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In making a specific galvanic cell, explain how one decides on the electrodes and the solutions to use in the cell.

Short Answer

Expert verified
To decide on the electrodes and solutions for a specific galvanic cell, follow these steps: 1. Choose electrodes made of metals that participate in the desired redox reaction, are stable, and have a positive cell potential (\(E_{cell}\)). 2. Select solutions containing ions involved in the redox reaction, while considering concentration, safety, and availability. 3. Set up the cell by connecting electrodes to a voltmeter, placing them in the solutions, and adding a salt bridge. 4. Observe voltmeter readings and adjust ion concentrations if necessary to ensure the desired redox reaction occurs and provides the desired output.

Step by step solution

01

Understanding Galvanic Cells

A galvanic cell is an electrochemical cell that converts chemical energy into electrical energy through spontaneous redox reactions. The main components of a galvanic cell are two electrodes (an anode and a cathode), an electrolyte solution in which the electrodes are placed, and a salt bridge that allows the flow of ions between the two compartments without mixing the solutions.
02

Choosing the Electrodes

The electrodes are chosen based on the redox reaction we want to occur in the galvanic cell. One of the electrodes will be the anode, where oxidation occurs, and the other will be the cathode, where reduction occurs. When selecting electrodes, consider the following factors: 1. The type of metal: The electrodes should be made of a metal that can participate in the redox reaction. The most common choice is the metal that is a constituent of the species being oxidized and reduced. 2. The standard reduction potential: Using the standard reduction potential values in a table, predict whether the redox reaction will be spontaneous or not. If the cell potential (\(E_{cell}\)) is positive, the reaction is spontaneous. 3. The Stability: The electrodes should be stable and not corrode or dissolve in the solution.
03

Choosing the Solutions

The solutions to be used along with the electrodes in the galvanic cell should contain the ions that are involved in the overall redox reaction. This can be achieved by choosing solutions containing different ions and observing the changes in cell potential until the desired redox reaction occurs. When selecting solutions, consider the following factors: 1. Concentration: Choose the appropriate concentration of the ions to favor the desired redox reaction. 2. Safety: The solutions should be safe to handle and not dangerous, as some chemicals can be highly reactive or toxic. 3. Availability: The chosen solutions should be readily available and cost-effective.
04

Finalizing the Galvanic Cell

Once the electrodes and the solutions are selected, set up the galvanic cell by connecting the electrodes to a voltmeter and placing them in their respective solutions. Add a salt bridge to facilitate ion transfer between the compartments. Finally, observe the voltmeter readings to ensure that the desired redox reaction is occurring, and the cell provides the desired output. Adjust the concentrations of the ions in the solution if necessary.

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Most popular questions from this chapter

Gold metal will not dissolve in either concentrated nitric acid on concentrated hydrochloric acid. It will dissolve, however, in aqua regia, a mixture of the two concentrated acids. The products of the reaction are the \(\mathrm{AuCl}_{4}^{-}\) ion and gaseous NO. Write a balanced equation for the dissolution of gold in aqua regia.

How can one construct a galvanic cell from two substances, each having a negative standard reduction potential?

An aqueous solution of an unknown salt of ruthenium is electrolyzed by a current of \(2.50\) A passing for \(50.0 \mathrm{~min}\). If \(2.618 \mathrm{~g}\) Ru is produced at the cathode, what is the charge on the ruthenium ions in solution?

When magnesium metal is added to a beaker of \(\mathrm{HCl}(a q)\), a gas is produced. Knowing that magnesium is oxidized and that hydrogen is reduced, write the balanced equation for the reaction. How many electrons are transferred in the balanced equation? What quantity of useful work can be obtained when \(\mathrm{Mg}\) is added directly to the beaker of HCl? How can you harness this reaction to do useful work?

Sketch the galvanic cells based on the following half-reactions. Show the direction of electron flow, show the direction of ion migration through the salt bridge, and identify the cathode and anode. Give the overall balanced equation, and determine \(\mathscr{E}^{\circ}\) for the galvanic cells. Assume that all concentrations are \(1.0 M\) and that all partial pressures are \(1.0 \mathrm{~atm}\). a. \(\mathrm{Cl}_{2}+2 \mathrm{e}^{-} \rightarrow 2 \mathrm{Cl}^{-} \quad \mathscr{E}^{\circ}=1.36 \mathrm{~V}\) \(\mathrm{Br}_{2}+2 \mathrm{e}^{-} \rightarrow 2 \mathrm{Br}^{-} \quad 8^{\circ}=1.09 \mathrm{~V}\) b. \(\mathrm{MnO}_{4}^{-}+8 \mathrm{H}^{+}+5 \mathrm{e}^{-} \rightarrow \mathrm{Mn}^{2+}+4 \mathrm{H}_{2} \mathrm{O}\) \(\mathscr{b}^{\circ}=1.51 \mathrm{~V}\) \(\mathrm{IO}_{4}^{-}+2 \mathrm{H}^{+}+2 \mathrm{e}^{-} \rightarrow \mathrm{IO}_{3}^{-}+\mathrm{H}_{2} \mathrm{O} \quad \mathscr{E ^ { \circ }}=1.60 \mathrm{~V}\)

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