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Define what is meant by unimolecular and bimolecular steps. Why are termolecular steps infrequently seen in chemical reactions?

Short Answer

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A unimolecular step is a single-step chemical reaction involving one reactant molecule in the rate-determining step, such as isomerization or dissociation. A bimolecular step involves the collision of two reactant molecules in the rate-determining step, resulting in an exchange of atoms between them. Termolecular steps are infrequent because they require the simultaneous collision of three reactant molecules with appropriate orientation and energy, which has a significantly lower probability compared to unimolecular or bimolecular steps. Additionally, the reaction is more likely to proceed through simpler steps.

Step by step solution

01

Define Unimolecular Step

A unimolecular step is a single-step chemical reaction in which only one reactant molecule is involved in the rate-determining step. These reactions typically involve isomerization, dissociation, or a rearrangement of atoms within a molecule. An example of a unimolecular reaction is the isomerization of cis-butene to trans-butene.
02

Define Bimolecular Step

A bimolecular step is a single-step chemical reaction in which the rate-determining step involves the collision of two reactant molecules. These reactions typically involve an exchange of atoms between the two reactants, resulting in two new products. An example of a bimolecular reaction is the reaction between hydrogen and iodine molecules to form hydrogen iodide (\(H_2 + I_2 \rightarrow 2HI\)).
03

Explain Infrequency of Termolecular Steps

Termolecular steps are infrequently seen in chemical reactions because they require the simultaneous collision of three reactant molecules with the appropriate orientation and energy. The probability of such collisions occurring is significantly lower than for unimolecular or bimolecular steps, making termolecular steps much less frequent in most chemical reactions. In addition, due to the increased complexity of the termolecular step, it is more likely that the reaction proceeds through a series of unimolecular and bimolecular steps instead.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Unimolecular Reactions
Unimolecular reactions are fascinating events in the world of chemistry, characterized by the transformation of a single molecule. This type of reaction occurs when a compound undergoes a rearrangement within itself. Imagine just one molecule shuffling its atoms around or breaking down into smaller pieces. This can happen due to internal molecular motions. A common scenario is isomerization, where one isomer transforms into another, but without any outside help.

Unimolecular reactions often occur when a molecule absorbs energy and then uses that energy to rearrange its structure. The energy could come from light, heat, or even a catalytic surface. An everyday example is when a compound changes its structure, say from "cis" to "trans" without adding anything else into the mix.
  • Simple: Only one molecule changing on its own.
  • Common types: Isomerization, decomposition, or structural rearrangements.
  • Activation energy needed: Energy intake to trigger the change.
Bimolecular Reactions
Bimolecular reactions bring two reactant molecules together to interact, often through the sharing or swapping of atoms. These reactions are like social events, where two parties meet and exchange valuable parts, resulting in different and often new molecules. This type of reaction is more common than termolecular reactions because it involves just two reactants, increasing the likelihood of collision and interaction.

When two molecules collide with the right orientation and sufficient energy, a bimolecular reaction occurs. A classic example is the formation of water from hydrogen and oxygen molecules. This involves hydrogen molecules reacting with each other, swapping parts, and forming something entirely new.
  • Two molecules meet and react.
  • Collisions must have correct orientation and energy.
  • Examples include many synthesis and decomposition reactions.
Termolecular Reactions
Termolecular reactions are the celestial alignments of chemical reactions, needing three molecules to collide and react with one another simultaneously. They are a rarity due to the improbability of three molecules perfectly colliding at once with the needed energy and orientation. This makes them far less common than unimolecular and bimolecular reactions.

Even though they are rare, termolecular reactions serve an educational purpose; they illustrate the necessity of perfect conditions for certain reactions to happen. Instead of relying on the simultaneous clash of three molecules, such processes are more likely to occur through sequential unimolecular or bimolecular reaction steps.
  • Requires simultaneous collision of three reactant molecules.
  • Less frequent due to low probability of successful collisions.
  • Often broken down into simpler steps for practical occurrences.

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Most popular questions from this chapter

Consider the following initial rate data for the decomposition of compound \(\mathrm{AB}\) to give \(\mathrm{A}\) and \(\mathrm{B}\) : Determine the half-life for the decomposition reaction initially having \(1.00 M \mathrm{AB}\) present.

Define stability from both a kinetic and thermodynamic perspective. Give examples to show the differences in these concepts.

Enzymes are kinetically important for many of the complex reactions necessary for plant and animal life to exist. However, only a tiny amount of any particular enzyme is required for these complex reactions to occur. Explain.

A certain reaction has the following general form: $$ \mathrm{aA} \longrightarrow \mathrm{bB} $$ At a particular temperature and \([\mathrm{A}]_{0}=2.80 \times 10^{-3} M\), concentration versus time data were collected for this reaction, and a plot of \(1 /[\mathrm{A}]\) versus time resulted in a straight line with a slope value of \(+3.60 \times 10^{-2} \mathrm{~L} / \mathrm{mol} \cdot \mathrm{s}\) a. Determine the rate law, the integrated rate law, and the value of the rate constant for this reaction. b. Calculate the half-life for this reaction. c. How much time is required for the concentration of \(\mathrm{A}\) to decrease to \(7.00 \times 10^{-4} M ?\)

Chemists commonly use a rule of thumb that an increase of \(10 \mathrm{~K}\) in temperature doubles the rate of a reaction. What must the activation energy be for this statement to be true for a temperature increase from 25 to \(35^{\circ} \mathrm{C}\) ?

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