Warning: foreach() argument must be of type array|object, bool given in /var/www/html/web/app/themes/studypress-core-theme/template-parts/header/mobile-offcanvas.php on line 20

a. Classify the following elements as metals or nonmetals: $$ \begin{array}{lll} \mathrm{Mg} & \mathrm{Si} & \mathrm{Rn} \\ \mathrm{Ti} & \mathrm{Ge} & \mathrm{Eu} \\ \mathrm{Au} & \mathrm{B} & \mathrm{Am} \\ \mathrm{Bi} & \mathrm{At} & \mathrm{Br} \end{array} $$ b. The distinction between metals and nonmetals is really not a clear one. Some elements, called metalloids, are intermediate in their properties. Which of these elements would you reclassify as metalloids? What other elements in the periodic table would you expect to be metalloids?

Short Answer

Expert verified
The given elements can be classified as follows: Metals: Mg, Ti, Eu, Au, Am, Bi Nonmetals: Rn, At, Br Metalloids: Si, Ge, B Other elements in the periodic table that are considered metalloids include: Boron (B), Silicon (Si), Germanium (Ge), Arsenic (As), Antimony (Sb), Tellurium (Te), and Polonium (Po).

Step by step solution

01

Identify the elements' positions in the periodic table

In order to classify the given elements, first, refer to a periodic table and identify the position of the following elements within the periodic table: Mg, Si, Rn, Ti, Ge, Eu, Au, B, Am, Bi, At, Br
02

Classify the elements as metals or nonmetals

Based on their positions in the periodic table and the general properties of the groups they belong to, classify the given elements as follows: Metals: Mg, Ti, Eu, Au, Am, Bi Nonmetals: Si, Rn, B, At, Br
03

Identify metalloids in the given set of elements

Elements with properties between metals and nonmetals are considered as metalloids. Based on their properties and their position in the periodic table, identify the following elements as metalloids: Si, Ge, B
04

List other elements in the periodic table expected to be metalloids

Other elements in the periodic table that could be considered as metalloids are: Boron (B), Silicon (Si), Germanium (Ge), Arsenic (As), Antimony (Sb), Tellurium (Te), and Polonium (Po). These elements are typically found around the diagonal line separating metals and nonmetals in the p-block region of the periodic table and have properties that are intermediate between metals and nonmetals. Final classification of the given elements: Metals: Mg, Ti, Eu, Au, Am, Bi Nonmetals: Rn, At, Br Metalloids: Si, Ge, B

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with Vaia!

Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Periodic Table Classification
Understanding the organization of the periodic table is crucial for classifying elements as metals, nonmetals, or metalloids. The periodic table is divided into several blocks referred to as s, p, d, and f-blocks. The metals reside on the left side of the periodic table and are characterized by their shiny appearance, malleability, ductility, and excellent heat and electricity conduction. Nonmetals, located on the right side, are often dull, brittle, and poor conductors of heat and electricity. Metalloids can be found bordering the staircase line that diagonally divides metals and nonmetals in the p-block.

Metallic character decreases as you move from left to right across a period and from bottom to top across a group. This is because of the increase in the number of valence electrons, which affects an element's ability to lose or gain electrons. When working through homework problems or classifying elements, pay special attention to the position of the element within the periodic table, as this is a strong indicator of its classification. For instance, Magnesium (Mg) as an s-block element is thus classified as a metal, whereas Radon (Rn), found in the p-block and to the far right, is classified as a nonmetal.
Properties of Metals and Nonmetals
Metals and nonmetals exhibit distinctive properties which help in their classification. Metals are typically hard, have high melting and boiling points, and are good conductors of electricity and heat. They tend to lose electrons during chemical reactions, forming positive ions or cations. In contrast, nonmetals usually have lower densities, melting and boiling points, and are mostly poor conductors, making them good insulators. They have a tendency to gain electrons, forming negative ions or anions.

For example, Gold (Au), with its high conductivity and ability to be drawn into wires, clearly fits the profile of a metal. Bromine (Br), on the other hand, is a liquid at room temperature and is known to gain electrons during reactions, which is indicative of its nonmetallic nature. It's important, while studying elements, to look at these properties, which are often defined by their electron configurations and bonds they form. Real-world examples, such as copper wiring (metal) or the use of sulfur in fertilizers (nonmetal), can solidify the understanding of these properties.
Identifying Metalloids
Metalloids exhibit a mix of metallic and nonmetallic properties, which can make them quite versatile. They are semiconductors, meaning they can carry electricity better than nonmetals but not as well as metals. This makes them useful in electronic devices. Metalloids also have a variable appearance and may not be as malleable or ductile as metals.

