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Consider the following information: i. The layer of dead skin on our bodies is sufficient to protect us from most \(\alpha\) -particle radiation. ii. Plutonium is an \(\alpha\) -particle producer. iii. The chemistry of \(\mathrm{Pu}^{4+}\) is similar to that of \(\mathrm{Fe}^{3+}\). iv. Pu oxidizes readily to \(\mathrm{Pu}^{4+}\). Why is plutonium one of the most toxic substances known?

Short Answer

Expert verified
Plutonium is one of the most toxic substances known due to its ability to imitate iron in our body after oxidizing to Pu⁴⁺, despite the protective layer of dead skin stopping most α-particle radiation. When ingested, inhaled, or entering through a wound, plutonium can be absorbed by our cells and tissues, where it emits α-particle radiation from within, causing significant cellular and tissue damage. Its chemical similarity to Fe³⁺ and easy oxidation to Pu⁴⁺ increases its likelihood of being absorbed by our body.

Step by step solution

01

Understanding α-particle radiation protection by dead skin

Our body's outer layer of dead skin cells is capable of stopping most α-particle radiation. This means that when α-particle radiation interacts with our skin, it doesn't penetrate and cause significant damage to our tissues and organs.
02

Linking Plutonium with α-particle production

As an α-particle producer, plutonium emits α-particles when it undergoes radioactive decay. According to the given information, our skin should protect us from most α-particle radiation, limiting the potential harm solely by the emission of α-particles.
03

Analyzing the chemical similarity between Pu⁴⁺ and Fe³⁺

It is stated that the chemistry of Pu⁴⁺ is similar to that of Fe³⁺. This suggests that plutonium could imitate the behavior of iron in our bodies, allowing it to be taken up by cells and tissues that otherwise would absorb iron ions (Fe³⁺). This means that if plutonium is ingested, inhaled, or enters the body through a wound, it can potentially replace iron in certain biological pathways.
04

Considering the effect of Pu⁴⁺ oxidation

Plutonium oxidizes readily to Pu⁴⁺. Since Pu⁴⁺ shares chemical similarities with Fe³⁺, this oxidation increases the likelihood of plutonium imitating iron within our body and getting absorbed by our cells.
05

Determining why plutonium is highly toxic

From our analysis, we can conclude that despite the protective layer of dead skin stopping most α-particle radiation, plutonium's high toxicity comes from its ability to imitate iron in our body due to its chemical similarity after oxidizing to Pu⁴⁺. When plutonium enters our body through ingestion, inhalation, or wounds, it can be absorbed by our cells and tissues, emitting α-particle radiation from within, causing significant damage to our cells, tissues, and organs. This characteristic is what makes plutonium one of the most toxic substances known.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Alpha Particle Radiation
Alpha particles are a type of radiation composed of two protons and two neutrons. These particles are emitted from the nucleus of radioactive atoms during radioactive decay. Although alpha particles are relatively heavy and carry a positive charge, their ability to penetrate materials is quite limited.
Most of the substances they encounter can effectively block them, including a simple sheet of paper or the outer layer of dead skin on humans.
While they cannot penetrate the skin to destroy living cells, they pose a significant health risk when they are inhaled, ingested, or enter the body through other means.
  • This is because alpha particles have a high energy transfer (linear energy transfer) to whatever is nearby.
  • Inside the body, this can cause severe damage to living tissues and organs.
It is essential to manage the exposure to alpha-particle emitters, as internal exposure can be extremely dangerous.
Radioactive Decay
Radioactive decay is the process by which an unstable atomic nucleus loses energy by emitting radiation. This can happen in several forms: alpha, beta, or gamma radiation.
In the case of plutonium, it largely undergoes alpha decay, which involves the emission of alpha particles.
During decay, plutonium atoms are transformed into different, more stable elements.
  • This transformation alters the element, and if a plutonium atom becomes lodged inside the body, it will continue to emit radiation as it decays.
  • The ongoing radiation emission can be extremely harmful as it can result in damage at the cellular level, potentially leading to cancers and other health issues over time.
Understanding this process is crucial to both limiting exposure and preventing the harmful effects caused by radioactive materials.
Chemical Mimicry
Chemical mimicry refers to the ability of a chemical substance to act or be recognized as another within biological systems. This can cause particular problems when it comes to highly toxic substances like plutonium being mistaken for essential metals in the body.
Plutonium ions ( ext{Pu}^{4+}) have similar properties to iron ions ( ext{Fe}^{3+}). Because of this similarity, plutonium can mimic iron’s behavior within the body.
This mimicry is problematic because it means plutonium can be absorbed by cells and tissues that typically require iron.
  • By entering these biological pathways, plutonium takes on iron’s role, which disrupts normal cellular processes.
  • It is particularly dangerous as once inside living cells, it can then release its harmful radiation internally.
Understanding plutonium’s mimicry potential is essential in understanding how it interacts with and damages biological systems.
Oxidation States
Oxidation states describe the degree of oxidation of an atom in a compound.
Plutonium can exist in multiple oxidation states, but the transition from different states greatly affects its chemical reactions.
Pu naturally oxidizes to ext{Pu}^{4+}, which is a key stable state that allows for its similarity to iron ( ext{Fe}^{3+}).
  • In this oxidation state, it can interact with molecules and ions in ways that support its absorption in biological systems meant for iron.
  • This raises the risk of plutonium continuous radioactive decay occurring directly within biological tissues.
The oxidative transitions enable plutonium’s toxic mimicry within the body, making it more challenging to isolate and safely manage.

