Warning: foreach() argument must be of type array|object, bool given in /var/www/html/web/app/themes/studypress-core-theme/template-parts/header/mobile-offcanvas.php on line 20

Combustion reactions of fossil fuels provide most of the energy needs of the world. Why are combustion reactions of fossil fuels so exothermic?

Short Answer

Expert verified
Combustion reactions of fossil fuels are highly exothermic due to the energy difference between the bonds formed and the bonds broken during the reaction. Fossil fuels contain strong C-H and C-C bonds in their hydrocarbon makeup, which break during combustion, releasing energy. The reaction forms new C=O bonds in CO₂ and H-O bonds in H₂O, releasing even more energy. The net energy release in the form of heat is significant, making these reactions particularly useful for providing the world's energy needs.

Step by step solution

01

Understand Exothermic Reactions

An exothermic reaction is a chemical reaction that releases energy in the form of heat. It occurs when the energy required to break the bonds in the reactants is less than the energy released upon the formation of new bonds in the products. The difference between these energies results in the release of heat.
02

Fossil Fuels Composition

Fossil fuels, such as coal, oil, and natural gas, are composed mainly of hydrocarbons (molecules containing hydrogen and carbon atoms) and other carbon-based compounds. These hydrocarbons, like methane (CH4) and octane (C8H18), are rich in energy due to the strong carbon-hydrogen (C-H) and carbon-carbon (C-C) bonds present in the molecules.
03

Combustion Reactions

In a combustion reaction, a hydrocarbon reacts with oxygen to produce carbon dioxide (CO2), water (H2O) and heat. The general equation for a combustion reaction can be represented as: \[ C_xH_y + O_2 \rightarrow CO_2 + H_2O + \text{Heat} \]
04

Breaking and Forming Bonds

During the combustion of fossil fuels, C-H and C-C bonds in hydrocarbons are broken, and new bonds—carbon-oxygen (C=O) bonds in CO2 and hydrogen-oxygen (H-O) bonds in H2O—are formed. The energy required to break the C-H and C-C bonds is less than the energy released during the formation of C=O and H-O bonds.
05

Highly Exothermic Reaction

The difference between the energy required to break the original bonds in the hydrocarbons and the energy released upon the formation of new bonds in CO2 and H2O accounts for the highly exothermic nature of combustion reactions. The large amount of heat released during these reactions makes them particularly useful for providing the significant amount of energy required to meet the world's energy needs.

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with Vaia!

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

List all the possible bonds that can occur between the elements \(\mathrm{P}, \mathrm{Cs}, \mathrm{O}\), and \(\mathrm{H}\). Predict the type of bond (ionic, covalent, or polar covalent) one would expect to form for each bond.

The second electron affinity values for both oxygen and sulfur are unfavorable (endothermic). Explain.

For each of the following, write an equation that corresponds to the energy given. a. lattice energy of \(\mathrm{NaCl}\) b. lattice energy of \(\mathrm{NH}_{4} \mathrm{Br}\) c. lattice energy of \(\mathrm{MgS}\) d. \(\mathrm{O}=\mathrm{O}\) double bond energy beginning with \(\mathrm{O}_{2}(g)\) as a reactant

Hydrogen has an electronegativity value between boron and carbon and identical to phosphorus. With this in mind, rank the following bonds in order of decreasing polarity: \(\mathrm{P}-\mathrm{H}, \mathrm{O}-\mathrm{H}\), \(\mathrm{N}-\mathrm{H}, \mathrm{F}-\mathrm{H}, \mathrm{C}-\mathrm{H}\)

The alkali metal ions are very important for the proper functioning of biologic systems, such as nerves and muscles, and \(\mathrm{Na}^{+}\) and \(\mathrm{K}^{+}\) ions are present in all body cells and fluids. In human blood plasma, the concentrations are $$ \left[\mathrm{Na}^{+}\right] \approx 0.15 M \text { and }\left[\mathrm{K}^{+}\right] \approx 0.005 M $$ For the fluids inside the cells, the concentrations are reversed: $$ \left[\mathrm{Na}^{+}\right] \approx 0.005 M \text { and }\left[\mathrm{K}^{+}\right] \approx 0.16 M $$ Since the concentrations are so different inside and outside the cells, an elaborate mechanism is needed to transport \(\mathrm{Na}^{+}\) and \(\mathrm{K}^{+}\) ions through the cell membranes. What are the ground-state electron configurations for \(\mathrm{Na}^{+}\) and \(\mathrm{K}^{+}\) ? Which ion is smaller in size? Counterions also must be present in blood plasma and inside intracellular fluid. Assume the counterion present to balance the positive charge of \(\mathrm{Na}^{+}\) and \(\mathrm{K}^{+}\) is \(\mathrm{Cl}^{-}\). What is the ground-state electron configuration for \(\mathrm{Cl}^{-}\) ? Rank these three ions in order of increasing size.

See all solutions

Recommended explanations on Chemistry Textbooks

View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.

Sign-up for free