Question

Tin forms compounds in the \(+2\) and \(+4\) oxidation states. Therefore, when tin reacts with fluorine, two products are possible. Write balanced equations for the production of the two tin halide compounds and name them.

Short answer

The two balanced equations for the formation of tin halide compounds when tin reacts with fluorine are: 1. \( 2Sn + 2F2 \rightarrow 2SnF2 \) (Tin(II) fluoride) 2. \( Sn + 2F2 \rightarrow SnF4 \) (Tin(IV) fluoride)

Step-by-step solution

Determine the chemical formulas for the two tin halide compounds.

Tin has two possible oxidation states, +2 and +4, and fluorine has an oxidation state of -1. The first compound will have tin in a +2 oxidation state and the second compound will have tin in a +4 oxidation state. To balance the charges in the compounds, we use the following formulas: 1. Tin(+2) + Fluorine(-1) --> SnF2 2. Tin(+4) + Fluorine(-1) --> SnF4 Now we have the chemical formulas for the two tin halide compounds.

Write the balanced equations for the production of the tin halide compounds.

To write the balanced equations for the production of these compounds, we start with the unbalanced equation and then balance it according to the law of conservation of mass. Since there are only two reactants in each reaction (tin and fluorine), the balancing process is straightforward. 1. Unbalanced equation (first tin halide compound): Sn + F2 → SnF2 Balanced equation: 2Sn + 2F2 → 2SnF2 2. Unbalanced equation (second tin halide compound): Sn + F2 → SnF4 Balanced equation: Sn + 2F2 → SnF4 Now we have balanced equations for both reactions.

Name the tin halide compounds.

Now that we have written the balanced equations for the formation of the tin halide compounds, we can name them. The names for metallic compounds follow the pattern "metal name" + "halide name." + Roman numeral, to indicate the oxidation state of the metal if it forms multiple compounds. 1. First tin halide compound (SnF2): Name - Tin(II) fluoride 2. Second tin halide compound (SnF4): Name - Tin(IV) fluoride In summary, the two balanced equations for the formation of tin halide compounds are: 1. 2Sn + 2F2 → 2SnF2 (Tin(II) fluoride) 2. Sn + 2F2 → SnF4 (Tin(IV) fluoride)