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According to the law of conservation of mass, mass cannot be gained or destroyed in a chemical reaction. Why can't you simply add the masses of two reactants to determine the total mass of product?

Short Answer

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The law of conservation of mass states that mass cannot be created or destroyed in a chemical reaction, meaning the total mass of reactants should equal the total mass of products. Simply adding the masses of two reactants to determine the total mass of products is incorrect because it does not consider the stoichiometry of the reaction, which dictates the proportions of reactants used and products formed. To determine the correct mass of products, we must follow a series of steps involving the balanced chemical equation, molar conversions, identifying limiting reactants, and using stoichiometric coefficients to relate reactants and products. This approach ensures mass conservation in a chemical reaction.

Step by step solution

01

Introduction to the law of conservation of mass

The law of conservation of mass states that mass cannot be created or destroyed in a chemical reaction. In other words, the total mass of the reactants in a chemical reaction should be equal to the total mass of the products.
02

Understanding chemical reactions

In a chemical reaction, reactants are converted into products through the rearrangement of atoms, which involves breaking the existing bonds and forming new ones. It is essential to understand that the mass of atoms involved in a chemical reaction does not change; only the way they are connected or bonded changes.
03

Mismatch in mass while adding reactants

When we attempt to simply add the masses of the reactants to determine the total mass of products, we often find that there is a mismatch in the mass. This is because we are not taking into account the stoichiometry of the reaction, which is the balanced chemical equation that shows in what proportions the reactants are to be used exactly and how many products are formed. The stoichiometric coefficients in the balanced chemical equation play an essential role in how to obtain the correct mass of the products by relating the amount of reactants to the amount of products.
04

Stoichiometry and conservation of mass

By taking into account the stoichiometry of the reaction, we can properly understand the conservation of mass. To calculate the mass of the products, we need to follow these steps: 1. Write the balanced chemical equation for the reaction. 2. Convert the masses of the reactants into moles by dividing the masses by their respective molar masses. 3. Determine the limiting reactant (if there is one) by comparing the mole ratios of the reactants to their stoichiometric coefficients. 4. Calculate the moles of products formed by using the stoichiometric coefficients and the moles of limiting reactant. 5. Convert the moles of products into mass by multiplying them by their respective molar masses. Following these steps can help us understand the relationship between the masses of reactants and products and how they are related by the stoichiometry of the reaction. This will correctly show that the mass is conserved during a chemical reaction.

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Most popular questions from this chapter

When aluminum metal is heated with an element from Group \(6 \mathrm{~A}\) of the periodic table, an ionic compound forms. When the experiment is performed with an unknown Group \(6 \mathrm{~A}\) element, the product is \(18.56 \%\) Al by mass. What is the formula of the compound?

In the production of printed circuit boards for the electronics industry, a \(0.60-\mathrm{mm}\) layer of copper is laminated onto an insulating plastic board. Next, a circuit pattern made of a chemically resistant polymer is printed on the board. The unwanted copper is removed by chemical etching, and the protective polymer is finally removed by solvents. One etching reaction is \(\mathrm{Cu}\left(\mathrm{NH}_{3}\right)_{4} \mathrm{Cl}_{2}(a q)+4 \mathrm{NH}_{3}(a q)+\mathrm{Cu}(s) \longrightarrow 2 \mathrm{Cu}\left(\mathrm{NH}_{3}\right)_{4} \mathrm{Cl}(a q)\) A plant needs to manufacture 10,000 printed circuit boards, each \(8.0 \times 16.0 \mathrm{~cm}\) in area. An average of \(80 . \%\) of the copper is remoyed from each board (density of copper \(=8.96 \mathrm{~g} / \mathrm{cm}^{3}\) ). What masses of \(\mathrm{Cu}\left(\mathrm{NH}_{3}\right)_{4} \mathrm{Cl}_{2}\) and \(\mathrm{NH}_{3}\) are needed to do this? Assume \(100 \%\) yield.

An iron ore sample contains \(\mathrm{Fe}_{2} \mathrm{O}_{3}\) plus other impurities. A 752 g sample of impure iron ore is heated with excess carbon, producing \(453 \mathrm{~g}\) of pure iron by the following reaction: $$ \mathrm{Fe}_{2} \mathrm{O}_{3}(s)+3 \mathrm{C}(s) \longrightarrow 2 \mathrm{Fe}(s)+3 \mathrm{CO}(\mathrm{g}) $$ What is the mass percent of \(\mathrm{Fe}_{2} \mathrm{O}_{3}\) in the impure iron ore sample? Assume that \(\mathrm{Fe}_{2} \mathrm{O}_{3}\) is the only source of iron and that the reaction is \(100 \%\) efficient.

In 1987 the first substance to act as a superconductor at a temperature above that of liquid nitrogen \((77 \mathrm{~K})\) was discovered. The approximate formula of this substance is \(\mathrm{YBa}_{2} \mathrm{Cu}_{3} \mathrm{O}_{7} .\) Calculate the percent composition by mass of this material.

A common demonstration in chemistry courses involves adding a tiny speck of manganese(IV) oxide to a concentrated hydrogen peroxide \(\left(\mathrm{H}_{2} \mathrm{O}_{2}\right)\) solution. Hydrogen peroxide decomposes quite spectacularly under these conditions to produce oxygen gas and steam (water vapor). Manganese(IV) oxide is a catalyst for the decomposition of hydrogen peroxide and is not consumed in the reaction. Write the balanced equation for the decomposition reaction of hydrogen peroxide.

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