Warning: foreach() argument must be of type array|object, bool given in /var/www/html/web/app/themes/studypress-core-theme/template-parts/header/mobile-offcanvas.php on line 20

Qualitatively draw the crystal field splitting for a trigonal bipyramidal complex ion. (Let the \(z\) axis be perpendicular to the trigonal plane.)

Short Answer

Expert verified
In a trigonal bipyramidal complex ion, the d-orbitals of the metal ion split into two energy levels due to different electrostatic interactions with the ligands. The axial orbitals (\(d_{z^2}\) and \(d_{x^2 - y^2}\)) have higher energy (\(E_g\)) while the equatorial orbitals (\(d_{xy}\), \(d_{yz}\), and \(d_{xz}\)) have lower energy (\(T_{2g}\)). To draw the crystal field splitting diagram, start with a vertical line representing energy levels. Draw two horizontal lines for the two energy levels (\(E_g\) and \(T_{2g}\)). Label and draw the axial orbitals (\(d_{z^2}\) and \(d_{x^2 - y^2}\)) on the \(E_g\) level and the equatorial orbitals (\(d_{xy}\), \(d_{yz}\), and \(d_{xz}\)) on the \(T_{2g\) level. Make sure to indicate the energy splitting between the levels.

Step by step solution

01

- Understand the Trigonal Bipyramidal Geometry

In trigonal bipyramidal geometry, there are five ligands surrounding the central metal ion, forming a triangle in the equatorial XY plane (trigonal plane), and two axial bonds connecting the metal ion to ligands above and below the equatorial plane along the Z-axis. This arrangement causes the d-orbitals of the metal ion to split into two sets because of different electrostatic interactions with the ligands.
02

- Identify the d-orbitals

In a transition-metal ion, there are five d-orbitals - \(d_{xy}\), \(d_{yz}\), \(d_{xz}\), \(d_{x^2 - y^2}\), and \(d_{z^2}\). Since the Z-axis is perpendicular to the trigonal plane in a trigonal bipyramidal complex ion, we can classify these d-orbitals as: - Axial orbitals: \(d_{z^2}\) and \(d_{x^2 - y^2}\) - Equatorial orbitals: \(d_{xy}\), \(d_{yz}\), and \(d_{xz}\)
03

- Determine the Crystal Field Splitting

In the trigonal bipyramidal complex ion, the axial orbitals and equatorial orbitals experience different electrostatic interactions with surrounding ligands. The axial orbitals face repulsion from two axial ligands along the z-axis, while the equatorial orbitals experience repulsion from the three equatorial ligands in the XY plane. This difference causes the d-orbitals to split into two energy levels: Higher energy level (\(E_g\)): Axial orbitals - \(d_{z^2}\) and \(d_{x^2 - y^2}\), Lower energy level (\(T_{2g}\)): Equatorial orbitals - \(d_{xy}\), \(d_{yz}\), and \(d_{xz}\).
04

- Draw the Crystal Field Splitting Diagram

Based on this information, we can now draw the crystal field splitting diagram for a trigonal bipyramidal complex ion: 1. Start by drawing a vertical line to represent energy levels. 2. Draw two horizontal lines with space between to represent the two different energy levels: higher (\(E_g\)) and lower (\(T_{2g}\)). 3. Label the higher energy level line as "(\(E_g\))" and the lower energy line as "(\(T_{2g}\))". 4. On the higher energy level line, draw two boxes and label them \(d_{z^2}\) and \(d_{x^2 - y^2}\), representing the axial orbitals. 5. On the lower energy level line, draw three boxes and label them \(d_{xy}\), \(d_{yz}\), and \(d_{xz}\), representing the equatorial orbitals. Make sure to indicate the energy splitting between these two levels clearly, and the overall diagram should represent the qualitative crystal field splitting for a trigonal bipyramidal complex ion.

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with Vaia!

