Warning: foreach() argument must be of type array|object, bool given in /var/www/html/web/app/themes/studypress-core-theme/template-parts/header/mobile-offcanvas.php on line 20

Polyesters containing double bonds are often crosslinked by reacting the polymer with styrene. a. Draw the structure of the copolymer of \(\mathrm{HO}-\mathrm{CH}_{2} \mathrm{CH}_{2}-\mathrm{OH} \quad\) and \(\quad \mathrm{HO}_{2} \mathrm{C}-\mathrm{CH}=\mathrm{CH}-\mathrm{CO}_{2} \mathrm{H}\) b. Draw the structure of the crosslinked polymer (after the polyester has been reacted with styrene).

Short Answer

Expert verified
The copolymer structure of the given monomers is \(\mathrm{HO}-\mathrm{CH}_{2} \mathrm{CH}_{2}-\mathrm{O}-\mathrm{CO}-\mathrm{CH}=\mathrm{CH}-\mathrm{CO}_{2} \mathrm{H}\), where the hydroxyl group of one monomer reacts with the carboxylic acid group of the other forming an ester linkage. The crosslinked polymer structure after reacting with styrene can be represented as \(\mathrm{[HO}-\mathrm{CH}_{2} \mathrm{CH}_{2}-\mathrm{O}-\mathrm{CO}-\mathrm{CH}-\mathrm{CH}-\mathrm{CO}_{2} \mathrm{H][styrene]_{n}\), where styrene molecules connect to the copolymer through the reactive double bonds forming a crosslinked network.

Step by step solution

01

Identify the reactive groups in the monomers

The reactive groups in the given monomers are the hydroxyl groups (\(\mathrm{OH}\)) in \(\mathrm{HO}-\mathrm{CH}_{2} \mathrm{CH}_{2}-\mathrm{OH}\) and the double bond (\(\mathrm{C}=\mathrm{C}\)) and carboxylic acid group (\(\mathrm{CO}_{2} \mathrm{H}\)) in \(\mathrm{HO}_{2} \mathrm{C}-\mathrm{CH}=\mathrm{CH}-\mathrm{CO}_{2} \mathrm{H}\).
02

Combine the monomers through a condensation reaction

In a condensation polymerization reaction, the hydroxyl group of one monomer reacts with the carboxylic acid group of the other monomer to form an ester (\(\mathrm{COO}\)) linkage and a molecule of water. The double bond in the second monomer remains unreacted. The resulting structure is shown below: \(\mathrm{HO}-\mathrm{CH}_{2} \mathrm{CH}_{2}-\mathrm{O}-\mathrm{CO}-\mathrm{CH}=\mathrm{CH}-\mathrm{CO}_{2} \mathrm{H}\) B. Drawing the crosslinked polymer structure
03

Identify the reaction of styrene with the copolymer

Styrene has a double bond between two carbon atoms, which makes it reactive and capable of reacting with the double bond in the copolymer created in part A.
04

Draw the crosslinked polymer

The reactive double bond in the copolymer can react with styrene to form a crosslinked structure. The crosslinked structure can be represented as: \(\mathrm{[HO}-\mathrm{CH}_{2} \mathrm{CH}_{2}-\mathrm{O}-\mathrm{CO}-\mathrm{CH}-\mathrm{CH}-\mathrm{CO}_{2} \mathrm{H][styrene]_{n}\) In this structure, the styrene molecules are connected to the copolymer through the reactive double bonds, forming a crosslinked network.

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with Vaia!

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

A chemical "breathalyzer" test works because ethanol in the breath is oxidized by the dichromate ion (orange) to form acetic acid and chromium(III) ion (green). The balanced reaction is \(3 \mathrm{C}_{2} \mathrm{H}_{5} \mathrm{OH}(a q)+2 \mathrm{Cr}_{2} \mathrm{O}_{7}{ }^{2-}(a q)+2 \mathrm{H}^{+}(a q) \longrightarrow\) \(3 \mathrm{HC}_{2} \mathrm{H}_{3} \mathrm{O}_{2}(a q)+4 \mathrm{Cr}^{3+}(a q)+11 \mathrm{H}_{2} \mathrm{O}(l)\) You analyze a breathalyzer test in which \(4.2 \mathrm{mg} \mathrm{K}_{2} \mathrm{Cr}_{2} \mathrm{O}_{7}\) was reduced. Assuming the volume of the breath was \(0.500 \mathrm{~L}\) at \(30 .{ }^{\circ} \mathrm{C}\) and \(750 . \mathrm{mm} \mathrm{Hg}\), what was the mole percent alcohol of the breath?

Diborane, \(\mathrm{B}_{2} \mathrm{H}_{6}\), is a highly unstable compound that reacts explosively with oxygen. Ethane, \(\mathrm{C}_{2} \mathrm{H}_{6}\), combines with oxygen only at elevated temperatures. Explain the differences in these two compounds.

Draw all structural and geometrical ( cis-trans) isomers of \(\mathrm{C}_{4} \mathrm{H}_{7} \mathrm{~F}\). Ignore any cyclic isomers.

Polychlorinated dibenzo- \(p\) -dioxins (PCDDs) are highly toxic substances that are present in trace amounts as by-products of some chemical manufacturing processes. They have been implicated in a number of environmental incidents- for example, the chemical contamination at Love Canal and the herbicide spraying The most toxic \(\mathrm{PCDD}\) is \(2,3,7,8\) -tetrachloro-dibenzo- \(p\) -dioxin. Draw the structure of this compound. Also draw the structures of two other isomers containing four chlorine atoms.

Over 100 different kinds of mutant hemoglobin molecules have been detected in humans. Unlike sickle cell anemia (see Exercise 93), not all of these mutations are as serious. In one nonlethal mutation, glutamine substitutes for a single glutamic acid in normal hemoglobin. Rationalize why this substitution is nonlethal.

See all solutions

Recommended explanations on Chemistry Textbooks

View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.

Sign-up for free