion.
02

Oxyacid Strength Dependence on Electronegativity

Before discussing the effect of oxygen atoms in the formula, it's essential to note that the electronegativity of the halogen atom also impacts the oxyacid strength. When comparing different halogens, a more electronegative halogen will result in a stronger oxyacid.
03

Effect of Oxygen Atoms on Oxyacid Strength

As the number of oxygen atoms in the oxyacid increases, the oxyacid strength also increases. This is because the oxygen atoms pull electron density away from the halogen atom (X), increasing the strength of the H-X bond. More oxygen atoms cause the negative charge on the oxygen atoms to be delocalized, which increases the oxyacid strength.
04

Example with the Halogen Chlorine

Let's consider the halogen chlorine (Cl) and compare four oxyacids with varying oxygen atoms in the formula: HClO, HClO2, HClO3, and HClO4. As we increase the number of oxygen atoms from one to four, the oxyacid strength increases: 1. HClO (Hypochlorous acid): Weak oxyacid 2. HClO2 (Chlorous acid): Moderate oxyacid 3. HClO3 (Chloric acid): Strong oxyacid 4. HClO4 (Perchloric acid): Very strong oxyacid The above example shows that the strength of the oxyacid increases with the increase in the number of oxygen atoms in the formula.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Halogens Oxyacidity
Exploring the nuances of halogens oxyacidity helps us understand why certain oxyacids are stronger than others. Oxyacids consist of hydrogen, a halogen, and oxygen represented by the general formula HXO_n, where 'X' stands for a halogen element, and 'n' denotes the number of oxygen atoms bonded to the halogen.The rule of thumb is the more oxygen atoms present, the greater the oxyacidity. This uptick in acidity can be attributed to the electronegative nature of oxygen. Oxygen atoms draw electron density away from the halogen, which in turn weakens the H-X bond within the molecule. A weaker bond means the hydrogen ion, or proton, can be released more readily into solution, resulting in a stronger acid.

When examining halogens specifically, they are known to form a series of oxyacids, and as the halogen remains constant and the number of oxygens increases, the oxyacidity follows suit. For example, in the set of oxyacids of chlorine—HClO, HClO_2, HClO_3, and HClO_4—each additional oxygen atom escalates the acid strength, making HClO the weakest and HClO_4 the strongest in the series.
Electronegativity and Acidity
Electronegativity plays a pivotal role in determining the strength of an acid. It refers to the ability of an atom to attract electrons towards itself in a bond. The higher the electronegativity of the halogen in an oxyacid, the stronger the acid. This is because electronegative atoms, like chlorine, fluorine, or bromine, will hold onto their shared electrons more tightly.In turn, this increased electronegativity stabilizes the negative charge that arises when the oxyacid ionizes and loses a proton. So, an element like fluorine, which is more electronegative than chlorine, will generally form stronger oxyacids. This effect is layered upon the previous explanation about the influence of the number of oxygen atoms, emphasizing that both the identity of the halogen and the number of oxygen atoms are crucial factors in determining the oxyacid's potency.
Proton Donation and Acidity
Acidity is essentially a measure of a substance's willingness to donate protons (H+ ions) to bases in a solution. According to the Brønsted-Lowry theory of acids and bases, an acid is a proton donor. Thus, the ease with which an oxyacid donates a proton is a direct indicator of its acidity.The bond strength between the hydrogen and the halogen intuitively impacts this ease of proton donation. A weaker H-X bond means that the proton can be more readily donated to the solution, forming the corresponding conjugate base. With each additional oxygen atom, the oxyacid's ability to donate a proton improves due to the increased pulling of electron density away from the halogen—this decreases the bond's strength and enhances acidity. The more easily an oxyacid relinquishes a proton, the more formidable the acid becomes. This is crucial in understanding why acids like perchloric acid (HClO_4) are so potent, as their structural setup greatly favors proton donation.

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Most popular questions from this chapter

Although nitrogen trifluoride \(\left(\mathrm{NF}_{3}\right)\) is a thermally stable compound, nitrogen triiodide \(\left(\mathrm{NI}_{3}\right)\) is known to be a highly explosive material. \(\mathrm{NI}_{3}\) can be synthesized according to the equation $$ \mathrm{BN}(s)+3 \mathrm{IF}(g) \longrightarrow \mathrm{BF}_{3}(g)+\mathrm{NI}_{3}(g) $$ a. What is the enthalpy of formation for \(\mathrm{NI}_{3}(s)\) given the enthalpy of reaction \((-307 \mathrm{~kJ})\) and the enthalpies of formation for \(\mathrm{BN}(s)(-254 \mathrm{~kJ} / \mathrm{mol}), \mathrm{IF}(g)(-96 \mathrm{~kJ} / \mathrm{mol})\), and \(\mathrm{BF}_{3}(g)(-1136 \mathrm{~kJ} / \mathrm{mol})\) ? b. It is reported that when the synthesis of \(\mathrm{NI}_{3}\) is conducted using 4 moles of IF for every 1 mole of \(\mathrm{BN}\), one of the by-products isolated is \(\left[\mathrm{IF}_{2}\right]^{+}\left[\mathrm{BF}_{4}\right]_{-}^{-} .\) What are the molecular geometries of the species in this by-product? What are the hybridizations of the central atoms in each species in the by-product?

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