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Explain the difference between \(K, K_{\mathrm{p}}\), and \(Q\).

Short Answer

Expert verified
In short, \(K\) and \(K_{p}\) are both equilibrium constants for chemical reactions, with \(K\) defined in terms of concentrations and \(K_{p}\) in terms of partial pressures for gas-phase reactions. They express the extent to which a reaction proceeds before reaching equilibrium. \(Q\) is the reaction quotient, calculated at any point during a reaction, and is used to predict the direction in which the reaction will proceed to reach equilibrium. Comparing \(Q\) with \(K\) or \(K_{p}\) provides insights on whether the reaction needs to proceed toward products or reactants to achieve equilibrium.

Step by step solution

01

Definition of K (Equilibrium Constant)

K, or the equilibrium constant, is a number that expresses how far a chemical reaction proceeds to the right (toward products) before reaching a state of equilibrium. It is the ratio of the concentrations of the products to the concentrations of the reactants, each raised to the power of their stoichiometric coefficients. Mathematically, for a general balanced equation: \[aA + bB \rightleftharpoons cC + dD\] The equilibrium constant K is defined as: \[K = \frac{[C]^c [D]^d}{[A]^a [B]^b}\] where [A], [B], [C], and [D] represent the equilibrium concentrations (in mol/L) of the respective species.
02

Definition of K_p (Equilibrium Constant in terms of Pressure)

For gaseous reactions, the equilibrium constant can also be expressed in terms of the partial pressures of the reactants and products involved in the reaction. The equilibrium constant K_p is defined as the equilibrium constant in terms of pressure for gas-phase reactions. Mathematically, for the same balanced equation: \[aA(g) + bB(g) \rightleftharpoons cC(g) + dD(g)\] K_p is defined as: \[K_{p} = \frac{(P_C)^c (P_D)^d}{(P_A)^a (P_B)^b}\] Here, P_A, P_B, P_C, and P_D represent the partial pressures of the respective gaseous species (in atm) at equilibrium. The relationship between K and K_p is given by the equation: \[K_p = K(RT)^{\Delta n}\] Here, R is the universal gas constant, T is the temperature in Kelvin, and Δn represents the change in the number of moles of gas for the reaction (Δn = c + d - a - b).
03

Definition of Q (Reaction Quotient)

The reaction quotient, denoted by Q, is a number that gives a snapshot of a reaction's progress at any given moment. Like K and K_p, it is calculated using either concentrations or partial pressures of the reactants and products. However, Q is not specific to equilibrium conditions. Q can be calculated at any point during the reaction and is used to predict the direction in which the reaction will proceed to reach equilibrium. Mathematically, for the example reaction: \[aA + bB \rightleftharpoons cC + dD\] Q is defined as: \[Q = \frac{[C]^c [D]^d}{[A]^a [B]^b}\] For any given moment during the reaction, comparing Q with K or K_p will provide insights on the direction of the reaction: - If Q < K (or K_p), it means that the reaction will proceed to the right (toward products) to achieve equilibrium. - If Q > K (or K_p), the reaction will proceed to the left (toward reactants) to achieve equilibrium. - If Q = K (or K_p), it indicates that the reaction is already at equilibrium. In summary, K and K_p are both equilibrium constants, with K defined in terms of concentrations and K_p defined in terms of partial pressures for gas-phase reactions. On the other hand, Q is the reaction quotient calculated at any point during a reaction to predict the direction of the reaction to reach equilibrium.

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Most popular questions from this chapter

For the following reaction at a certain temperature $$ \mathrm{H}_{2}(g)+\mathrm{F}_{2}(g) \rightleftharpoons 2 \mathrm{HF}(g) $$ it is found that the equilibrium concentrations in a 5.00-L rigid container are \(\left[\mathrm{H}_{2}\right]=0.0500 M,\left[\mathrm{~F}_{2}\right]=0.0100 M\), and \([\mathrm{HF}]=\) \(0.400 \mathrm{M}\). If \(0.200 \mathrm{~mol} \mathrm{~F}_{2}\) is added to this equilibrium mixture, calculate the concentrations of all gases once equilibrium is reestablished.

At a particular temperature, \(K=2.0 \times 10^{-6}\) for the reaction $$ 2 \mathrm{CO}_{2}(g) \rightleftharpoons 2 \mathrm{CO}(g)+\mathrm{O}_{2}(g) $$ If \(2.0 \mathrm{~mol} \mathrm{CO}_{2}\) is initially placed into a 5.0-L vessel, calculate the equilibrium concentrations of all species.

The synthesis of ammonia gas from nitrogen gas and hydrogen gas represents a classic case in which a knowledge of kinetics and equilibrium was used to make a desired chemical reaction economically feasible. Explain how each of the following conditions helps to maximize the yield of ammonia. a. running the reaction at an elevated temperature b. removing the ammonia from the reaction mixture as it forms c. using a catalyst d. running the reaction at high pressure

The formation of peptide bonds is an important area of chemistry. The following reaction has an equilibrium constant \((K)\) of \(3.2 \times 10^{2}\) at some temperature: Alanine \((a q)+\) leucine \((a q) \rightleftharpoons\) alanine-leucine dipeptide \((a q)+\mathrm{H}_{2} \mathrm{O}(l)\) Which direction will this reaction need to shift to reach equilibrium under the following conditions? a. \([\) alanine \(]=0.60 M,[\) leucine \(]=0.40 M,[\) dipeptide \(]=0.20 M\) b. \([\) alanine \(]=3.5 \times 10^{-4} M,[\) leucine \(]=3.6 M,[\) dipeptide \(]=\) \(0.40 M\) c. \([\) alanine \(]=6.0 \times 10^{-3} M,[\) leucine \(]=9.0 \times 10^{-3} M\), \([\) dipeptide \(]=0.30 M\)

The following equilibrium pressures were observed at a certain temperature for the reaction $$ \begin{array}{c} \mathrm{N}_{2}(g)+3 \mathrm{H}_{2}(g) \rightleftharpoons 2 \mathrm{NH}_{3}(g) \\\ P_{\mathrm{NH}_{3}}=3.1 \times 10^{-2} \mathrm{~atm} \\ P_{\mathrm{N}_{2}}=8.5 \times 10^{-1} \mathrm{~atm} \\ P_{\mathrm{H}_{2}}=3.1 \times 10^{-3} \mathrm{~atm} \end{array} $$ Calculate the value for the equilibrium constant \(K_{\mathrm{p}}\) at this temperature. If \(P_{\mathrm{N}_{2}}=0.525 \mathrm{~atm}, P_{\mathrm{NH}_{3}}=0.0167 \mathrm{~atm}\), and \(P_{\mathrm{H}_{2}}=0.00761\) atm, does this represent a system at equilibrium?

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