For instance, Silicon (Si) is a classic metalloid used extensively in computer chips for its semiconducting properties. When identifying metalloids in homework exercises or in practice, look for elements that have intermediate electronegativity and ionization energies. As demonstrated in the step-by-step solution, Boron (B) and Germanium (Ge) are also metalloids due to their properties and position on the periodic table near the metal-nonmetal dividing line. Typically, to correctly identify metalloids, you'll need to be familiar with their position in the periodic table and their unique mixed properties. This knowledge can be applied to predict the behavior of elements in chemical reactions and their use in various applications.

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

You have gone back in time and are working with Dalton on a table of relative masses. Following are his data. \(0.602 \mathrm{~g}\) gas A reacts with \(0.295 \mathrm{~g}\) gas \(\mathrm{B}\) \(0.172 \mathrm{~g}\) gas \(\mathrm{B}\) reacts with \(0.401 \mathrm{~g}\) gas \(\mathrm{C}\) \(0.320 \mathrm{~g}\) gas \(\mathrm{A}\) reacts with \(0.374 \mathrm{~g}\) gas \(\mathrm{C}\) a. Assuming simplest formulas \((\mathrm{AB}, \mathrm{BC}\), and \(\mathrm{AC}\) ), construct a table of relative masses for Dalton. b. Knowing some history of chemistry, you tell Dalton that if he determines the volumes of the gases reacted at constant temperature and pressure, he need not assume simplest formulas. You collect the following data: 6 volumes gas \(A+1\) volume gas \(B \rightarrow 4\) volumes product 1 volume gas \(\mathrm{B}+4\) volumes gas \(\mathrm{C} \rightarrow 4\) volumes product 3 volumes gas \(\mathrm{A}+2\) volumes gas \(\mathrm{C} \rightarrow 6\) volumes product Write the simplest balanced equations, and find the actual relative masses of the elements. Explain your reasoning.

From the information in this chapter on the mass of the proton, the mass of the electron, and the sizes of the nucleus and the atom, calculate the densities of a hydrogen nucleus and a hydrogen atom.

Carbon- 14 dating is a method used to determine the age of historical artifacts by examining the ratio of two isotopes of carbon (carbon- 14 and carbon-12). A living plant consumes carbon dioxide in the photosynthesis process and incorporates the carbon, including \({ }^{14} \mathrm{C}\), into its molecules. As long as a plant lives, the \({ }^{14} \mathrm{C} /{ }^{12} \mathrm{C}\) ratio in its molecules remains the same as in the atmosphere because of its continuous uptake of carbon. However, as soon as a tree is cut to make a wooden bowl or a flax plant is harvested to make linen, the \({ }^{14} \mathrm{C}^{12} \mathrm{C}\) ratio begins to decrease because of the radioactive decay of \({ }^{14} \mathrm{C}\left({ }^{12} \mathrm{C}\right.\) is stable). By comparing the current \({ }^{14} \mathrm{C} /{ }^{12} \mathrm{C}\) ratio to the presumed ratio when the artifact was made, one can estimate the age of the artifact. For carbon-14 and carbon- 12 , how many protons and neutrons are in each nucleus? Assuming neutral atoms, how many electrons are present in an atom of carbon- 14 and in an atom of carbon-12?

Write the atomic symbol \(\left({ }_{Z}^{A} X\right)\) for each of the following isotopes. a. \(Z=8\), number of neutrons \(=9\) b. the isotope of chlorine in which \(A=37\) c. \(Z=27, A=60\) d. number of protons \(=26\), number of neutrons \(=31\) e. the isotope of \(I\) with a mass number of 131 f. \(Z=3\), number of neutrons \(=4\)

Why do we call \(\mathrm{Ba}\left(\mathrm{NO}_{3}\right)_{2}\) barium nitrate, but we call \(\mathrm{Fe}\left(\mathrm{NO}_{3}\right)_{2}\) iron(II) nitrate?

See all solutions

Recommended explanations on Chemistry Textbooks

View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.

Sign-up for free