Warning: foreach() argument must be of type array|object, bool given in /var/www/html/web/app/themes/studypress-core-theme/template-parts/header/mobile-offcanvas.php on line 20

Consider a weak acid, HX. If a \(0.10 M\) solution of HX has a pH of \(5.83\) at \(25^{\circ} \mathrm{C}\), what is \(\Delta G^{\circ}\) for the acid's dissociation reaction at \(25^{\circ} \mathrm{C}\) ?

Short Answer

Expert verified
The standard Gibbs Free Energy change (ΔG°) for the dissociation of the weak acid HX at 25°C is 56.196 kJ/mol.

Step by step solution

01

Convert the pH to the concentration of H+ ions

We first need to find the concentration of H+ ions from the given pH value: pH = - log[H+] Or [H+] = 10^(-pH) Given pH = 5.83, we can determine the concentration of H+ ions: [H+] = 10^(-5.83) = 1.47 × 10^(-6) M
02

Write the chemical equation for the dissociation of HX

The chemical equation for the dissociation of the weak acid HX is: HX(aq) ⇌ H+(aq) + X^-(aq)
03

Calculate the equilibrium constant (Ka) for the reaction

Using the reaction above, we can now determine the equilibrium constant (Ka). Since the dissociation is at equilibrium, we can write the expression for Ka: \[ K_a = \frac{[H+][X^-]}{[HX]} \] We know that [H+] = 1.47 × 10^(-6) M, and [HX] at the start is 0.10 M. Since the weak acid dissociates partially, at equilibrium, the concentration of X⁻ will also be equal to [H+]. Therefore, [X⁻] = 1.47 × 10^(-6) M. Now, we can calculate Ka: \[ K_a = \frac{(1.47 \times 10^{-6})(1.47 \times 10^{-6})}{0.10} \] Ka = 2.15 × 10^(-12)
04

Determine the standard reaction Gibbs energy change (ΔG°) using the relationship between ΔG° and Ka

Finally, we need to find the standard Gibbs Free Energy change (ΔG°) using the following formula: \[ \Delta G^{\circ} = -RT \ln(K_a) \] Where R is the gas constant (8.314 J/(mol·K)) and T is the temperature in Kelvin (25°C = 298.15 K) \[ \Delta G^{\circ} = -(8.314)(298.15) \ln(2.15 \times 10^{-12}) \] ΔG° = 56,196 J/mol = 56.196 kJ/mol Therefore, the standard Gibbs Free Energy change (ΔG°) for the dissociation of the weak acid HX at 25°C is 56.196 kJ/mol.

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with Vaia!

Key Concepts

These are the key concepts you need to understand to accurately answer the question.