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Most popular questions from this chapter

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The mass ratios of \({ }^{40} \mathrm{Ar}\) to \({ }^{40} \mathrm{~K}\) also can be used to date geologic materials. Potassium-40 decays by two processes: \({ }_{19}^{40} \mathrm{~K}+{ }_{-1}^{0} \mathrm{e} \longrightarrow{ }_{18}^{40} \mathrm{Ar}(10.7 \%) \quad t_{1 / 2}=1.27 \times 10^{9}\) years \({ }_{19}^{40} \mathrm{~K} \longrightarrow{ }_{20}^{40} \mathrm{Ca}+{ }_{-1}^{0} \mathrm{e}(89.3 \%)\) a. Why are \({ }^{40} \mathrm{Ar} /{ }^{40} \mathrm{~K}\) ratios used to date materials rather than \({ }^{40} \mathrm{Ca} /{ }^{40} \mathrm{~K}\) ratios? b. What assumptions must be made using this technique? c. A sedimentary rock has an \({ }^{40} \mathrm{Ar} /{ }^{40} \mathrm{~K}\) ratio of \(0.95\). Calculate the age of the rock. d. How will the measured age of a rock compare to the actual age if some \({ }^{40} \mathrm{Ar}\) escaped from the sample?

To determine the \(K_{\text {sp }}\) value of \(\mathrm{Hg}_{2} \mathrm{I}_{2}\), a chemist obtained a solid sample of \(\mathrm{Hg}_{2} \mathrm{I}_{2}\) in which some of the iodine is present as radioactive \({ }^{131} \mathrm{I}\). The count rate of the \(\mathrm{Hg}_{2} \mathrm{I}_{2}\) sample is \(5.0 \times\) \(10^{11}\) counts per minute per mole of \(\mathrm{I}\). An excess amount of \(\mathrm{Hg}_{2} \mathrm{I}_{2}(s)\) is placed into some water, and the solid is allowed to come to equilibrium with its respective ions. A \(150.0-\mathrm{mL}\) sample of the saturated solution is withdrawn and the radioactivity measured at 33 counts per minute. From this information, calculate the \(K_{\mathrm{sp}}\) value for \(\mathrm{Hg}_{2} \mathrm{I}_{2}\). \(\mathrm{Hg}_{2} \mathrm{I}_{2}(s) \rightleftharpoons \mathrm{Hg}_{2}^{2+}(a q)+2 \mathrm{I}^{-}(a q) \quad K_{\mathrm{sp}}=\left[\mathrm{Hg}_{2}^{2+}\right]\left[\mathrm{I}^{-}\right]^{2}\)

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