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Name each of the following compounds: a. CuI f. \(\mathrm{S}_{4} \mathrm{~N}_{4}\) b. \(\mathrm{CuI}_{2}\) g. \(\mathrm{SF}_{4}\) c. CoI \(_{2}\) h. \(\mathrm{NaOCl}\) d. \(\mathrm{Na}_{2} \mathrm{CO}_{3}\) i. \(\mathrm{BaCrO}_{4}\) e. \(\mathrm{NaHCO}_{3}\) j. \(\mathrm{NH}_{4} \mathrm{NO}_{3}\)

Short Answer

Expert verified
a. Copper(I) Iodide f. Tetrasulfur Tetranitride b. Copper(II) Iodide g. Sulfur Tetrafluoride c. Cobalt(II) Iodide h. Sodium Hypochlorite d. Sodium Carbonate i. Barium Chromate e. Sodium Bicarbonate j. Ammonium Nitrate

Step by step solution

01

Compound a: CuI

This is a binary compound. Copper (Cu) is a transition metal, so its oxidation state should be written in Roman numerals after the name. The oxidation state of copper here is +1 because iodine (I) has a -1 charge. This gives us the name Copper(I) Iodide.
02

Compound f: \(\mathrm{S}_{4} \mathrm{N}_{4}\)

This is a binary compound. We use prefixes to show the number of atoms of each element: Tetrasulfur (S4) and Tetranitrogen (N4). The name of this compound is Tetrasulfur Tetranitride.
03

Compound b: \(\mathrm{CuI}_{2}\)

This is a binary compound containing copper and iodine. Copper (Cu) in this compound has an oxidation state of +2 since 2 iodine atoms balance the charge. The name of this compound is Copper(II) Iodide.
04

Compound g: \(\mathrm{SF}_{4}\)

This is a binary compound. The name of this compound is Sulfur Tetrafluoride, following the same naming rules as in Compound f.
05

Compound c: CoI\(_{2}\)

This is a binary compound. Cobalt (Co) is a transition metal, so its oxidation state should be written in Roman numerals after the name. The oxidation state of cobalt here is +2 because 2 iodine atoms balance the charge. This gives us the name Cobalt(II) Iodide.
06

Compound h: \(\mathrm{NaOCl}\)

This compound contains sodium (Na), oxygen (O), and chlorine (Cl). Here, we have the polyatomic ion hypochlorite (OCl-), so the name is Sodium Hypochlorite.
07

Compound d: \(\mathrm{Na}_{2} \mathrm{CO}_{3}\)

This compound is composed of sodium (Na) and the polyatomic ion carbonate (CO3^2-). The name of this compound is Sodium Carbonate.
08

Compound i: \(\mathrm{BaCrO}_{4}\)

This compound consists of barium (Ba) and the polyatomic ion chromate (CrO4^2-). The name of this compound is Barium Chromate.
09

Compound e: \(\mathrm{NaHCO}_{3}\)

This compound is composed of sodium (Na) and the polyatomic ion hydrogen carbonate (HCO3-), which is also known as bicarbonate. The name of this compound is Sodium Bicarbonate.
10

Compound j: \(\mathrm{NH}_{4} \mathrm{NO}_{3}\)

This compound is composed of the ammonium (NH4+) polyatomic ion and the nitrate (NO3-) polyatomic ion. The name for this compound is Ammonium Nitrate.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Transition Metals
Transition metals are found in the d-block of the periodic table and possess unique properties, including the ability to form compounds with different oxidation states. This ability arises from the presence of d-electrons, which can be lost or shared when forming bonds. Transition metals often form colored compounds, another distinct trait. One example from our exercise involves Copper (Cu), a transition metal. In compound CuI, Copper displays a +1 oxidation state, and its name is Copper(I) Iodide. Understanding the versatility of transition metals is crucial for correctly naming compounds, especially when multiple oxidation states are possible.
Binary Compounds
Binary compounds consist of two different elements. Naming such compounds requires understanding the nature of the elements involved. If one of the elements is a metal, its oxidation state must be specified if it has more than one possible state. For example, CuI and CuI i{2} are binary compounds containing copper and iodine. They are distinguished by their oxidation states: Copper(I) Iodide and Copper(II) Iodide, respectively. When both elements are nonmetals, prefixes such as 'mono-', 'di-', 'tri-', etc., are used to indicate the number of atoms, as seen in SF i{4}, named Sulfur Tetrafluoride, and S b{4}N b{4}, named Tetrasulfur Tetranitride. These rules help ensure clarity and precision in chemical nomenclature.
Polyatomic Ions
Polyatomic ions are charged entities composed of several atoms bonded together. They act collectively as a single ion. Key polyatomic ions include carbonate cn{CO}{3}{2-}, bicarbonate cn{HCO}{3}{-}, and nitrate cn{NO}{3}{-}. Naming compounds with polyatomic ions involves combining the cation and the name of the polyatomic ion. Consider compound Na b{2}CO b{3}, which includes sodium and the carbonate ion, making it Sodium Carbonate. Similarly, NaHCO b{3} is Sodium Bicarbonate, and NaOCl contains the hypochlorite ion, resulting in the name Sodium Hypochlorite. Understanding the nomenclature of polyatomic ions is essential for correctly naming many inorganic compounds.
Oxidation States
Oxidation states, or oxidation numbers, indicate the degree of oxidation of an atom in a compound. They help to determine how electrons are distributed among different atoms. Understanding oxidation states is vital when naming compounds containing transition metals. In binary p{and } transition metal compounds, the metal's oxidation state is often specified using Roman numerals. e For example, compound CoI i{2} involves cobalt with a +2 oxidation state, and it's named Cobalt(II) Iodide. Similarly, in CuI i{2}, copper is in a +2 oxidation state, resulting in it being called Copper(II) Iodide. Recognizing and applying the concept of oxidation states facilitates accurate chemical naming and helps predict the properties of compounds.

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