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Would you expect \(\mathrm{Fe}^{3+}\) or \(\mathrm{Fe}^{2+}\) to be the stronger Lewis acid? Explain.

Short Answer

Expert verified
Based on the charge and size considerations, we would expect \(Fe^{3+}\) to be the stronger Lewis acid compared to \(Fe^{2+}\). \(Fe^{3+}\) has a higher positive charge, making it more electron-deficient, and a smaller ionic size, allowing it to more effectively attract and house an electron pair.

Step by step solution

01

Understanding Lewis Acids

A Lewis acid is a species that can accept an electron pair from a Lewis base. In other words, it is an electron-pair acceptor. In general, species with greater electron-deficient centers will act as stronger Lewis acids, as they can more effectively attract and house an electron pair.
02

Comparing the Charges of Fe³⁺ and Fe²⁺

Fe³⁺ has a higher positive charge than Fe²⁺, indicating that it has fewer valence electrons. This higher charge results in a more electron-deficient center, which can make it a stronger electron acceptor.
03

Comparing the Sizes of Fe³⁺ and Fe²⁺

The smaller the size of the metal ion, the more effective it is as a Lewis acid. When the charge increases, the electron cloud shrinks, which leads to a smaller effective size of the cation. Since Fe³⁺ has a higher charge, it should be smaller in size compared to Fe²⁺, making it a better Lewis acid.
04

Conclusion

Based on the charge and size considerations, we would expect Fe³⁺ to be the stronger Lewis acid compared to Fe²⁺. Fe³⁺ has a higher positive charge, making it more electron-deficient, and a smaller ionic size, allowing it to more effectively attract and house an electron pair.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Lewis acids and bases
When delving into the world of chemical reactions, understanding Lewis acids and bases is crucial. A Lewis acid is a chemical species eager to accept an electron pair, thus serving as an electron-pair acceptor. On the other hand, a Lewis base is generous in offering an electron pair, making it an electron-pair donor. This dance of giving and receiving electrons is fundamental to many reactions in chemistry.

Lewis acids are not limited to hydrogen ions; they can be metal ions, molecules, or even compounds with vacant orbitals ready to be filled. Recognizing a Lewis acid involves looking for positive charge centers or atoms with incomplete octets that make them susceptible to accepting electrons. Comprehending this concept helps unravel the mysteries of reaction mechanisms and coordination compounds.
Electron acceptor
In the context of Lewis theory, the electron acceptor plays a pivotal role. It is essentially the 'hand' that reaches out to grab a pair of electrons from a donor—this is the essence of what we identify as a Lewis acid. The strength of an electron acceptor depends on several factors, including its charge, the nature of the atoms involved, and the overall structure of the molecule or ion.

The ability to accept electrons is a defining trait of acid strength, where stronger Lewis acids possess greater affinity for electrons. This characteristic turns them into crucial components in various chemical industries and processes, such as catalysis, and is fundamental in the field of organic chemistry where predicting reaction outcomes is often based on the interaction between Lewis acids and bases.
Ionic charge
Ionic charge is intrinsically linked to the concept of Lewis acid strength. It is simply the difference in the number of protons (positively charged particles) and electrons (negatively charged particles) in an ion. A higher positive charge typically denotes fewer electrons and means an increased desire for electron pairs—picture this as a greater 'hunger' for electrons.

The ionic charge is a simple yet powerful indicator of the Lewis acid's strength. Ions with higher charges are generally stronger acids because they have more substantial electric fields that can attract electron pairs from Lewis bases. This relationship is why we see the comparison of ionic charges when evaluating the relative strength of Lewis acids, with higher-charged ions often leading the pack.
Metal ion size
The size of metal ions is a delicate yet meaningful factor influencing their prowess as Lewis acids. A smaller metal ion size allows for the positive charge to be distributed over a smaller area, intensifying the positive charge's influence on potential electron pairs. It's like having a stronger magnetic pull on the electrons in the vicinity.

Moreover, a smaller-sized ion facilitates closer interactions with the Lewis base, promoting efficient electron pair acceptance. Therefore, smaller metal ions tend to be stronger Lewis acids, as is often seen in the comparison of ions within the same group or period of the periodic table. It's no coincidence that this factor tied in with the charge, paints a comprehensive picture of the ion's acid strength. Smaller, highly charged ions are typically the most eager to accept electron pairs, and thus, are the stronger Lewis acids in chemistry.

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Most popular questions from this chapter

Write the reaction and the corresponding \(K_{\mathrm{b}}\) equilibrium expression for each of the following substances acting as bases in water. a. aniline, \(\mathrm{C}_{6} \mathrm{H}_{5} \mathrm{NH}_{2}\) b. dimethylamine, \(\left(\mathrm{CH}_{3}\right)_{2} \mathrm{NH}\)

Consider \(0.10 M\) solutions of the following compounds: \(\mathrm{AlCl}_{3}\) \(\mathrm{NaCN}, \mathrm{KOH}, \mathrm{CsClO}_{4}\), and NaF. Place these solutions in order of increasing \(\mathrm{pH}\).

Will \(0.10 M\) solutions of the following salts be acidic, basic, of neutral? See Appendix 5 for \(K_{\mathrm{a}}\) values. a. ammonium bicarbonate b. sodium dihydrogen phosphate c. sodium hydrogen phosphate d. ammonium dihydrogen phosphate e. ammonium formate

The \(\mathrm{pH}\) of \(1.0 \times 10^{-8} \mathrm{M}\) hydrochloric acid is not \(8.00\). The correct \(\mathrm{pH}\) can be calculated by considering the relationship between the molarities of the three principal ions in the solution \(\left(\mathrm{H}^{+}, \mathrm{Cl}^{-}\right.\), and \(\left.\mathrm{OH}^{-}\right) .\) These molarities can be calculated from algebraic equations that can be derived from the considerations given below. a. The solution is electrically neutral. b. The hydrochloric acid can be assumed to be \(100 \%\) ionized. c. The product of the molarities of the hydronium ions and the hydroxide ions must equal \(K_{\mathrm{w}}\). Calculate the \(\mathrm{pH}\) of a \(1.0 \times 10^{-8}-\mathrm{M} \mathrm{HCl}\) solution.

Arrange the following \(0.10 \mathrm{M}\) solutions in order of most acidic to most basic. \(\mathrm{KOH}, \mathrm{KNO}_{3}, \mathrm{KCN}, \mathrm{NH}_{4} \mathrm{Cl}, \mathrm{HCl}\)

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