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What do each of the following sets of compounds/ions have in common with each other? a. \(\mathrm{SO}_{3}, \mathrm{NO}_{3}^{-}, \mathrm{CO}_{3}^{2-}\) b. \(\mathrm{O}_{3}, \mathrm{SO}_{2}, \mathrm{NO}_{2}^{-}\)

Short Answer

Expert verified
The common property among the compounds/ions in set a (\(\mathrm{SO}_{3}, \mathrm{NO}_{3}^{-}, \mathrm{CO}_{3}^{2-}\)) is that they are all Trigonal Planar molecules and ions with three Oxygen atoms surrounding the central atom with double or coordinate covalent bonds. In set b (\(\mathrm{O}_{3}, \mathrm{SO}_{2}, \mathrm{NO}_{2}^{-}\)), the common property is that they are all Bent (V-shaped) molecules and ions, featuring two atoms of either Oxygen or Sulfur surrounding the central atom with double and single bonds or two double bonds.

Step by step solution

01

Observation of Bonding Patterns

From the given compounds/ions, we notice that all of them have three atoms surrounding the central atom. Also, we can see that they share Oxygen atoms. Now, let's look for any common bonding pattern.
02

Valence Electrons

In all three compounds/ions, the three Oxygen atoms are bonded to the central atom (Sulfur, Nitrogen, or Carbon) using double bonds or coordinate covalent bonds (in the case of the negative ions). The double bonds are formed due to the sharing of a pair of valence electrons by both the central atom and the Oxygen atom.
03

Common Property

After analyzing the valence electrons and bonding patterns in these compounds/ions, we can conclude that the common property among these is that they are all Trigonal Planar molecules and ions, featuring three Oxygen atoms surrounding the central atom with double or coordinate covalent bonds. #b. Identify the common property of \(\mathrm{O}_{3}, \mathrm{SO}_{2}, \mathrm{NO}_{2}^{-}\)#
04

Observation of Bonding Patterns

In this set of compounds/ions, we notice that all of these species have two atoms connected to the central atom. One is an Oxygen atom, and another can be either Oxygen or Sulfur. Let's investigate the bonding patterns.
05

Valence Electrons

All three compounds/ions have a central atom (Oxygen, Sulfur, or Nitrogen) sharing valence electrons with the other atoms. In the case of \(\mathrm{O_3}\) (Ozone) and \(\mathrm{NO}_{2}^{-}\), the central atom is linked by double bonds and single bonds to the other atoms, while \(\mathrm{SO}_{2}\) has two double bonds between the central Sulfur atom and the two Oxygen atoms.
06

Common Property

After analyzing the bonding patterns and valence electrons in these compounds/ions, we can conclude that the common property among these is that they are all Bent (V-shaped) molecules and ions, featuring two atoms of either Oxygen or Sulfur surrounding the central atom with double and single bonds or two double bonds.

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Most popular questions from this chapter

The space shuttle orbiter utilizes the oxidation of methyl hydrazine by dinitrogen tetroxide for propulsion: \(5 \mathrm{~N}_{2} \mathrm{O}_{4}(g)+4 \mathrm{~N}_{2} \mathrm{H}_{3} \mathrm{CH}_{3}(g) \longrightarrow 12 \mathrm{H}_{2} \mathrm{O}(g)+9 \mathrm{~N}_{2}(g)+4 \mathrm{CO}_{2}(g)\) Use bond energies to estimate \(\Delta H\) for this reaction. The structures for the reactants are:

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Identify the five compounds of \(\mathrm{H}, \mathrm{N}\), and \(\mathrm{O}\) described below. For each compound, write a Lewis structure that is consistent with the information given. a. All the compounds are electrolytes, although not all of them are strong electrolytes. Compounds \(\mathrm{C}\) and \(\mathrm{D}\) are ionic and compound \(\mathrm{B}\) is covalent. b. Nitrogen occurs in its highest possible oxidation state in compounds \(\mathrm{A}\) and \(\mathrm{C}\); nitrogen occurs in its lowest possible oxidation state in compounds \(\mathrm{C}, \mathrm{D}\), and \(\mathrm{E}\). The formal charge on both nitrogens in compound \(\mathrm{C}\) is \(+1\); the formal charge on the only nitrogen in compound \(\mathrm{B}\) is \(0 .\) c. Compounds A and E exist in solution. Both solutions give off gases. Commercially available concentrated solutions of compound \(\mathrm{A}\) are normally \(16 M .\) The commercial, concentrated solution of compound \(\mathrm{E}\) is \(15 M\). d. Commercial solutions of compound \(\mathrm{E}\) are labeled with a misnomer that implies that a binary, gaseous compound of nitrogen and hydrogen has reacted with water to produce ammonium ions and hydroxide ions. Actually, this reaction occurs to only a slight extent. e. Compound \(\mathrm{D}\) is \(43.7 \% \mathrm{~N}\) and \(50.0 \% \mathrm{O}\) by mass. If compound D were a gas at STP, it would have a density of \(2.86 \mathrm{~g} / \mathrm{L}\). f. A formula unit of compound \(\mathrm{C}\) has one more oxygen than a formula unit of compound D. Compounds \(\mathrm{C}\) and \(\mathrm{A}\) have one ion in common when compound \(\mathrm{A}\) is acting as a strong electrolyte. g. Solutions of compound \(\mathrm{C}\) are weakly acidic; solutions of compound \(\mathrm{A}\) are strongly acidic; solutions of compounds \(\mathrm{B}\) and \(\mathrm{E}\) are basic. The titration of \(0.726 \mathrm{~g}\) compound \(\mathrm{B}\) requires \(21.98 \mathrm{~mL}\) of \(1.000 M \mathrm{HCl}\) for complete neutralization.

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