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Anabolic steroids are performance enhancement drugs whose use has been banned from most major sporting activities. One anabolic steroid is fluoxymesterone \(\left(\mathrm{C}_{20} \mathrm{H}_{29} \mathrm{FO}_{3}\right) .\) Calculate the percent composition by mass of fluoxymesterone.

Short Answer

Expert verified
The percent composition by mass of fluoxymesterone (C20H29FO3) is approximately 71.38% carbon, 8.70% hydrogen, 5.65% fluorine, and 14.27% oxygen.

Step by step solution

01

Find the molar mass of fluoxymesterone

To determine the molar mass of fluoxymesterone (C20H29FO3), we need to find the total mass of all the atoms in one mole of the compound. We can do this by multiplying the number of each atom by its molar mass: - For carbon (C), the molar mass is 12.01 g/mol. - For hydrogen (H), the molar mass is 1.01 g/mol. - For fluorine (F), the molar mass is 19 g/mol. - For oxygen (O), the molar mass is 16 g/mol. Molar mass of fluoxymesterone: = (20 * 12.01) + (29 * 1.01) + (1 * 19) + (3 * 16) = 240.2 + 29.29 + 19 + 48 = 336.49 g/mol
02

Find the individual masses of elements in fluoxymesterone

To find the mass of each element in fluoxymesterone, we multiply the number of atoms of the element with their respective molar mass. Mass of carbon (C) = 20 * 12.01 g/mol = 240.2 g/mol Mass of hydrogen (H) = 29 * 1.01 g/mol = 29.29 g/mol Mass of fluorine (F) = 1 * 19 g/mol = 19 g/mol Mass of oxygen (O) = 3 * 16 g/mol = 48 g/mol
03

Calculate the percent composition by mass of each element

To find the percent composition by mass of each element in fluoxymesterone, we divide the mass of each element by the molar mass of the compound and multiply by 100. Percent composition of carbon (C) = (240.2 g/mol) / (336.49 g/mol) * 100 = 71.38% Percent composition of hydrogen (H) = (29.29 g/mol) / (336.49 g/mol) * 100 = 8.70% Percent composition of fluorine (F) = (19 g/mol) / (336.49 g/mol) * 100 = 5.65% Percent composition of oxygen (O) = (48 g/mol) / (336.49 g/mol) * 100 = 14.27% Thus, the percent composition by mass of fluoxymesterone (C20H29FO3) is approximately 71.38% carbon, 8.70% hydrogen, 5.65% fluorine, and 14.27% oxygen.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Fluoxymesterone
Fluoxymesterone is a type of anabolic steroid known for its ability to enhance muscle growth and performance. It is recognized by its chemical formula \(\mathrm{C}_{20} \mathrm{H}_{29} \mathrm{FO}_{3}\) and is often used in the context of sports and bodybuilding, although its use is banned in many professional and competitive sports due to its performance-enhancing effects.
The compound’s chemical formula reveals its structure, indicating it contains 20 carbon atoms, 29 hydrogen atoms, 1 fluorine atom, and 3 oxygen atoms.
These components together contribute to the total molar mass and the biological activity associated with the compound. Understanding its compositional structure is crucial for grasping how such steroids interact within the body, their metabolism, and the effects they prompt at a cellular level.
Molar Mass Calculation
Calculating the molar mass of a compound like fluoxymesterone involves adding up the atomic masses of each element within its chemical formula.
Each atom’s contribution to the molar mass is determined by multiplying the number of atoms by their respective atomic masses.
  • Carbon (C) contributes 12.01 g/mol, and with 20 atoms, this is 240.2 g/mol.
  • Hydrogen (H) at 1.01 g/mol with 29 atoms contributes 29.29 g/mol.
  • Fluorine (F), at 19 g/mol, accounts for 19 g/mol with its single atom.
  • Oxygen (O) at 16 g/mol with 3 atoms contributes 48 g/mol.
By summing these individual contributions, the total molar mass of fluoxymesterone is calculated to be 336.49 g/mol.
Understanding how to calculate molar mass is fundamental in chemistry, as it helps us assess substance quantities for reactions and understand compound interactions.
Chemical Formula Interpretation
Chemical formula interpretation involves decoding the subscripts and elemental symbols to understand the makeup of a compound.
In fluoxymesterone’s formula, \(\mathrm{C}_{20} \mathrm{H}_{29} \mathrm{FO}_{3}\), the letters represent elements:
  • \mathrm{C} stands for Carbon
  • \mathrm{H} stands for Hydrogen
  • \mathrm{F} stands for Fluorine
  • \mathrm{O} stands for Oxygen
The numbers, known as subscripts, inform us of the number of atoms of each element present in one molecule of the compound.
This analysis is essential for identifying the relationships between elements and for conducting precise scientific calculations, like determining percent composition by mass or engaging in chemical reactions, where knowing the exact composition is crucial.
Interpreting these formulas correctly helps in predicting the properties and potential uses of the compound.

