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What types of experiments can be carried out to determine whether a reaction is spontaneous? Does spontaneity have any relationship to the final equilibrium position of a reaction? Explain.

Short Answer

Expert verified
To determine the spontaneity of a reaction, we can perform experiments that measure changes in enthalpy (\( \Delta H\)) using calorimetry and determine entropy changes (\( \Delta S\)) by analyzing the number and types of particles involved in the reaction. The relationship between spontaneity and the final equilibrium position of a reaction is mediated by Gibbs free energy (\( \Delta G\)). Spontaneous reactions, characterized by \( \Delta G < 0\), will proceed in the forward direction and favor the formation of products at equilibrium, while non-spontaneous reactions (\( \Delta G > 0\)) will proceed in the reverse direction, favoring reactants.

Step by step solution

01

Understanding Spontaneous Reactions

A spontaneous reaction is one that occurs without any external input, such as the application of heat or pressure. In other words, these reactions occur naturally, driven by the energetics and entropy changes of the system. To determine the spontaneity of a reaction, we can perform experiments to find out the change in Gibbs free energy (\( \Delta G \)) which is related to enthalpy (\( \Delta H \)) and entropy (\( \Delta S \)) by the following equation: \[ \Delta G = \Delta H - T \Delta S\] Where \( T \) is the absolute temperature. If \( \Delta G < 0 \), the reaction is spontaneous, and if \( \Delta G > 0 \), the reaction is non-spontaneous.
02

Experiment 1: Measuring Enthalpy Change

One way to determine if a reaction is spontaneous is by measuring the change in enthalpy (\( \Delta H \)). The enthalpy change can be determined through calorimetry, which measures the heat exchange during a reaction. If the reaction transfers energy to the surroundings by releasing heat (exothermic), it has a negative \( \Delta H \), which would favor spontaneity. A positive \( \Delta H \) (endothermic reaction) does not necessarily mean a non-spontaneous reaction, as other factors like entropy changes may affect spontaneity.
03

Experiment 2: Measuring Entropy Change

Entropy is a measure of disorder or randomness in a system. An increase in entropy (positive \( \Delta S \)) is favored for spontaneity, whereas a decrease in entropy (negative \( \Delta S \)) is not. Entropy changes can be determined by analyzing the number and types of particles involved in a reaction. Additionally, it's possible to find values available for standard molar entropy of compounds in reference tables.
04

Relationship between Spontaneity and Equilibrium Position

The spontaneity of a reaction is directly related to its final equilibrium position via Gibbs free energy. A spontaneous reaction with a negative \( \Delta G \) will proceed in the forward direction until it reaches equilibrium. This means that there will be more products than reactants at equilibrium. On the other hand, a non-spontaneous reaction with a positive \( \Delta G \) will proceed in the reverse direction, meaning that more reactants will remain at equilibrium. It's important to note that just because a reaction is spontaneous doesn't mean it proceeds to completion, as it may reach equilibrium with both reactants and products present. In summary, experiments determining changes in enthalpy and entropy can be conducted to determine the spontaneity of a reaction. Spontaneity is indeed related to the final equilibrium position of a reaction, with spontaneous reactions favoring the formation of products at equilibrium.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Gibbs Free Energy
Gibbs free energy (\( \Delta G \)) is a vital concept for understanding spontaneous reactions. It combines enthalpy (\( \Delta H \)) and entropy (\( \Delta S \)), and is given by the equation:
  • \[ \Delta G = \Delta H - T \Delta S \]
Here, \( T \) stands for temperature in Kelvin. To determine if a chemical reaction will happen spontaneously, calculate \( \Delta G \). A negative value (\( \Delta G < 0 \)) indicates that the reaction can occur on its own.
This means the process can proceed without added energy. Conversely, if \( \Delta G > 0 \), the reaction is not spontaneous.
It's crucial to remember that spontaneity does not indicate the speed of a reaction. It only shows whether or not it can occur unassisted.
Enthalpy Change
Enthalpy change (\( \Delta H \)) measures the heat transferred during a chemical reaction. It tells us whether energy is absorbed or released.
An exothermic reaction releases heat, leading to a negative \( \Delta H \), often favoring spontaneity.
  • When the surroundings receive heat, \( \Delta H \) is negative.
  • An endothermic reaction, absorbing heat, has a positive \( \Delta H \).
Calorimetry experiments can measure the heat change in reactions.
Determining \( \Delta H \) involves measuring the temperature change and knowing the specific heat capacity of the materials involved.
However, it's not just enthalpy determining spontaneity; entropy plays a role too.
Entropy Change
Entropy (\( \Delta S \)) reflects the level of disorder within a chemical reaction system. A positive entropy change suggests increasing disorder, and it often favors spontaneity.
  • Entropy tends to increase when solid reactions produce gas or liquid, or when there’s an increase in the number of particles.
  • To determine \( \Delta S \), look at the reaction's products and reactants.
Reference tables can provide standard molar entropies for substances, valuable for calculating the total entropy change.
These tables simplify the examination of potential entropy effects on spontaneity. An understanding of entropy changes helps predict which reactions might occur naturally.
Equilibrium Position
Equilibrium position in a reaction relates to Gibbs free energy as it decides reactants-to-products balance. If \( \Delta G \) is negative,
  • The forward reaction is favored, leading to more products at equilibrium.
  • A negative \( \Delta G \) means the reaction shoots towards equilibrium naturally.
On the contrary, a positive \( \Delta G \) hints at a reverse reaction direction and more reactants in equilibrium.
It's important to recognize that at equilibrium, \( \Delta G = 0 \), meaning no net change in products and reactants.
In spontaneous reactions, even at equilibrium, products dominate over reactants.
This concept underscores why understanding Gibbs Free Energy is crucial in chemistry.
Calorimetry
Calorimetry is a method used to measure the heat involved in chemical reactions, crucial for finding enthalpy change (\( \Delta H \)).
By helping quantify the energy change, it assists in analyzing spontaneity.
  • Consider a calorimeter as a reaction's heat exchange device.
  • When reactions occur in calorimeters, the temperature shift is measured.
This measure helps to calculate \( \Delta H \) directly if the system’s specific heat is known.
Calorimetry is particularly effective in experiments measuring whether conditions lead to spontaneous reactions.
It makes enthalpy values tangible, giving insights into how heat flows and impacts reaction spontaneity.

