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In the hybrid orbital model, compare and contrast \(\sigma\) bonds with \(\pi\) bonds. What orbitals form the \(\sigma\) bonds and what orbitals form the \(\pi\) bonds? Assume the \(z\) -axis is the internuclear axis

Short Answer

Expert verified
In the hybrid orbital model, sigma (σ) bonds are formed by the direct overlap of orbitals along the internuclear axis (z-axis), such as s-s, s-p, or p-p overlaps. On the other hand, pi (π) bonds are formed by the sideways overlap of parallel p orbitals (either p_x or p_y), resulting in electron density above and below the internuclear axis. Sigma bonds are generally stronger and allow for free rotation of bonded atoms, while π bonds are weaker and restrict rotation due to the parallel orientation of overlapping orbitals. Additionally, σ bonds have symmetrical electron density distribution along the internuclear axis, while π bonds have electron density distributed above and below the internuclear axis.

Step by step solution

01

Definition of sigma (σ) and pi (π) bonds

Sigma (σ) bonds are formed by the direct overlap of orbitals along the internuclear axis between two atoms. Pi (π) bonds are formed by the sideways overlap of adjacent parallel orbitals, resulting in electron density above and below the axis connecting the two atoms.
02

Sigma (σ) bond orbitals

Sigma (σ) bonds can be formed by the combination of various orbitals, such as s-s, s-p, and p-p overlapping. When a σ bond is formed by the direct overlap of orbitals along the internuclear axis, the orbitals involved can be one of the following: 1. s-s overlap: a σ bond formed by the overlap of two s orbitals (one from each atom). 2. s-p overlap: a σ bond formed by the overlap of an s orbital of one atom and a p orbital of the other atom. 3. p-p overlap: a σ bond formed by the overlap of two p orbitals (one from each atom) along the internuclear axis (z-axis in this case).
03

Pi (π) bond orbitals

Pi (π) bonds are formed by the sideways overlap of parallel p orbitals. When a π bond is formed above and below the internuclear axis (z-axis), only the following overlap is possible: 1. p-p overlap: a π bond formed by the overlap of two p orbitals lying parallel to the internuclear axis. These can be either p_x or p_y orbitals, but not p_z, as it is aligned along the z-axis (internuclear axis).
04

Comparing σ and π bonds

1. Formation: Sigma bonds are formed by the direct overlap of orbitals along the internuclear axis, while π bonds are formed by the parallel overlap of p orbitals above and below the internuclear axis. 2. Strength: Sigma bonds are generally stronger and more stable than π bonds due to the greater degree of orbital overlap. 3. Rotation: Sigma bonds allow for free rotation of the bonded atoms around the internuclear axis, while π bonds restrict rotation due to the parallel orientation of the overlapping orbitals. 4. Electron density distribution: Sigma bonds have symmetrical electron density distribution along the internuclear axis, while π bonds have electron density distributed above and below the internuclear axis.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Sigma Bonds
Sigma (\(\sigma\)) bonds are the primary bonds formed between two atoms and play a crucial role in maintaining molecular structure. These bonds occur when orbitals overlap directly along the internuclear axis, which is the imaginary line connecting the nuclei of the two bonded atoms. The orbitals that contribute to \(\sigma\) bonds can include:
  • s-s overlap: two s orbitals combine, which is common in simple molecules like hydrogen.
  • s-p overlap: an s orbital from one atom interacts with a p orbital from another atom.
  • p-p overlap: two p orbitals from each atom overlap directly along the z-axis.

These direct overlaps allow for a robust connection, bestowing \(\sigma\) bonds with high stability and strength. Consequently, they permit the free rotation of bonded atoms around the internuclear axis.
Pi Bonds
Pi (\(\pi\)) bonds form when orbitals overlap sideways and create electron clouds above and below the internuclear axis. Unlike \(\sigma\) bonds, \(\pi\) bonds involve the overlap of p orbitals that are oriented parallel to each other. Therefore, the potential overlaps are between p orbitals such as \(p_x\) or \(p_y\) that lie perpendicular to the axis.
  • p-p overlap is the typical scenario for \(\pi\) bonds, requiring these orbitals to be aligned parallel to the internuclear axis.

Pi bonds are generally less robust than \(\sigma\) bonds due to the reduced degree of overlap. Additionally, they don't allow free rotation because twisting the bonded atoms would disrupt the orbital interaction. Consequently, molecules with \(\pi\) bonds are often more rigid in structure.
Orbital Overlap
Understanding orbital overlap is pivotal in grasping how chemical bonds form and why they have certain properties. Orbital overlap refers to the way in which atomic orbitals from two different atoms come together to share electrons. The nature of this overlap determines the type and strength of the bond.
  • Direct overlap leads to the formation of \(\sigma\) bonds. As the orbitals meet head-on along the internuclear axis, it maximizes the electron density directly between the centers of the bonding atoms.
  • Sideways overlap results in \(\pi\) bonds, where orbitals align parallel to each other and form regions of electron density above and below the internuclear axis.

The efficiency of the overlap dictates bond strength—the greater the overlap, the stronger the bond. This is why \(\sigma\) bonds, with their significant head-on overlap, are usually stronger than \(\pi\) bonds.
Electron Density Distribution
The electron density distribution in a bond reveals where electrons are most likely to be found. It provides insights into bond strength, polarity, and geometry.
  • In \(\sigma\) bonds, electron density is largely concentrated along the internuclear axis. This symmetrical distribution contributes to the strength and flexibility of \(\sigma\) bonds, allowing atoms to rotate freely around the axis.
  • In \(\pi\) bonds, electron density exists in lobes located above and below the internuclear axis. This distribution is less symmetrical and limits rotational freedom because turning the bonded atoms could disrupt the electron clouds.

The understanding of electron density distribution helps chemists predict the shape and characteristics of molecules, influencing how they interact with other substances in reactions.

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Most popular questions from this chapter

Cyanamide \(\left(\mathrm{H}_{2} \mathrm{NCN}\right)\), an important industrial chemical, is produced by the following steps: $$ \begin{aligned} \mathrm{CaC}_{2}+\mathrm{N}_{2} & \longrightarrow \mathrm{CaNCN}+\mathrm{C} \\\ \mathrm{CaNCN} & \stackrel{\text { Acid }}{\longrightarrow} \mathrm{H}_{2} \mathrm{NCN} \end{aligned} $$ Cyanamid Calcium cyanamide (CaNCN) is used as a direct-application fertilizer, weed killer, and cotton defoliant. It is also used to make cyanamide, dicyandiamide, and melamine plastics: a. Write Lewis structures for \(\mathrm{NCN}^{2-}, \mathrm{H}_{2} \mathrm{NCN}\), dicyandiamide, and melamine, including resonance structures where appropriate. b. Give the hybridization of the \(\mathrm{C}\) and \(\mathrm{N}\) atoms in each species. c. How many \(\sigma\) bonds and how many \(\pi\) bonds are in each species? d. Is the ring in melamine planar? e. There are three different \(\mathrm{C}-\mathrm{N}\) bond distances in dicyandiamide, \(\mathrm{NCNC}\left(\mathrm{NH}_{2}\right)_{2}\), and the molecule is nonlinear. Of all the resonance structures you drew for this molecule, predict which should be the most important.

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Arrange the following from lowest to highest ionization energy: \(\mathrm{O}, \mathrm{O}_{2}, \mathrm{O}_{2}^{-}, \mathrm{O}_{2}^{+} .\) Explain your answer.

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