pH calculation
The concept of pH is central to understanding acid-base reactions. It measures the acidity or basicity of a solution. The pH scale ranges from 0 to 14, with 7 being neutral. Acidic solutions have pH values less than 7, while basic solutions are above 7.
To find the concentration of hydrogen ions ([H+]) from a given pH, we use the formula:\[\text{pH} = -\log[\text{H}^+]\]
Reversing this gives the concentration as:\[[\text{H}^+] = 10^{-\text{pH}}\]
In our example, a pH of 5.83 means the concentration of H+ ions is \(1.47 \times 10^{-6}\ M\). This calculation helps in determining how strongly an acid dissociates in solution.
Equilibrium constant (Ka)
The equilibrium constant \(K_a\) is a vital parameter for weak acids. It quantifies the extent of dissociation of an acid in water. For a weak acid like HX, which dissociates into H+ and X-, the expression is given by:
\[ K_a = \frac{[\text{H}^+][\text{X}^-]}{[\text{HX}]} \]
In our scenario, we know that at equilibrium, [H+] = [X-], both equal to \(1.47 \times 10^{-6}\ M\). The initial concentration of HX is \(0.10\ M\).
By substituting these values into the expression, we find:\[ K_a = \frac{(1.47 \times 10^{-6})(1.47 \times 10^{-6})}{0.10} \approx 2.15 \times 10^{-12} \]
This small \(K_a\) value indicates that HX is a weak acid, dissociating only slightly in solution.
Gibbs Free Energy (ΔG°)
Gibbs Free Energy change (\(\Delta G^\circ\)) provides insight into the favorability of a reaction. It's a thermodynamic quantity that predicts whether a reaction will occur spontaneously.
For chemical reactions, \(\Delta G^\circ\) is related to the equilibrium constant (\(K_a\)) using:
\[ \Delta G^{\circ} = -RT \ln(K_a) \]
Here, \(R\) represents the gas constant (8.314 J/(mol·K)), and \(T\) is the temperature in Kelvin.
At 25°C or 298.15 K, substituting \(K_a = 2.15 \times 10^{-12}\), we find:
\[ \Delta G^{\circ} = -(8.314)(298.15) \ln(2.15 \times 10^{-12}) \approx 56.196\ \text{kJ/mol} \]
This positive \(\Delta G^\circ\) suggests the dissociation of HX into H+ and X- is not spontaneous.
Chemical equilibrium
Chemical equilibrium is a state where the forward and reverse reactions occur at the same rate, resulting in constant concentrations of products and reactants.
For the dissociation of a weak acid like HX:
\[ \text{HX} (aq) \rightleftharpoons \text{H}^+ (aq) + \text{X}^- (aq) \]
Equilibrium is reached when the concentration of HX, H+, and X- stabilize. At this point, the rates of dissociation and recombination of HX equal each other.
This balance is described quantitatively by the equilibrium constant \(K_a\). It helps determine how much an acid will dissociate under specific conditions.
In weak acids, the position of equilibrium is toward the reactants side, indicating limited dissociation, which is why \(K_a\) values are usually small.
This concept is crucial for understanding not only acid-base chemistry, but overall chemical reactions and their behaviors in various conditions.

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

Consider two reactions for the production of ethanol: $$\begin{array}{l}\mathrm{C}_{2} \mathrm{H}_{4}(g)+\mathrm{H}_{2} \mathrm{O}(g) \longrightarrow \mathrm{CH}_{3} \mathrm{CH}_{2} \mathrm{OH}(l) \\\ \mathrm{C}_{2} \mathrm{H}_{6}(g)+\mathrm{H}_{2} \mathrm{O}(g) \longrightarrow \mathrm{CH}_{3} \mathrm{CH}_{2} \mathrm{OH}(l)+\mathrm{H}_{2}(g) \end{array}$$ Which would be the more thermodynamically feasible at standard conditions? Why?

Some nonelectrolyte solute (molar mass \(=142 \mathrm{~g} / \mathrm{mol}\) ) was dissolved in \(150 . \mathrm{mL}\) of a solvent (density \(=0.879 \mathrm{~g} / \mathrm{cm}^{3}\) ). The elevated boiling point of the solution was \(355.4 \mathrm{~K}\). What mass of solute was dissolved in the solvent? For the solvent, the enthalpy of vaporization is \(33.90 \mathrm{~kJ} / \mathrm{mol}\), the entropy of vaporization is \(95.95\) \(\mathrm{J} / \mathrm{K} \cdot \mathrm{mol}\), and the boiling-point elevation constant is \(2.5 \mathrm{~K} \cdot \mathrm{kg} / \mathrm{mol}\).

Consider the following energy levels, each capable of holding two objects: \(E=2 \mathrm{~kJ}\) ______ \(E=1 \mathrm{~kJ}\) ______ \(E=0 \quad \mathrm{XX}\) Draw all the possible arrangements of the two identical particles (represented by X) in the three energy levels. What total energy is most likely, that is, occurs the greatest number of times? Assume that the particles are indistinguishable from each other.

What types of experiments can be carried out to determine whether a reaction is spontaneous? Does spontaneity have any relationship to the final equilibrium position of a reaction? Explain.

Which of the following processes are spontaneous? a. Salt dissolves in \(\mathrm{H}_{2} \mathrm{O}\). b. A clear solution becomes a uniform color after a few drops of dye are added. c. Iron rusts. d. You clean your bedroom.

See all solutions

Recommended explanations on Chemistry Textbooks

View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.

Sign-up for free