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Most popular questions from this chapter

As \(\mathrm{O}_{2}(l)\) is cooled at \(1 \mathrm{~atm}\), it freezes at \(54.5 \mathrm{~K}\) to form solid \(\mathrm{I}\). At a lower temperature, solid I rearranges to solid II, which has a different crystal structure. Thermal measurements show that \(\Delta H\) for the \(\mathrm{I} \rightarrow\) II phase transition is \(-743.1 \mathrm{~J} / \mathrm{mol}\), and \(\Delta S\) for the same transition is \(-17.0 \mathrm{~J} / \mathrm{K} \cdot\) mol. At what temperature are solids I and II in equilibrium?

Given the following data: $$ \begin{aligned} 2 \mathrm{C}_{6} \mathrm{H}_{6}(l)+15 \mathrm{O}_{2}(g) \longrightarrow & 12 \mathrm{CO}_{2}(g)+& 6 \mathrm{H}_{2} \mathrm{O}(l) \\ & \Delta G^{\circ}=-6399 \mathrm{~kJ} \\ \mathrm{C}(s)+\mathrm{O}_{2}(g) \longrightarrow \mathrm{CO}_{2}(g) & \Delta G^{\circ}=-394 \mathrm{~kJ} \\ \mathrm{H}_{2}(g)+\frac{1}{2} \mathrm{O}_{2}(g) \longrightarrow \mathrm{H}_{2} \mathrm{O}(l) & \Delta G^{\circ}=-237 \mathrm{~kJ} \end{aligned} $$ calculate \(\Delta G^{\circ}\) for the reaction $$ 6 \mathrm{C}(s)+3 \mathrm{H}_{2}(g) \longrightarrow \mathrm{C}_{6} \mathrm{H}_{6}(l) $$

Carbon tetrachloride \(\left(\mathrm{CCl}_{4}\right)\) and benzene \(\left(\mathrm{C}_{6} \mathrm{H}_{6}\right)\) form ideal solutions. Consider an equimolar solution of \(\mathrm{CCl}_{4}\) and \(\mathrm{C}_{6} \mathrm{H}_{6}\) at \(25^{\circ} \mathrm{C}\). The vapor above the solution is collected and condensed. Using the following data, determine the composition in mole fraction of the condensed vapor.

At 1 atm, liquid water is heated above \(100^{\circ} \mathrm{C}\). For this process, which of the following choices (i-iv) is correct for \(\Delta S_{\text {surr }}\) ? \(\Delta S\) ? \(\Delta S_{\text {univ }} ?\) Explain each answer. i. greater than zero ii. less than zero iii. equal to zero iv. cannot be determined

Consider the system $$ \mathrm{A}(g) \longrightarrow \mathrm{B}(g) $$ at \(25^{\circ} \mathrm{C}\). a. Assuming that \(G_{\mathrm{A}}^{\circ}=8996 \mathrm{~J} / \mathrm{mol}\) and \(G_{\mathrm{B}}^{\circ}=11,718 \mathrm{~J} / \mathrm{mol}\), calculate the value of the equilibrium constant for this reaction. b. Calculate the equilibrium pressures that result if \(1.00 \mathrm{~mole}\) of \(\mathrm{A}(g)\) at \(1.00\) atm and \(1.00\) mole of \(\mathrm{B}(g)\) at \(1.00 \mathrm{~atm}\) are mixed at \(25^{\circ} \mathrm{C}\). c. Show by calculations that \(\Delta G=0\) at equilibrium.

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