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What mass of \(\mathrm{NaOH}\) is contained in \(250.0 \mathrm{~mL}\) of a \(0.400 \mathrm{M}\) sodium hydroxide solution?

Short Answer

Expert verified
The mass of \(\mathrm{NaOH}\) contained in \(250.0 \mathrm{~mL}\) of a \(0.400\mathrm{M}\) sodium hydroxide solution is 4.00 g.

Step by step solution

01

Convert mL of solution to L

To convert from mL to L, we'll divide the volume of the solution (250.0 mL) by 1000 since there are 1000 mL in 1 L: Volume in L = 250.0 mL ÷ 1000 = 0.250 L
02

Calculate the number of moles of NaOH

To find the number of moles of NaOH, we'll multiply the volume of the solution (in L) by the given concentration: Number of moles of NaOH = (volume of solution in L) × (concentration) Number of moles of NaOH = (0.250 L) × (0.400 mol/L) = 0.100 mol
03

Find the molar mass of NaOH

To calculate the mass of NaOH, we need the molar mass of the solute. The formula for sodium hydroxide is NaOH, and we can find the molar mass using the periodic table: Molar mass of Na (sodium) = 22.99 g/mol Molar mass of O (oxygen) = 16.00 g/mol Molar mass of H (hydrogen) = 1.008 g/mol Molar mass of NaOH = (22.99 + 16.00 + 1.008) g/mol = 40.00 g/mol
04

Calculate the mass of NaOH

Now we can calculate the mass of NaOH by multiplying the number of moles with the molar mass: mass of NaOH = (number of moles of NaOH) × (molar mass of NaOH) mass of NaOH = (0.100 mol) × (40.00 g/mol) = 4.00 g The mass of \(\mathrm{NaOH}\) contained in \(250.0 \mathrm{~mL}\) of a \(0.400\mathrm{M}\) sodium hydroxide solution is 4.00 g.

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