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Most popular questions from this chapter

A compound containing only sulfur and nitrogen is \(69.6 \% \mathrm{~S}\) by mass; the molar mass is \(184 \mathrm{~g} / \mathrm{mol}\). What are the empirical and molecular formulas of the compound?

A compound contains only carbon, hydrogen, nitrogen, and oxygen. Combustion of \(0.157 \mathrm{~g}\) of the compound produced \(0.213 \mathrm{~g}\) \(\mathrm{CO}\), and \(0.0310 \mathrm{~g} \mathrm{H}_{2} \mathrm{O} .\) In another experiment, it is found that \(0.103 \mathrm{~g}\) of the compound produces \(0.0230 \mathrm{~g} \mathrm{NH}_{3} .\) What is the empirical formula of the compound? Hint: Combustion involves reacting with excess \(\mathrm{O}_{2}\). Assume that all the carbon ends up in \(\mathrm{CO}_{2}\) and all the hydrogen ends up in \(\mathrm{H}_{2} \mathrm{O}\). Also assume that all the nitrogen ends up in the \(\mathrm{NH}_{3}\) in the second experiment.

The space shuttle environmental control system handles excess \(\mathrm{CO}_{2}\) (which the astronauts breathe out; it is \(4.0 \%\) by mass of exhaled air) by reacting it with lithium hydroxide, LiOH, pellets to form lithium carbonate, \(\mathrm{Li}_{2} \mathrm{CO}_{3}\), and water. If there are 7 astronauts on board the shuttle, and each exhales \(20 . \mathrm{L}\) of air per minute, how long could clean air be generated if there were \(25,000 \mathrm{~g}\) of LiOH pellets available for each shuttle mission? Assume the density of air is \(0.0010 \mathrm{~g} / \mathrm{mL}\).

A sample of urea contains \(1.121 \mathrm{~g} \mathrm{~N}, 0.161 \mathrm{~g} \mathrm{H}, 0.480 \mathrm{~g} \mathrm{C}\), and \(0.640 \mathrm{~g} \mathrm{O} .\) What is the empirical formula of urea?

Silver sulfadiazine burn-treating cream creates a barrier against bacterial invasion and releases antimicrobial agents directly into the wound. If \(25.0 \mathrm{~g} \mathrm{Ag}_{2} \mathrm{O}\) is reacted with \(50.0 \mathrm{~g} \mathrm{C}_{10} \mathrm{H}_{10} \mathrm{~N}_{4} \mathrm{SO}_{2}\), what mass of silver sulfadiazine, \(\mathrm{AgC}_{10} \mathrm{H}_{9} \mathrm{~N}_{4} \mathrm{SO}_{2}\), can be produced, assuming \(100 \%\) yield? \(\mathrm{Ag}_{2} \mathrm{O}(s)+2 \mathrm{C}_{10} \mathrm{H}_{10} \mathrm{~N}_{4} \mathrm{SO}_{2}(s) \longrightarrow 2 \mathrm{AgC}_{10} \mathrm{H}_{9} \mathrm{~N}_{4} \mathrm{SO}_{2}(s)+\mathrm{H}_{2} \mathrm{O}(l)\)

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