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

. Which is more likely to be paramagnetic, \(\mathrm{Fe}(\mathrm{CN})_{6}^{4-}\) or \(\mathrm{Fe}\left(\mathrm{H}_{2} \mathrm{O}\right)_{6}^{2+}\) ? Explain.

The compound cisplatin, \(\mathrm{Pt}\left(\mathrm{NH}_{3}\right)_{2} \mathrm{Cl}_{2}\), has been studied extensively as an antitumor agent. The reaction for the synthesis of cisplatin is: $$\mathrm{K}_{2} \mathrm{PtCl}_{4}(a q)+2 \mathrm{NH}_{3}(a q) \longrightarrow \mathrm{Pt}\left(\mathrm{NH}_{3}\right)_{2} \mathrm{Cl}_{2}(s)+2 \mathrm{KCl}(a q)$$ Write the electron configuration for platinum ion in cisplatin. Most \(d^{8}\) transition metal ions exhibit square planar geometry. With this and the name in mind, draw the structure of cisplatin.

How many bonds could each of the following chelating ligands form with a metal ion? a. acetylacetone (acacH), a common ligand in organometallic catalysts: b. diethylenetriamine, used in a variety of industrial processes: c. salen, a common ligand for chiral organometallic catalysts: d. porphine, often used in supermolecular chemistry as well as catalysis; biologically, porphine is the basis for many different types of porphyrin- containing proteins, including heme proteins:

In the production of printed circuit boards for the electronics industry, a \(0.60-\mathrm{mm}\) layer of copper is laminated onto an insulating plastic board. Next, a circuit pattern made of a chemically resistant polymer is printed on the board. The unwanted copper is removed by chemical etching, and the protective polymer is finally removed by solvents. One etching reaction is \(\left[\mathrm{Cu}\left(\mathrm{NH}_{3}\right)_{4}\right] \mathrm{Cl}_{2}(a q)+4 \mathrm{NH}_{3}(a q)+\mathrm{Cu}(s)\) \(\longrightarrow 2\left[\mathrm{Cu}\left(\mathrm{NH}_{3}\right)_{4}\right] \mathrm{Cl}(a q)\) a. Is this reaction an oxidation-reduction process? Explain. b. \(A\) plant needs to manufacture 10,000 printed circuit boards, each \(8.0 \times 16.0 \mathrm{~cm}\) in area. An average of \(80 . \%\) of the copper is removed from each board (density of copper \(=8.96\) \(\mathrm{g} / \mathrm{cm}^{3}\) ). What masses of \(\left[\mathrm{Cu}\left(\mathrm{NH}_{3}\right)_{4}\right] \mathrm{Cl}_{2}\) and \(\mathrm{NH}_{3}\) are needed to do this? Assume \(100 \%\) yield.

There are three salts that contain complex ions of chromium and have the molecular formula \(\mathrm{CrCl}_{3} \cdot 6 \mathrm{H}_{2} \mathrm{O}\). Treating \(0.27 \mathrm{~g}\) of the first salt with a strong dehydrating agent resulted in a mass loss of \(0.036 \mathrm{~g}\). Treating \(270 \mathrm{mg}\) of the second salt with the same dehydrating agent resulted in a mass loss of \(18 \mathrm{mg}\). The third salt did not lose any mass when treated with the same dehydrating agent. Addition of excess aqueous silver nitrate to \(100.0-\mathrm{mL}\) portions of \(0.100 M\) solutions of each salt resulted in the formation of different masses of silver chloride; one solution yielded 1430 \(\mathrm{mg} \mathrm{AgCl} ;\) another, \(2870 \mathrm{mg} \mathrm{AgCl}\); the third, \(4300 \mathrm{mg} \mathrm{AgCl}\). Two of the salts are green and one is violet. Suggest probable structural formulas for these salts, defending your answer on the basis of the preceding observations. State which salt is most likely to be violet. Would a study of the magnetic properties of the salts be helpful in determining the structural formulas? Explain.

See all solutions

Recommended explanations on Chemistry Textbooks

View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.

Sign-up for free