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Write equations for the stepwise formation of each of the following complex ions. a. \(\mathrm{CoF}_{6}^{3-}\) b. \(\mathrm{Zn}\left(\mathrm{NH}_{3}\right)_{4}^{2+}\)

Short Answer

Expert verified
The stepwise formation equations for the complex ion \(\mathrm{CoF}_{6}^{3-}\) are as follows: 1. Co³⁺ + F⁻ → CoF²⁺ 2. CoF²⁺ + F⁻ → CoF₂⁺ 3. CoF₂⁺ + F⁻ → CoF₃ 4. CoF₃ + F⁻ → CoF₄⁻ 5. CoF₄⁻ + F⁻ → CoF₅²⁻ 6. CoF₅²⁻ + F⁻ → CoF₆³⁻ The stepwise formation equations for the complex ion \(\mathrm{Zn}(\mathrm{NH}_{3})_{4}^{2+}\) are as follows: 1. Zn²⁺ + NH₃ → Zn(NH₃)²⁺ 2. Zn(NH₃)²⁺ + NH₃ → Zn(NH₃)₂²⁺ 3. Zn(NH₃)₂²⁺ + NH₃ → Zn(NH₃)₃²⁺ 4. Zn(NH₃)₃²⁺ + NH₃ → Zn(NH₃)₄²⁺

Step by step solution

01

Identify components of the complex ions

In order to write stepwise formation equations for the complex ions, we first need to identify the components involved in the formation of each ion. For complex ion a: \(\mathrm{CoF}_{6}^{3-}\) - Central metal ion: Co (Cobalt) - Ligand: F⁻ (Fluoride ion) - Charge: 3- For complex ion b: \(\mathrm{Zn}(\mathrm{NH}_{3})_{4}^{2+}\) - Central metal ion: Zn (Zinc) - Ligand: NH₃ (Ammonia) - Charge: 2+
02

Write the stepwise formation equations for \(\mathrm{CoF}_{6}^{3-}\)

Now we will write the stepwise formation equations for the cobalt fluoride complex ion \(\mathrm{CoF}_{6}^{3-}\): 1. Co³⁺ + F⁻ → CoF²⁺ 2. CoF²⁺ + F⁻ → CoF₂⁺ 3. CoF₂⁺ + F⁻ → CoF₃ 4. CoF₃ + F⁻ → CoF₄⁻ 5. CoF₄⁻ + F⁻ → CoF₅²⁻ 6. CoF₅²⁻ + F⁻ → CoF₆³⁻ The stepwise formation of \(\mathrm{CoF}_{6}^{3-}\) is completed.
03

Write the stepwise formation equations for \(\mathrm{Zn}(\mathrm{NH}_{3})_{4}^{2+}\)

Now we will write the stepwise formation equations for the zinc ammonia complex ion \(\mathrm{Zn}(\mathrm{NH}_{3})_{4}^{2+}\): 1. Zn²⁺ + NH₃ → Zn(NH₃)²⁺ 2. Zn(NH₃)²⁺ + NH₃ → Zn(NH₃)₂²⁺ 3. Zn(NH₃)₂²⁺ + NH₃ → Zn(NH₃)₃²⁺ 4. Zn(NH₃)₃²⁺ + NH₃ → Zn(NH₃)₄²⁺ The stepwise formation of \(\mathrm{Zn}(\mathrm{NH}_{3})_{4}^{2+}\) is completed.

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Most popular questions from this chapter

In the presence of \(\mathrm{CN}^{-}, \mathrm{Fe}^{3+}\) forms the complex ion \(\mathrm{Fe}(\mathrm{CN})_{6}^{3-}\). The equilibrium concentrations of \(\mathrm{Fe}^{3+}\) and \(\mathrm{Fe}(\mathrm{CN})_{6}^{3-}\) are \(8.5 \times 10^{-40} M\) and \(1.5 \times 10^{-3} M\), respectively, in a \(0.11 M \mathrm{KCN}\) solution. Calculate the value for the overall formation constant of \(\mathrm{Fe}(\mathrm{CN})_{6}^{3-}\) $$\mathrm{Fe}^{3+}(a q)+6 \mathrm{CN}^{-}(a q) \rightleftharpoons \mathrm{Fe}(\mathrm{CN})_{6}{ }^{3-} \quad K_{\text {overall }}=?$$

A mixture contains \(1.0 \times 10^{-3} \mathrm{M} \mathrm{Cu}^{2+}\) and \(1.0 \times 10^{-3} \mathrm{M} \mathrm{Mn}^{2+}\) and is saturated with \(0.10 M \mathrm{H}_{2} \mathrm{~S}\). Determine a \(\mathrm{pH}\) where CuS precipitates but MnS does not precipitate. \(K_{\text {op }}\) for \(\mathrm{CuS}=8.5 \times 10^{-45}\) and \(K_{\mathrm{s}}\) for \(\mathrm{MnS}=2.3 \times 10^{-1.3}\)

Use the following data to calculate the \(K_{\mathrm{sp}}\) value for each solid. a. The solubility of \(\mathrm{CaC}_{2} \mathrm{O}_{4}\) is \(4.8 \times 10^{-5} \mathrm{~mol} / \mathrm{L}\). b. The solubility of \(\mathrm{BiI}_{3}\) is \(1.32 \times 10^{-5} \mathrm{~mol} / \mathrm{L}\).

When aqueous KI is added gradually to mercury(II) nitrate, an orange precipitate forms. Continued addition of KI causes the precipitate to dissolve. Write balanced equations to explain these observations. (Hint: \(\mathrm{Hg}^{2+}\) reacts with \(\mathrm{I}^{-}\) to form \(\mathrm{HgI}_{4}{ }^{2-}\).)

The stepwise formation constants for a complex ion are all generally values much greater than 1 . What is the significance of this?

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