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Draw the structural formula for each of the following. a. formaldehyde (methanal) b. 4 -heptanone c. 3 -chlorobutanal d. 5,5 -dimethyl-2-hexanone

Short Answer

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a. Formaldehyde (methanal): H-C=O b. 4-heptanone: CH3-CH2-CH2-CH2-CO-CH2-CH3 c. 3-chlorobutanal: H3C-CH(Cl)-CH2-CH=O d. 5,5-dimethyl-2-hexanone: CH3-CO-CH-CH2-CH(CH3)2

Step by step solution

01

Compound a: Formaldehyde (methanal)

Formaldehyde is the simplest aldehyde with one carbon atom, making it methanal according to IUPAC nomenclature. The aldehyde functional group is -CHO. Hence, the structural formula for formaldehyde is: H ' H - C = O ' H
02

Compound b: 4-heptanone

4-heptanone is a ketone with a seven-carbon atom chain (hept- prefix). The ketone functional group is -CO-, and the number "4" indicates that it is attached to the 4th carbon atom. The structural formula for 4-heptanone is: CH3-CH2-CH2-CH2-CO-CH2-CH3
03

Compound c: 3-chlorobutanal

3-chlorobutanal is an aldehyde with a four-carbon atom chain (but- prefix) and a chlorine atom (chloro) attached to the third carbon atom. The aldehyde group is -CHO, attached to the first carbon atom (terminal). The structural formula for 3-chlorobutanal is: Cl ' H3C-CH-CH2-CH=O ' H
04

Compound d: 5,5-dimethyl-2-hexanone

5,5-dimethyl-2-hexanone is a ketone with a six-carbon atom chain (hex- prefix). The ketone functional group is -CO-, and it is attached to the second carbon atom. There are two methyl groups (-CH3) attached to the fifth carbon atom, as indicated by the (5,5-dimethyl) prefix. The structural formula for 5,5-dimethyl-2-hexanone is: CH3 ' CH3-CO-CH-CH2-CH(CH3)2 ' H

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Most popular questions from this chapter

In the presence of light, chlorine can substitute for one (or more) of the hydrogens in an alkane. For the following reactions, draw the possible monochlorination products. a. 2,2 -dimethylpropane \(+\mathrm{Cl}_{2} \stackrel{\mathrm{hv}}{\longrightarrow}\) b. 1,3 -dimethylcyclobutane \(+\mathrm{Cl}_{2} \stackrel{\text { hv }}{\longrightarrow}\) c. 2,3 -dimethylbutane \(+\mathrm{Cl}_{2} \stackrel{\mathrm{hv}^{-}}{\longrightarrow}\)

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