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Which of the following mixtures would result in a buffered solution when \(1.0 \mathrm{~L}\) of each of the two solutions are mixed? a. \(0.2 \mathrm{M} \mathrm{HNO}_{\mathrm{z}}\) and \(0.4 \mathrm{M} \mathrm{NaNO}_{3}\) b. \(0.2 \mathrm{M} \mathrm{HNO}_{3}\) and \(0.4 \mathrm{M} \mathrm{HF}\) c. \(0.2 \mathrm{M} \mathrm{HNO}_{3}\) and \(0.4 \mathrm{M} \mathrm{NaF}\) d. \(0.2 \mathrm{M} \mathrm{HNO}_{3}\) and \(0.4 \mathrm{M} \mathrm{NaOH}\)

Short Answer

Expert verified
The correct answer is option c: \(0.2 M HNO_3\) and \(0.4 M NaF\) produce a buffered solution. This mixture forms a weak acid/conjugate base pair, which will result in a buffered solution.

Step by step solution

01

Identify Weak Acids and Bases and Their Conjugates

First, it is crucial to recognize the weak acids and bases and their respective conjugate pairs. This will assist in determining if the pairs are suitable for creating a buffered solution. \(HNO_3\) is a strong acid, and \(NO_3^-\) is its conjugate base. \(HF\) is a weak acid, and \(F^-\) is its conjugate base. \(NaNO_3\) is the sodium salt of a strong acid, \(HNO_3\), and will produce \(Na^+\) and \(NO_3^-\) in water. \(NaF\) is the sodium salt of a weak acid, \(HF\), and will produce \(Na^+\) and \(F^-\) in water. \(NaOH\) is a strong base, and \(OH^-\) is its conjugate base.
02

Evaluate the Given Mixtures

Next, examine each of the provided mixtures to see if they can create a buffered solution by forming a weak acid and its conjugate base or a weak base and its conjugate acid. a. \(0.2 M HNO_3\) and \(0.4 M NaNO_3\): The mixture contains a strong acid and its conjugate base. Therefore, it cannot form a buffered solution. b. \(0.2 M HNO_3\) and \(0.4 M HF\): This mixture contains a strong acid and an unrelated weak acid. No weak acid/conjugate base pair is present in this mixture, so it cannot form a buffered solution. c. \(0.2 M HNO_3\) and \(0.4 M NaF\): In this mixture, the \(HNO_3\) is a strong acid, and the \(NaF\) dissociates into \(Na^+\) and its conjugate base \(F^-\). The \(F^-\) can react with the \(HNO_3\) to produce the weak acid, \(HF\), and its conjugate base \(NO_3^-\). Therefore, this mixture forms a weak acid/conjugate base pair and can result in a buffered solution. d. \(0.2 M HNO_3\) and \(0.4 M NaOH\): The mixture comprises a strong acid and a strong base, which will neutralize each other. This mixture cannot form a buffered solution.
03

Choose the Buffered Solution

Based on the analysis of the given mixtures: a. Not buffered (strong acid and its conjugate base) b. Not buffered (strong acid and unrelated weak acid) c. Buffered (forms a weak acid and its conjugate base pair) d. Not buffered (strong acid and strong base) The correct answer is option c: \(0.2 M HNO_3\) and \(0.4 M NaF\) produce a buffered solution.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Weak Acids and Bases
Understanding weak acids and bases is fundamental to grasping the concept of buffered solutions. Unlike their strong counterparts that fully dissociate in water, weak acids and bases only partially dissociate. This partial dissociation leads to an equilibrium between the non-dissociated molecules and the ions produced. An example of a weak acid is hydrofluoric acid (HF), which dissociates into its ions only to a limited extent in water.

It is important to note that the strength of an acid or a base is not about its pH level but about its ability to dissociate. Thus, a weak acid can actually have a low pH if it is highly concentrated, and similarly, a weak base can have a high pH if highly concentrated. In the context of the exercise, this understanding is crucial to identify which compounds can contribute to buffer formation.
Conjugate Acid-Base Pairs
A conjugate acid-base pair consists of molecules or ions that differ by the presence of one hydrogen ion (H+). When an acid donates a hydrogen ion, the remaining species is its conjugate base. Similarly, when a base accepts a hydrogen ion, it forms its conjugate acid. The concept of conjugate acid-base pairs is tied in with Brønsted-Lowry acid-base theory, which defines an acid as a proton donor and a base as a proton acceptor.

