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Draw all geometrical and linkage isomers of square planar \(\left[\mathrm{Pt}\left(\mathrm{NH}_{3}\right)_{2}(\mathrm{SCN})_{2}\right]\).

Short Answer

Expert verified
The four possible isomers for the square planar complex \(\left[\mathrm{Pt}\left(\mathrm{NH}_{3}\right)_{2}(\mathrm{SCN})_{2}\right]\) are: 1. Cis arrangement with N-bonded SCN-: \(\left[\mathrm{Pt}\left(\mathrm{NH}_{3}\right)_{2}\left(\mathrm{NCS}\right)_{2}\right]_{\text {cis}}\) 2. Cis arrangement with S-bonded SCN-: \(\left[\mathrm{Pt}\left(\mathrm{NH}_{3}\right)_{2}\left(\mathrm{SCN}\right)_{2}\right]_{\text {cis}}\) 3. Trans arrangement with N-bonded SCN-: \(\left[\mathrm{Pt}\left(\mathrm{NH}_{3}\right)_{2}\left(\mathrm{NCS}\right)_{2}\right]_{\text {trans}}\) 4. Trans arrangement with S-bonded SCN-: \(\left[\mathrm{Pt}\left(\mathrm{NH}_{3}\right)_{2}\left(\mathrm{SCN}\right)_{2}\right]_{\text {trans}}\) These include two geometrical isomers (cis and trans) and two linkage isomers (N-bonded and S-bonded SCN-).

Step by step solution

01

Draw Geometrical Isomers

We have two possible geometrical arrangements for the ligands in a square planar complex: cis and trans. 1. Cis arrangement: Both NH3 ligands are adjacent, and both SCN- ligands are adjacent. \(\begin{array}{cc} \left[\mathrm{Pt}\left(\mathrm{NH}_{3}\right)_{2}\left(\mathrm{SCN}\right)_{2}\right]_{\text {cis }} \end{array}\) 2. Trans arrangement: Both NH3 ligands are opposite, and both SCN- ligands are opposite. \(\begin{array}{cc} \left[\mathrm{Pt}\left(\mathrm{NH}_{3}\right)_{2}\left(\mathrm{SCN}\right)_{2}\right]_{\text {trans }} \end{array}\)
02

Draw Linkage Isomers

Now we will draw the possible linkage isomers by considering the SCN- ligand binding through either the sulfur (S) or the nitrogen (N) atom. 1. Cis arrangement (N-bonded SCN-): \(\begin{array}{cc} \left[\mathrm{Pt}\left(\mathrm{NH}_{3}\right)_{2}\left(\mathrm{NCS}\right)_{2}\right]_{\text {cis}} \end{array}\) 2. Cis arrangement (S-bonded SCN-): \(\begin{array}{cc} \left[\mathrm{Pt}\left(\mathrm{NH}_{3}\right)_{2}\left(\mathrm{SCN}\right)_{2}\right]_{\text {cis}} \end{array}\) 3. Trans arrangement (N-bonded SCN-): \(\begin{array}{cc} \left[\mathrm{Pt}\left(\mathrm{NH}_{3}\right)_{2}\left(\mathrm{NCS}\right)_{2}\right]_{\text {trans}} \end{array}\) 4. Trans arrangement (S-bonded SCN-): \(\begin{array}{cc} \left[\mathrm{Pt}\left(\mathrm{NH}_{3}\right)_{2}\left(\mathrm{SCN}\right)_{2}\right]_{\text {trans}} \end{array}\) Therefore, there are four possible isomers for the given complex: two geometrical isomers and two linkage isomers.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Geometrical Isomers in Square Planar Complexes
In coordination chemistry, geometrical isomers are molecules with the same chemical formula but different spatial arrangements of ligands. This change in position leads to variations in properties. For square planar complexes, common geometrical isomers include "cis" and "trans" formations. In a cis arrangement, similar ligands are adjacent, which could affect properties like polarity or color. Meanwhile, in a trans arrangement, similar ligands are on opposite sides of the central atom, often leading to different physical or chemical behaviors.
For example, in the complex \([\mathrm{Pt}(\mathrm{NH}_3)_2(\mathrm{SCN})_2]\), the NH₃ and SCN⁻ ligands can shift between these positions, creating distinct isomeric forms.
  • Cis isomer: NH₃ are adjacent and SCN⁻ are adjacent.
  • Trans isomer: NH₃ are opposite each other, and SCN⁻ are opposite each other.
Understanding the arrangement helps predict interaction and behavior in different chemical environments.
Linkage Isomers and Their Importance
Linkage isomers occur when a ligand capable of coordinating in more than one way changes its point of attachment to the central metal atom. Some ligands, like thiocyanate (SCN⁻), can attach via different atoms, leading to unique ismomeric varieties.
The thiocyanate ligand can bond either through the sulfur (S) atom or the nitrogen (N) atom:
  • S-bonded SCN: The sulfur atom connects to the central platinum.
  • N-bonded SCN: The nitrogen atom connects to the central platinum.
Linkage isomers can have differing chemical properties, including reactivity and color, despite having similar structures. Within the \([\mathrm{Pt}(\mathrm{NH}_3)_2(\mathrm{SCN})_2]\) complex, linkage isomers can exist in both cis and trans forms, giving rise to a variety of isomeric forms based on bonding site.
Characteristics of Square Planar Complexes
Square planar complexes are a subset of coordination compounds where ligands are positioned in a planar square around a central metal. This arrangement is common for metal ions such as Pt²⁺, Pd²⁺, and Au³⁺. Due to their geometry, they can exhibit both geometrical and linkage isomerism.
These complexes not only participate in demonstrating the concepts of cis/trans isomerism but also provide an avenue for interesting electronic properties. The square planar arrangement allows for dfferent overlapping of orbitals as compared to other geometries like tetrahedral or octahedral complexes. This can affect stability and electronic transitions:
  • Preferred in lower coordination numbers: Typically four ligands are present.
  • Can show fascinating optical and magnetic properties: Due to their electronic structure and isomerism.
Understanding this geometry helps predict and explain their physical, chemical, and spectroscopic properties significantly.

