The blood alcohol \(\left(\mathrm{C}_{2} \mathrm{H}_{5} \mathrm{OH}\right)\)
level can be determined by titrating a sample of blood plasma with an acidic
potassium dichromate solution, resulting in the production of
\(\mathrm{Cr}^{3+}(a q)\) and carbon dioxide. The reaction can be monitored
because the dichromate ion \(\left(\mathrm{Cr}_{2} \mathrm{O}_{7}^{2-}\right)\)
is orange in solution, and the \(\mathrm{Cr}^{3+}\) ion is green. The unbalanced
redox equation is
$$\mathrm{Cr}_{2} \mathrm{O}_{7}^{2-}(a q)+\mathrm{C}_{2} \mathrm{H}_{5}
\mathrm{OH}(a q) \longrightarrow \mathrm{Cr}^{3+}(a q)+\mathrm{CO}_{2}(g)$$
If \(31.05 \mathrm{~mL}\) of \(0.0600 M\) potassium dichromate solution is
required to titrate \(30.0 \mathrm{~g}\) blood plasma, determine the mass
percent of alcohol in the blood.