In our textbook example, hydrofluoric acid (HF) and its ion (F-) form a conjugate acid-base pair. When choosing components for a buffered solution, it's important to pair a weak acid with its conjugate base or a weak base with its conjugate acid. This pairing is essential because it provides resistance to pH changes when adding small amounts of acid or base to the solution, maintaining equilibrium.
Buffer Systems in Chemistry
A buffer system is a solution that resists changes in pH when small amounts of acid or base are added. It typically consists of a weak acid and its conjugate base or a weak base and its conjugate acid. This resistance is essential for maintaining stable pH levels in many biological and chemical systems.

Buffer systems work through the neutralization reaction that occurs when the acid or base is added to the solution. If an acid is added, it will be neutralized by the conjugate base present in the buffer. Conversely, if a base is added, the weak acid neutralizes it. This back-and-forth process occurs at the equilibrium point of the weak acid or base's dissociation in water.

For a buffer to effectively maintain pH, both components of the conjugate pair must be present in sufficient quantities. This is highlighted in the textbook exercise, where the buffered solution contained a weak acid and its conjugate base, allowing it to resist significant pH changes upon the addition of other substances.

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Most popular questions from this chapter

Sketch the titration curve for the titration of a generic weak base B with a strong acid. The titration reaction is $$ \mathrm{B}+\mathrm{H}^{+} \rightleftharpoons \mathrm{BH}^{+} $$ On this curve, indicate the points that correspond to the following: a. the stoichiometric (equivalence) point b. the region with maximum buffering c. \(\mathrm{pH}=\mathrm{p} K_{\mathrm{a}}\)

You have the following reagents on hand: \begin{tabular}{|ll|} \hline Solids \(\left(\mathrm{p} \boldsymbol{K}_{\mathrm{a}}\right.\) of Acid Form Is Given) & Solutions \\ \hline Benzoic acid (4.19) & \(5.0 \mathrm{M} \mathrm{HCl}\) \\ Sodium acetate (4.74) & \(1.0 \mathrm{M}\) acetic acid (4.74) \\ Potassium fluoride (3.14) & \(2.6 \mathrm{M} \mathrm{NaOH}\) \\ Ammonium chloride (9.26) & \(1.0 \mathrm{M} \mathrm{HOCl}(7.46)\) \\ \hline \end{tabular} What combinations of reagents would you use to prepare buffers at the following \(\mathrm{pH}\) values? a. \(3.0\) b. \(4.0\) c. \(5.0\) d. \(7.0\) e. \(9.0\)

What are the major species in solution after \(\mathrm{NaHSO}_{4}\) is dissolved in water? What happens to the \(\mathrm{pH}\) of the solution as more \(\mathrm{NaHSO}_{4}\) is added? Why? Would the results vary if baking soda \(\left(\mathrm{NaHCO}_{3}\right)\) were used instead?

You make \(1.00 \mathrm{~L}\) of a buffered solution \((\mathrm{pH}=4.00)\) by mixing acetic acid and sodium acetate. You have \(1.00 M\) solutions of each component of the buffered solution. What volume of each solution do you mix to make such a buffered solution?

A friend asks the following: "Consider a buffered solution made up of the weak acid HA and its salt NaA. If a strong base like \(\mathrm{NaOH}\) is added, the HA reacts with the \(\mathrm{OH}^{-}\) to form \(\mathrm{A}^{-}\). Thus the amount of acid (HA) is decreased, and the amount of base \(\left(\mathrm{A}^{-}\right)\) is increased. Analogously, adding \(\mathrm{HCl}\) to the buffered solution forms more of the acid (HA) by reacting with the base \(\left(\mathrm{A}^{-}\right) .\) Thus how can we claim that a buffered solution resists changes in the \(\mathrm{pH}\) of the solution?' How would you explain buffering to this friend?

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