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Most popular questions from this chapter

Molybdenum is obtained as a by-product of copper mining or is mined directly (primary deposits are in the Rocky Mountains in Colorado). In both cases it is obtained as \(\mathrm{MoS}_{2}\), which is then converted to \(\mathrm{MoO}_{3}\). The \(\mathrm{MoO}_{3}\) can be used directly in the production of stainless steel for high-speed tools (which accounts for about \(85 \%\) of the molybdenum used). Molybdenum can be purified by dissolving \(\mathrm{MoO}_{3}\) in aqueous ammonia and crystallizing ammonium molybdate. Depending on conditions, either \(\left(\mathrm{NH}_{4}\right)_{2} \mathrm{Mo}_{2} \mathrm{O}_{7}\) or \(\left(\mathrm{NH}_{4}\right)_{6} \mathrm{Mo}_{7} \mathrm{O}_{24} \cdot 4 \mathrm{H}_{2} \mathrm{O}\) is obtained. a. Give names for \(\mathrm{MoS}_{2}\) and \(\mathrm{MoO}_{3}\). b. What is the oxidation state of Mo in each of the compounds mentioned above?

Name the following coordination compounds. a. \(\mathrm{Na}_{4}\left[\mathrm{Ni}\left(\mathrm{C}_{2} \mathrm{O}_{4}\right)_{3}\right]\) b. \(\mathrm{K}_{2}\left[\mathrm{CoCl}_{4}\right]\) c. \(\left[\mathrm{Cu}\left(\mathrm{NH}_{3}\right)_{4}\right] \mathrm{SO}_{4}\) d. \(\left[\mathrm{Co}(\mathrm{en})_{2}(\mathrm{SCN}) \mathrm{Cl}\right] \mathrm{Cl}\)

Ethylenediaminetetraacetate \(\left(\mathrm{EDTA}^{4-}\right)\) is used as a complexing agent in chemical analysis with the structure shown in Figure 21.7. Solutions of EDTA \(^{4-}\) are used to treat heavy metal poisoning by removing the heavy metal in the form of a soluble complex ion. The complex ion essentially eliminates the heavy metal ions from reacting with biochemical systems. The reaction of EDTA \(^{4-}\) with \(\mathrm{Pb}^{2+}\) is \(\mathrm{Pb}^{2+}(a q)+\mathrm{EDTA}^{4-}(a q) \rightleftharpoons \mathrm{PbEDTA}^{2-}(a q) \quad K=1.1 \times 10^{18}\) Consider a solution with \(0.010 \mathrm{~mol} \mathrm{~Pb}\left(\mathrm{NO}_{3}\right)_{2}\) added to \(1.0 \mathrm{~L}\) of an aqueous solution buffered at \(\mathrm{pH}=13.00\) and containing \(0.050\) \(M \mathrm{Na}_{4} \mathrm{EDTA} .\) Does \(\mathrm{Pb}(\mathrm{OH})_{2}\) precipitate from this solution? \(\left(K_{\text {?? }}\right.\) for \(\left.\mathrm{Pb}(\mathrm{OH})_{2}=1.2 \times 10^{-15} .\right)\)

Give formulas for the following. a. Hexakis(pyridine)cobalt(III) chloride b. Pentaammineiodochromium(III) iodide c. Tris(ethylenediamine)nickel(II) bromide d. Potassium tetracyanonickelate(II) e. Tetraamminedichloroplatinum(IV) tetrachloroplatinate(II)

Draw all geometrical and linkage isomers of \(\mathrm{Co}\left(\mathrm{NH}_{3}\right)_{4}\left(\mathrm{NO}_{2}\right)_{2}\).

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